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Trigonometry Examples
sin(3t)=12sin(3t)=12
Step 1
Take the inverse sine of both sides of the equation to extract tt from inside the sine.
3t=arcsin(12)
Step 2
Step 2.1
The exact value of arcsin(12) is π6.
3t=π6
3t=π6
Step 3
Step 3.1
Divide each term in 3t=π6 by 3.
3t3=π63
Step 3.2
Simplify the left side.
Step 3.2.1
Cancel the common factor of 3.
Step 3.2.1.1
Cancel the common factor.
3t3=π63
Step 3.2.1.2
Divide t by 1.
t=π63
t=π63
t=π63
Step 3.3
Simplify the right side.
Step 3.3.1
Multiply the numerator by the reciprocal of the denominator.
t=π6⋅13
Step 3.3.2
Multiply π6⋅13.
Step 3.3.2.1
Multiply π6 by 13.
t=π6⋅3
Step 3.3.2.2
Multiply 6 by 3.
t=π18
t=π18
t=π18
t=π18
Step 4
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from π to find the solution in the second quadrant.
3t=π-π6
Step 5
Step 5.1
Simplify.
Step 5.1.1
To write π as a fraction with a common denominator, multiply by 66.
3t=π⋅66-π6
Step 5.1.2
Combine π and 66.
3t=π⋅66-π6
Step 5.1.3
Combine the numerators over the common denominator.
3t=π⋅6-π6
Step 5.1.4
Subtract π from π⋅6.
Step 5.1.4.1
Reorder π and 6.
3t=6⋅π-π6
Step 5.1.4.2
Subtract π from 6⋅π.
3t=5⋅π6
3t=5⋅π6
3t=5⋅π6
Step 5.2
Divide each term in 3t=5⋅π6 by 3 and simplify.
Step 5.2.1
Divide each term in 3t=5⋅π6 by 3.
3t3=5⋅π63
Step 5.2.2
Simplify the left side.
Step 5.2.2.1
Cancel the common factor of 3.
Step 5.2.2.1.1
Cancel the common factor.
3t3=5⋅π63
Step 5.2.2.1.2
Divide t by 1.
t=5⋅π63
t=5⋅π63
t=5⋅π63
Step 5.2.3
Simplify the right side.
Step 5.2.3.1
Multiply the numerator by the reciprocal of the denominator.
t=5⋅π6⋅13
Step 5.2.3.2
Multiply 5π6⋅13.
Step 5.2.3.2.1
Multiply 5π6 by 13.
t=5π6⋅3
Step 5.2.3.2.2
Multiply 6 by 3.
t=5π18
t=5π18
t=5π18
t=5π18
t=5π18
Step 6
Step 6.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 6.2
Replace b with 3 in the formula for period.
2π|3|
Step 6.3
The absolute value is the distance between a number and zero. The distance between 0 and 3 is 3.
2π3
2π3
Step 7
The period of the sin(3t) function is 2π3 so values will repeat every 2π3 radians in both directions.
t=π18+2πn3,5π18+2πn3, for any integer n