Trigonometry Examples

$\sqrt{\frac{1 - \cos (\frac{π}{6})}{2}}$

Step 1

The exact value of $\cos (\frac{π}{6})$ is $\frac{\sqrt{3}}{2}$ .

$\sqrt{\frac{1 - \frac{\sqrt{3}}{2}}{2}}$

Step 2

Simplify the numerator.

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Step 2.1

Write $1$ as a fraction with a common denominator.

$\sqrt{\frac{\frac{2}{2} - \frac{\sqrt{3}}{2}}{2}}$

Step 2.2

Combine the numerators over the common denominator.

$\sqrt{\frac{\frac{2 - \sqrt{3}}{2}}{2}}$

Step 3

Multiply the numerator by the reciprocal of the denominator.

$\sqrt{\frac{2 - \sqrt{3}}{2} \cdot \frac{1}{2}}$

Step 4

Multiply $\frac{2 - \sqrt{3}}{2} \cdot \frac{1}{2}$ .

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Step 4.1

Multiply $\frac{2 - \sqrt{3}}{2}$ by $\frac{1}{2}$ .

$\sqrt{\frac{2 - \sqrt{3}}{2 \cdot 2}}$

Step 4.2

Multiply $2$ by $2$ .

$\sqrt{\frac{2 - \sqrt{3}}{4}}$

Step 5

Rewrite $\sqrt{\frac{2 - \sqrt{3}}{4}}$ as $\frac{\sqrt{2 - \sqrt{3}}}{\sqrt{4}}$ .

$\frac{\sqrt{2 - \sqrt{3}}}{\sqrt{4}}$

Step 6

Simplify the denominator.

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Step 6.1

Rewrite $4$ as $2^{2}$ .

$\frac{\sqrt{2 - \sqrt{3}}}{\sqrt{2^{2}}}$

Step 6.2

Pull terms out from under the radical, assuming positive real numbers.

$\frac{\sqrt{2 - \sqrt{3}}}{2}$

Step 7

The result can be shown in multiple forms.

Exact Form:

$\frac{\sqrt{2 - \sqrt{3}}}{2}$

Decimal Form:

$0.25881904 \dots$