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Trigonometry Examples
cos3(x)-cos(x)=0
Step 1
Step 1.1
Factor cos(x) out of cos3(x)-cos(x).
Step 1.1.1
Factor cos(x) out of cos3(x).
cos(x)cos2(x)-cos(x)=0
Step 1.1.2
Factor cos(x) out of -cos(x).
cos(x)cos2(x)+cos(x)⋅-1=0
Step 1.1.3
Factor cos(x) out of cos(x)cos2(x)+cos(x)⋅-1.
cos(x)(cos2(x)-1)=0
cos(x)(cos2(x)-1)=0
Step 1.2
Rewrite 1 as 12.
cos(x)(cos2(x)-12)=0
Step 1.3
Factor.
Step 1.3.1
Since both terms are perfect squares, factor using the difference of squares formula, a2-b2=(a+b)(a-b) where a=cos(x) and b=1.
cos(x)((cos(x)+1)(cos(x)-1))=0
Step 1.3.2
Remove unnecessary parentheses.
cos(x)(cos(x)+1)(cos(x)-1)=0
cos(x)(cos(x)+1)(cos(x)-1)=0
cos(x)(cos(x)+1)(cos(x)-1)=0
Step 2
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
cos(x)=0
cos(x)+1=0
cos(x)-1=0
Step 3
Step 3.1
Set cos(x) equal to 0.
cos(x)=0
Step 3.2
Solve cos(x)=0 for x.
Step 3.2.1
Take the inverse cosine of both sides of the equation to extract x from inside the cosine.
x=arccos(0)
Step 3.2.2
Simplify the right side.
Step 3.2.2.1
The exact value of arccos(0) is π2.
x=π2
x=π2
Step 3.2.3
The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from 2π to find the solution in the fourth quadrant.
x=2π-π2
Step 3.2.4
Simplify 2π-π2.
Step 3.2.4.1
To write 2π as a fraction with a common denominator, multiply by 22.
x=2π⋅22-π2
Step 3.2.4.2
Combine fractions.
Step 3.2.4.2.1
Combine 2π and 22.
x=2π⋅22-π2
Step 3.2.4.2.2
Combine the numerators over the common denominator.
x=2π⋅2-π2
x=2π⋅2-π2
Step 3.2.4.3
Simplify the numerator.
Step 3.2.4.3.1
Multiply 2 by 2.
x=4π-π2
Step 3.2.4.3.2
Subtract π from 4π.
x=3π2
x=3π2
x=3π2
Step 3.2.5
Find the period of cos(x).
Step 3.2.5.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 3.2.5.2
Replace b with 1 in the formula for period.
2π|1|
Step 3.2.5.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
2π1
Step 3.2.5.4
Divide 2π by 1.
2π
2π
Step 3.2.6
The period of the cos(x) function is 2π so values will repeat every 2π radians in both directions.
x=π2+2πn,3π2+2πn, for any integer n
x=π2+2πn,3π2+2πn, for any integer n
x=π2+2πn,3π2+2πn, for any integer n
Step 4
Step 4.1
Set cos(x)+1 equal to 0.
cos(x)+1=0
Step 4.2
Solve cos(x)+1=0 for x.
Step 4.2.1
Subtract 1 from both sides of the equation.
cos(x)=-1
Step 4.2.2
Take the inverse cosine of both sides of the equation to extract x from inside the cosine.
x=arccos(-1)
Step 4.2.3
Simplify the right side.
Step 4.2.3.1
The exact value of arccos(-1) is π.
x=π
x=π
Step 4.2.4
The cosine function is negative in the second and third quadrants. To find the second solution, subtract the reference angle from 2π to find the solution in the third quadrant.
x=2π-π
Step 4.2.5
Subtract π from 2π.
x=π
Step 4.2.6
Find the period of cos(x).
Step 4.2.6.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 4.2.6.2
Replace b with 1 in the formula for period.
2π|1|
Step 4.2.6.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
2π1
Step 4.2.6.4
Divide 2π by 1.
2π
2π
Step 4.2.7
The period of the cos(x) function is 2π so values will repeat every 2π radians in both directions.
x=π+2πn, for any integer n
x=π+2πn, for any integer n
x=π+2πn, for any integer n
Step 5
Step 5.1
Set cos(x)-1 equal to 0.
cos(x)-1=0
Step 5.2
Solve cos(x)-1=0 for x.
Step 5.2.1
Add 1 to both sides of the equation.
cos(x)=1
Step 5.2.2
Take the inverse cosine of both sides of the equation to extract x from inside the cosine.
x=arccos(1)
Step 5.2.3
Simplify the right side.
Step 5.2.3.1
The exact value of arccos(1) is 0.
x=0
x=0
Step 5.2.4
The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from 2π to find the solution in the fourth quadrant.
x=2π-0
Step 5.2.5
Subtract 0 from 2π.
x=2π
Step 5.2.6
Find the period of cos(x).
Step 5.2.6.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 5.2.6.2
Replace b with 1 in the formula for period.
2π|1|
Step 5.2.6.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
2π1
Step 5.2.6.4
Divide 2π by 1.
2π
2π
Step 5.2.7
The period of the cos(x) function is 2π so values will repeat every 2π radians in both directions.
x=2πn,2π+2πn, for any integer n
x=2πn,2π+2πn, for any integer n
x=2πn,2π+2πn, for any integer n
Step 6
The final solution is all the values that make cos(x)(cos(x)+1)(cos(x)-1)=0 true.
x=π2+2πn,3π2+2πn,π+2πn,2πn,2π+2πn, for any integer n
Step 7
Consolidate the answers.
x=πn2, for any integer n