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Trigonometry Examples
tan(4x)tan(4x)
Step 1
Factor 22 out of 4x4x.
tan(2(2x))tan(2(2x))
Step 2
Step 2.1
Apply the tangent double-angle identity.
22tan(x)1-tan2(x)1-tan2(2x)22tan(x)1−tan2(x)1−tan2(2x)
Step 2.2
Simplify the denominator.
Step 2.2.1
Rewrite 11 as 1212.
22tan(x)12-tan2(x)1-tan2(2x)22tan(x)12−tan2(x)1−tan2(2x)
Step 2.2.2
Since both terms are perfect squares, factor using the difference of squares formula, a2-b2=(a+b)(a-b)a2−b2=(a+b)(a−b) where a=1a=1 and b=tan(x)b=tan(x).
22tan(x)(1+tan(x))(1-tan(x))1-tan2(2x)22tan(x)(1+tan(x))(1−tan(x))1−tan2(2x)
22tan(x)(1+tan(x))(1-tan(x))1-tan2(2x)22tan(x)(1+tan(x))(1−tan(x))1−tan2(2x)
22tan(x)(1+tan(x))(1-tan(x))1-tan2(2x)22tan(x)(1+tan(x))(1−tan(x))1−tan2(2x)
Step 3
Step 3.1
Rewrite 11 as 1212.
22tan(x)(1+tan(x))(1-tan(x))12-tan2(2x)22tan(x)(1+tan(x))(1−tan(x))12−tan2(2x)
Step 3.2
Since both terms are perfect squares, factor using the difference of squares formula, a2-b2=(a+b)(a-b)a2−b2=(a+b)(a−b) where a=1a=1 and b=tan(2x)b=tan(2x).
22tan(x)(1+tan(x))(1-tan(x))(1+tan(2x))(1-tan(2x))22tan(x)(1+tan(x))(1−tan(x))(1+tan(2x))(1−tan(2x))
Step 3.3
Simplify.
Step 3.3.1
Apply the tangent double-angle identity.
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)1-tan2(x))(1-tan(2x))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)1−tan2(x))(1−tan(2x))
Step 3.3.2
Simplify the denominator.
Step 3.3.2.1
Rewrite 11 as 1212.
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)12-tan2(x))(1-tan(2x))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)12−tan2(x))(1−tan(2x))
Step 3.3.2.2
Since both terms are perfect squares, factor using the difference of squares formula, a2-b2=(a+b)(a-b)a2−b2=(a+b)(a−b) where a=1a=1 and b=tan(x)b=tan(x).
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-tan(2x))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−tan(2x))
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-tan(2x))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−tan(2x))
Step 3.3.3
Apply the tangent double-angle identity.
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)1-tan2(x))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)1−tan2(x))
Step 3.3.4
Simplify the denominator.
Step 3.3.4.1
Rewrite 11 as 1212.
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)12-tan2(x))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)12−tan2(x))
Step 3.3.4.2
Since both terms are perfect squares, factor using the difference of squares formula, a2-b2=(a+b)(a-b)a2−b2=(a+b)(a−b) where a=1a=1 and b=tan(x)b=tan(x).
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x)))
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x)))
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x)))
22tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))22tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x)))
Step 4
Combine 22 and 2tan(x)(1+tan(x))(1-tan(x))2tan(x)(1+tan(x))(1−tan(x)).
2(2tan(x))(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))2(2tan(x))(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x)))
Step 5
Multiply 22 by 22.
4tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))4tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x)))
Step 6
Multiply the numerator by the reciprocal of the denominator.
4tan(x)(1+tan(x))(1-tan(x))⋅1(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))4tan(x)(1+tan(x))(1−tan(x))⋅1(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x)))
Step 7
Multiply 4tan(x)(1+tan(x))(1-tan(x))4tan(x)(1+tan(x))(1−tan(x)) by 1(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))1(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x))).
4tan(x)(1+tan(x))(1-tan(x))(1+2tan(x)(1+tan(x))(1-tan(x)))(1-2tan(x)(1+tan(x))(1-tan(x)))4tan(x)(1+tan(x))(1−tan(x))(1+2tan(x)(1+tan(x))(1−tan(x)))(1−2tan(x)(1+tan(x))(1−tan(x)))