Trigonometry Examples

$3 \cos^{2} (x) - \sin^{2} (x) = 0$

Step 1

Replace the $3 \cos^{2} (x)$ with $3 (1 - \sin^{2} (x))$ based on the $\sin^{2} (x) + \cos^{2} (x) = 1$ identity.

$3 (1 - \sin^{2} (x)) - \sin^{2} (x) = 0$

Step 2

Simplify each term.

Tap for more steps...

Step 2.1

Apply the distributive property.

$3 \cdot 1 + 3 (- \sin^{2} (x)) - \sin^{2} (x) = 0$

Step 2.2

Multiply $3$ by $1$ .

$3 + 3 (- \sin^{2} (x)) - \sin^{2} (x) = 0$

Step 2.3

Multiply $- 1$ by $3$ .

$3 - 3 \sin^{2} (x) - \sin^{2} (x) = 0$

Step 3

Subtract $\sin^{2} (x)$ from $- 3 \sin^{2} (x)$ .

$3 - 4 \sin^{2} (x) = 0$

Step 4

Reorder the polynomial.

$- 4 \sin^{2} (x) + 3 = 0$

Step 5

Subtract $3$ from both sides of the equation.

$- 4 \sin^{2} (x) = - 3$

Step 6

Divide each term in $- 4 \sin^{2} (x) = - 3$ by $- 4$ and simplify.

Tap for more steps...

Step 6.1

Divide each term in $- 4 \sin^{2} (x) = - 3$ by $- 4$ .

$\frac{- 4 \sin^{2} (x)}{- 4} = \frac{- 3}{- 4}$

Step 6.2

Simplify the left side.

Tap for more steps...

Step 6.2.1

Cancel the common factor of $- 4$ .

Tap for more steps...

Step 6.2.1.1

Cancel the common factor.

$\frac{- 4 \sin^{2} (x)}{- 4} = \frac{- 3}{- 4}$

Step 6.2.1.2

Divide $\sin^{2} (x)$ by $1$ .

$\sin^{2} (x) = \frac{- 3}{- 4}$

Step 6.3

Simplify the right side.

Tap for more steps...

Step 6.3.1

Dividing two negative values results in a positive value.

$\sin^{2} (x) = \frac{3}{4}$

Step 7

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$\sin (x) = \pm \sqrt{\frac{3}{4}}$

Step 8

Simplify $\pm \sqrt{\frac{3}{4}}$ .

Tap for more steps...

Step 8.1

Rewrite $\sqrt{\frac{3}{4}}$ as $\frac{\sqrt{3}}{\sqrt{4}}$ .

$\sin (x) = \pm \frac{\sqrt{3}}{\sqrt{4}}$

Step 8.2

Simplify the denominator.

Tap for more steps...

Step 8.2.1

Rewrite $4$ as $2^{2}$ .

$\sin (x) = \pm \frac{\sqrt{3}}{\sqrt{2^{2}}}$

Step 8.2.2

Pull terms out from under the radical, assuming positive real numbers.

$\sin (x) = \pm \frac{\sqrt{3}}{2}$

Step 9

The complete solution is the result of both the positive and negative portions of the solution.

Tap for more steps...

Step 9.1

First, use the positive value of the $\pm$ to find the first solution.

$\sin (x) = \frac{\sqrt{3}}{2}$

Step 9.2

Next, use the negative value of the $\pm$ to find the second solution.

$\sin (x) = - \frac{\sqrt{3}}{2}$

Step 9.3

The complete solution is the result of both the positive and negative portions of the solution.

$\sin (x) = \frac{\sqrt{3}}{2}, - \frac{\sqrt{3}}{2}$

Step 10

Set up each of the solutions to solve for $x$ .

$\sin (x) = \frac{\sqrt{3}}{2}$

$\sin (x) = - \frac{\sqrt{3}}{2}$

Step 11

Solve for $x$ in $\sin (x) = \frac{\sqrt{3}}{2}$ .

Tap for more steps...

Step 11.1

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$x = \arcsin (\frac{\sqrt{3}}{2})$

Step 11.2

Simplify the right side.

Tap for more steps...

Step 11.2.1

The exact value of $\arcsin (\frac{\sqrt{3}}{2})$ is $\frac{π}{3}$ .

$x = \frac{π}{3}$

Step 11.3

The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from $π$ to find the solution in the second quadrant.

$x = π - \frac{π}{3}$

Step 11.4

Simplify $π - \frac{π}{3}$ .

Tap for more steps...

Step 11.4.1

To write $π$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$x = π \cdot \frac{3}{3} - \frac{π}{3}$

Step 11.4.2

Combine fractions.

Tap for more steps...

Step 11.4.2.1

Combine $π$ and $\frac{3}{3}$ .

$x = \frac{π \cdot 3}{3} - \frac{π}{3}$

Step 11.4.2.2

Combine the numerators over the common denominator.

$x = \frac{π \cdot 3 - π}{3}$

Step 11.4.3

Simplify the numerator.

Tap for more steps...

Step 11.4.3.1

Move $3$ to the left of $π$ .

$x = \frac{3 \cdot π - π}{3}$

Step 11.4.3.2

Subtract $π$ from $3 π$ .

$x = \frac{2 π}{3}$

Step 11.5

Find the period of $\sin (x)$ .

Tap for more steps...

Step 11.5.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 11.5.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 11.5.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 11.5.4

Divide $2 π$ by $1$ .

$2 π$

Step 11.6

The period of the $\sin (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = \frac{π}{3} + 2 π n, \frac{2 π}{3} + 2 π n$ , for any integer $n$

Step 12

Solve for $x$ in $\sin (x) = - \frac{\sqrt{3}}{2}$ .

Tap for more steps...

Step 12.1

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$x = \arcsin (- \frac{\sqrt{3}}{2})$

Step 12.2

Simplify the right side.

Tap for more steps...

Step 12.2.1

The exact value of $\arcsin (- \frac{\sqrt{3}}{2})$ is $- \frac{π}{3}$ .

$x = - \frac{π}{3}$

Step 12.3

The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from $2 π$ , to find a reference angle. Next, add this reference angle to $π$ to find the solution in the third quadrant.

$x = 2 π + \frac{π}{3} + π$

Step 12.4

Simplify the expression to find the second solution.

Tap for more steps...

Step 12.4.1

Subtract $2 π$ from $2 π + \frac{π}{3} + π$ .

$x = 2 π + \frac{π}{3} + π - 2 π$

Step 12.4.2

The resulting angle of $\frac{4 π}{3}$ is positive, less than $2 π$ , and coterminal with $2 π + \frac{π}{3} + π$ .

$x = \frac{4 π}{3}$

Step 12.5

Find the period of $\sin (x)$ .

Tap for more steps...

Step 12.5.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 12.5.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 12.5.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 12.5.4

Divide $2 π$ by $1$ .

$2 π$

Step 12.6

Add $2 π$ to every negative angle to get positive angles.

Tap for more steps...

Step 12.6.1

Add $2 π$ to $- \frac{π}{3}$ to find the positive angle.

$- \frac{π}{3} + 2 π$

Step 12.6.2

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$2 π \cdot \frac{3}{3} - \frac{π}{3}$

Step 12.6.3

Combine fractions.

Tap for more steps...

Step 12.6.3.1

Combine $2 π$ and $\frac{3}{3}$ .

$\frac{2 π \cdot 3}{3} - \frac{π}{3}$

Step 12.6.3.2

Combine the numerators over the common denominator.

$\frac{2 π \cdot 3 - π}{3}$

Step 12.6.4

Simplify the numerator.

Tap for more steps...

Step 12.6.4.1

Multiply $3$ by $2$ .

$\frac{6 π - π}{3}$

Step 12.6.4.2

Subtract $π$ from $6 π$ .

$\frac{5 π}{3}$

Step 12.6.5

List the new angles.

$x = \frac{5 π}{3}$

Step 12.7

The period of the $\sin (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = \frac{4 π}{3} + 2 π n, \frac{5 π}{3} + 2 π n$ , for any integer $n$

Step 13

List all of the solutions.

$x = \frac{π}{3} + 2 π n, \frac{2 π}{3} + 2 π n, \frac{4 π}{3} + 2 π n, \frac{5 π}{3} + 2 π n$ , for any integer $n$

Step 14

Consolidate the solutions.

Tap for more steps...

Step 14.1

Consolidate $\frac{π}{3} + 2 π n$ and $\frac{4 π}{3} + 2 π n$ to $\frac{π}{3} + π n$ .

$x = \frac{π}{3} + π n, \frac{2 π}{3} + 2 π n, \frac{5 π}{3} + 2 π n$ , for any integer $n$

Step 14.2

Consolidate $\frac{2 π}{3} + 2 π n$ and $\frac{5 π}{3} + 2 π n$ to $\frac{2 π}{3} + π n$ .

$x = \frac{π}{3} + π n, \frac{2 π}{3} + π n$ , for any integer $n$