Trigonometry Examples

Graph y=-3/2*cos(3/2x)
y=-32cos(32x)y=32cos(32x)
Step 1
Use the form acos(bx-c)+d to find the variables used to find the amplitude, period, phase shift, and vertical shift.
a=-32
b=32
c=0
d=0
Step 2
Find the amplitude |a|.
Amplitude: 32
Step 3
Find the period of -3cos(3x2)2.
Tap for more steps...
Step 3.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 3.2
Replace b with 32 in the formula for period.
2π|32|
Step 3.3
32 is approximately 1.5 which is positive so remove the absolute value
2π32
Step 3.4
Multiply the numerator by the reciprocal of the denominator.
2π23
Step 3.5
Multiply 2π23.
Tap for more steps...
Step 3.5.1
Combine 23 and 2.
223π
Step 3.5.2
Multiply 2 by 2.
43π
Step 3.5.3
Combine 43 and π.
4π3
4π3
4π3
Step 4
Find the phase shift using the formula cb.
Tap for more steps...
Step 4.1
The phase shift of the function can be calculated from cb.
Phase Shift: cb
Step 4.2
Replace the values of c and b in the equation for phase shift.
Phase Shift: 032
Step 4.3
Multiply the numerator by the reciprocal of the denominator.
Phase Shift: 0(23)
Step 4.4
Multiply 0 by 23.
Phase Shift: 0
Phase Shift: 0
Step 5
List the properties of the trigonometric function.
Amplitude: 32
Period: 4π3
Phase Shift: None
Vertical Shift: None
Step 6
Select a few points to graph.
Tap for more steps...
Step 6.1
Find the point at x=0.
Tap for more steps...
Step 6.1.1
Replace the variable x with 0 in the expression.
f(0)=-3cos(3(0)2)2
Step 6.1.2
Simplify the result.
Tap for more steps...
Step 6.1.2.1
Cancel the common factor of 0 and 2.
Tap for more steps...
Step 6.1.2.1.1
Factor 2 out of 3(0).
f(0)=-3cos(2(3(0))2)2
Step 6.1.2.1.2
Cancel the common factors.
Tap for more steps...
Step 6.1.2.1.2.1
Factor 2 out of 2.
f(0)=-3cos(2(3(0))2(1))2
Step 6.1.2.1.2.2
Cancel the common factor.
f(0)=-3cos(2(3(0))21)2
Step 6.1.2.1.2.3
Rewrite the expression.
f(0)=-3cos(3(0)1)2
Step 6.1.2.1.2.4
Divide 3(0) by 1.
f(0)=-3cos(3(0))2
f(0)=-3cos(3(0))2
f(0)=-3cos(3(0))2
Step 6.1.2.2
Simplify the numerator.
Tap for more steps...
Step 6.1.2.2.1
Multiply 3 by 0.
f(0)=-3cos(0)2
Step 6.1.2.2.2
The exact value of cos(0) is 1.
f(0)=-312
f(0)=-312
Step 6.1.2.3
Multiply 3 by 1.
f(0)=-32
Step 6.1.2.4
The final answer is -32.
-32
-32
-32
Step 6.2
Find the point at x=π3.
Tap for more steps...
Step 6.2.1
Replace the variable x with π3 in the expression.
f(π3)=-3cos(3(π3)2)2
Step 6.2.2
Simplify the result.
Tap for more steps...
Step 6.2.2.1
Combine 3 and π3.
f(π3)=-3cos(3π32)2
Step 6.2.2.2
Reduce the expression by cancelling the common factors.
Tap for more steps...
Step 6.2.2.2.1
Reduce the expression 3π3 by cancelling the common factors.
Tap for more steps...
Step 6.2.2.2.1.1
Cancel the common factor.
f(π3)=-3cos(3π32)2
Step 6.2.2.2.1.2
Rewrite the expression.
f(π3)=-3cos(π12)2
f(π3)=-3cos(π12)2
Step 6.2.2.2.2
Divide π by 1.
f(π3)=-3cos(π2)2
f(π3)=-3cos(π2)2
Step 6.2.2.3
The exact value of cos(π2) is 0.
f(π3)=-302
Step 6.2.2.4
Multiply 3 by 0.
f(π3)=-02
Step 6.2.2.5
Divide 0 by 2.
f(π3)=-0
Step 6.2.2.6
Multiply -1 by 0.
f(π3)=0
Step 6.2.2.7
The final answer is 0.
0
0
0
Step 6.3
Find the point at x=2π3.
Tap for more steps...
Step 6.3.1
Replace the variable x with 2π3 in the expression.
f(2π3)=-3cos(3(2π3)2)2
Step 6.3.2
Simplify the result.
Tap for more steps...
Step 6.3.2.1
Combine 3 and 2π3.
f(2π3)=-3cos(3(2π)32)2
Step 6.3.2.2
Multiply 3 by 2.
f(2π3)=-3cos(6π32)2
Step 6.3.2.3
Reduce the expression by cancelling the common factors.
Tap for more steps...
Step 6.3.2.3.1
Reduce the expression 6π3 by cancelling the common factors.
Tap for more steps...
Step 6.3.2.3.1.1
Factor 3 out of 6π.
f(2π3)=-3cos(3(2π)32)2
Step 6.3.2.3.1.2
Factor 3 out of 3.
f(2π3)=-3cos(3(2π)3(1)2)2
Step 6.3.2.3.1.3
Cancel the common factor.
f(2π3)=-3cos(3(2π)312)2
Step 6.3.2.3.1.4
Rewrite the expression.
f(2π3)=-3cos(2π12)2
f(2π3)=-3cos(2π12)2
Step 6.3.2.3.2
Divide 2π by 1.
f(2π3)=-3cos(2π2)2
f(2π3)=-3cos(2π2)2
Step 6.3.2.4
Simplify the numerator.
Tap for more steps...
Step 6.3.2.4.1
Cancel the common factor of 2.
Tap for more steps...
Step 6.3.2.4.1.1
Cancel the common factor.
f(2π3)=-3cos(2π2)2
Step 6.3.2.4.1.2
Divide π by 1.
f(2π3)=-3cos(π)2
f(2π3)=-3cos(π)2
Step 6.3.2.4.2
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.
f(2π3)=-3(-cos(0))2
Step 6.3.2.4.3
The exact value of cos(0) is 1.
f(2π3)=-3(-11)2
Step 6.3.2.4.4
Multiply -1 by 1.
f(2π3)=-3-12
f(2π3)=-3-12
Step 6.3.2.5
Simplify the expression.
Tap for more steps...
Step 6.3.2.5.1
Multiply 3 by -1.
f(2π3)=--32
Step 6.3.2.5.2
Move the negative in front of the fraction.
f(2π3)=32
f(2π3)=32
Step 6.3.2.6
The final answer is 32.
32
32
32
Step 6.4
Find the point at x=π.
Tap for more steps...
Step 6.4.1
Replace the variable x with π in the expression.
f(π)=-3cos(3(π)2)2
Step 6.4.2
Simplify the result.
Tap for more steps...
Step 6.4.2.1
Simplify the numerator.
Tap for more steps...
Step 6.4.2.1.1
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.
f(π)=-3cos(π2)2
Step 6.4.2.1.2
The exact value of cos(π2) is 0.
f(π)=-302
f(π)=-302
Step 6.4.2.2
Simplify the expression.
Tap for more steps...
Step 6.4.2.2.1
Multiply 3 by 0.
f(π)=-02
Step 6.4.2.2.2
Divide 0 by 2.
f(π)=-0
Step 6.4.2.2.3
Multiply -1 by 0.
f(π)=0
f(π)=0
Step 6.4.2.3
The final answer is 0.
0
0
0
Step 6.5
Find the point at x=4π3.
Tap for more steps...
Step 6.5.1
Replace the variable x with 4π3 in the expression.
f(4π3)=-3cos(3(4π3)2)2
Step 6.5.2
Simplify the result.
Tap for more steps...
Step 6.5.2.1
Combine 3 and 4π3.
f(4π3)=-3cos(3(4π)32)2
Step 6.5.2.2
Multiply 3 by 4.
f(4π3)=-3cos(12π32)2
Step 6.5.2.3
Reduce the expression by cancelling the common factors.
Tap for more steps...
Step 6.5.2.3.1
Reduce the expression 12π3 by cancelling the common factors.
Tap for more steps...
Step 6.5.2.3.1.1
Factor 3 out of 12π.
f(4π3)=-3cos(3(4π)32)2
Step 6.5.2.3.1.2
Factor 3 out of 3.
f(4π3)=-3cos(3(4π)3(1)2)2
Step 6.5.2.3.1.3
Cancel the common factor.
f(4π3)=-3cos(3(4π)312)2
Step 6.5.2.3.1.4
Rewrite the expression.
f(4π3)=-3cos(4π12)2
f(4π3)=-3cos(4π12)2
Step 6.5.2.3.2
Divide 4π by 1.
f(4π3)=-3cos(4π2)2
f(4π3)=-3cos(4π2)2
Step 6.5.2.4
Simplify the numerator.
Tap for more steps...
Step 6.5.2.4.1
Cancel the common factor of 4 and 2.
Tap for more steps...
Step 6.5.2.4.1.1
Factor 2 out of 4π.
f(4π3)=-3cos(2(2π)2)2
Step 6.5.2.4.1.2
Cancel the common factors.
Tap for more steps...
Step 6.5.2.4.1.2.1
Factor 2 out of 2.
f(4π3)=-3cos(2(2π)2(1))2
Step 6.5.2.4.1.2.2
Cancel the common factor.
f(4π3)=-3cos(2(2π)21)2
Step 6.5.2.4.1.2.3
Rewrite the expression.
f(4π3)=-3cos(2π1)2
Step 6.5.2.4.1.2.4
Divide 2π by 1.
f(4π3)=-3cos(2π)2
f(4π3)=-3cos(2π)2
f(4π3)=-3cos(2π)2
Step 6.5.2.4.2
Subtract full rotations of 2π until the angle is greater than or equal to 0 and less than 2π.
f(4π3)=-3cos(0)2
Step 6.5.2.4.3
The exact value of cos(0) is 1.
f(4π3)=-312
f(4π3)=-312
Step 6.5.2.5
Multiply 3 by 1.
f(4π3)=-32
Step 6.5.2.6
The final answer is -32.
-32
-32
-32
Step 6.6
List the points in a table.
xf(x)0-32π302π332π04π3-32
xf(x)0-32π302π332π04π3-32
Step 7
The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.
Amplitude: 32
Period: 4π3
Phase Shift: None
Vertical Shift: None
xf(x)0-32π302π332π04π3-32
Step 8
 [x2  12  π  xdx ]