Trigonometry Examples

$f (x) = \tan (x)$

Step 1

Find the x-intercepts.

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Step 1.1

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \tan (x)$

Step 1.2

Solve the equation.

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Step 1.2.1

Rewrite the equation as $\tan (x) = 0$ .

$\tan (x) = 0$

Step 1.2.2

Take the inverse tangent of both sides of the equation to extract $x$ from inside the tangent.

$x = \arctan (0)$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

The exact value of $\arctan (0)$ is $0$ .

$x = 0$

Step 1.2.4

The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from $π$ to find the solution in the fourth quadrant.

$x = π + 0$

Step 1.2.5

Add $π$ and $0$ .

$x = π$

Step 1.2.6

Find the period of $\tan (x)$ .

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Step 1.2.6.1

The period of the function can be calculated using $\frac{π}{| b |}$ .

$\frac{π}{| b |}$

Step 1.2.6.2

Replace $b$ with $1$ in the formula for period.

$\frac{π}{| 1 |}$

Step 1.2.6.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{π}{1}$

Step 1.2.6.4

Divide $π$ by $1$ .

$π$

Step 1.2.7

The period of the $\tan (x)$ function is $π$ so values will repeat every $π$ radians in both directions.

$x = π n, π + π n$ , for any integer $n$

Step 1.2.8

Consolidate the answers.

$x = π n$ , for any integer $n$

Step 1.3

x-intercept(s) in point form.

x-intercept(s): $(π n, 0)$ , for any integer $n$

Step 2

Find the y-intercepts.

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Step 2.1

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \tan (0)$

Step 2.2

Solve the equation.

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Step 2.2.1

Remove parentheses.

$y = \tan (0)$

Step 2.2.2

The exact value of $\tan (0)$ is $0$ .

$y = 0$

Step 2.3

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

Step 3

List the intersections.

x-intercept(s): $(π n, 0)$ , for any integer $n$

y-intercept(s): $(0, 0)$

Step 4