Trigonometry Examples

Solve for t sin(3t)=1/2
sin(3t)=12sin(3t)=12
Step 1
Take the inverse sine of both sides of the equation to extract tt from inside the sine.
3t=arcsin(12)
Step 2
Simplify the right side.
Tap for more steps...
Step 2.1
The exact value of arcsin(12) is π6.
3t=π6
3t=π6
Step 3
Divide each term in 3t=π6 by 3 and simplify.
Tap for more steps...
Step 3.1
Divide each term in 3t=π6 by 3.
3t3=π63
Step 3.2
Simplify the left side.
Tap for more steps...
Step 3.2.1
Cancel the common factor of 3.
Tap for more steps...
Step 3.2.1.1
Cancel the common factor.
3t3=π63
Step 3.2.1.2
Divide t by 1.
t=π63
t=π63
t=π63
Step 3.3
Simplify the right side.
Tap for more steps...
Step 3.3.1
Multiply the numerator by the reciprocal of the denominator.
t=π613
Step 3.3.2
Multiply π613.
Tap for more steps...
Step 3.3.2.1
Multiply π6 by 13.
t=π63
Step 3.3.2.2
Multiply 6 by 3.
t=π18
t=π18
t=π18
t=π18
Step 4
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from π to find the solution in the second quadrant.
3t=π-π6
Step 5
Solve for t.
Tap for more steps...
Step 5.1
Simplify.
Tap for more steps...
Step 5.1.1
To write π as a fraction with a common denominator, multiply by 66.
3t=π66-π6
Step 5.1.2
Combine π and 66.
3t=π66-π6
Step 5.1.3
Combine the numerators over the common denominator.
3t=π6-π6
Step 5.1.4
Subtract π from π6.
Tap for more steps...
Step 5.1.4.1
Reorder π and 6.
3t=6π-π6
Step 5.1.4.2
Subtract π from 6π.
3t=5π6
3t=5π6
3t=5π6
Step 5.2
Divide each term in 3t=5π6 by 3 and simplify.
Tap for more steps...
Step 5.2.1
Divide each term in 3t=5π6 by 3.
3t3=5π63
Step 5.2.2
Simplify the left side.
Tap for more steps...
Step 5.2.2.1
Cancel the common factor of 3.
Tap for more steps...
Step 5.2.2.1.1
Cancel the common factor.
3t3=5π63
Step 5.2.2.1.2
Divide t by 1.
t=5π63
t=5π63
t=5π63
Step 5.2.3
Simplify the right side.
Tap for more steps...
Step 5.2.3.1
Multiply the numerator by the reciprocal of the denominator.
t=5π613
Step 5.2.3.2
Multiply 5π613.
Tap for more steps...
Step 5.2.3.2.1
Multiply 5π6 by 13.
t=5π63
Step 5.2.3.2.2
Multiply 6 by 3.
t=5π18
t=5π18
t=5π18
t=5π18
t=5π18
Step 6
Find the period of sin(3t).
Tap for more steps...
Step 6.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 6.2
Replace b with 3 in the formula for period.
2π|3|
Step 6.3
The absolute value is the distance between a number and zero. The distance between 0 and 3 is 3.
2π3
2π3
Step 7
The period of the sin(3t) function is 2π3 so values will repeat every 2π3 radians in both directions.
t=π18+2πn3,5π18+2πn3, for any integer n
(
(
)
)
|
|
[
[
]
]
°
°
7
7
8
8
9
9
θ
θ
4
4
5
5
6
6
/
/
^
^
×
×
>
>
π
π
1
1
2
2
3
3
-
-
+
+
÷
÷
<
<
,
,
0
0
.
.
%
%
=
=
 [x2  12  π  xdx ]