Trigonometry Examples

$\frac{\sin (x) \cos (x)}{1 - (\sin (x) - \cos (x)) (\sin (x) - \cos (x))}$

Step 1

Rewrite $1$ as $1^{2}$ .

$\frac{\sin (x) \cos (x)}{1^{2} - (\sin (x) - \cos (x)) (\sin (x) - \cos (x))}$

Step 2

Rewrite $(\sin (x) - \cos (x)) (\sin (x) - \cos (x))$ as ${(\sin (x) - \cos (x))}^{2}$ .

$\frac{\sin (x) \cos (x)}{1^{2} - {(\sin (x) - \cos (x))}^{2}}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 1$ and $b = \sin (x) - \cos (x)$ .

$\frac{\sin (x) \cos (x)}{(1 + \sin (x) - \cos (x)) (1 - (\sin (x) - \cos (x)))}$

Step 4

Simplify.

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Step 4.1

Apply the distributive property.

$\frac{\sin (x) \cos (x)}{(1 + \sin (x) - \cos (x)) (1 - \sin (x) - - \cos (x))}$

Step 4.2

Multiply $- - \cos (x)$ .

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Step 4.2.1

Multiply $- 1$ by $- 1$ .

$\frac{\sin (x) \cos (x)}{(1 + \sin (x) - \cos (x)) (1 - \sin (x) + 1 \cos (x))}$

Step 4.2.2

Multiply $\cos (x)$ by $1$ .

$\frac{\sin (x) \cos (x)}{(1 + \sin (x) - \cos (x)) (1 - \sin (x) + \cos (x))}$