Trigonometry Examples

{csc}^{2} (x) - 2 = 0

$\csc^{2} (x) - 2 = 0$

Step 1

Add

$2$ to both sides of the equation.

$\csc^{2} (x) = 2$

Step 2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$\csc (x) = \pm \sqrt{2}$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

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Step 3.1

First, use the positive value of the

$\pm$ to find the first solution.

$\csc (x) = \sqrt{2}$

Step 3.2

Next, use the negative value of the

$\pm$ to find the second solution.

$\csc (x) = - \sqrt{2}$

Step 3.3

The complete solution is the result of both the positive and negative portions of the solution.

$\csc (x) = \sqrt{2}, - \sqrt{2}$

Step 4

Set up each of the solutions to solve for

$x$ .

$\csc (x) = \sqrt{2}$

$\csc (x) = - \sqrt{2}$

Step 5

Solve for

$x$ in

$\csc (x) = \sqrt{2}$ .

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Step 5.1

Take the inverse cosecant of both sides of the equation to extract

$x$ from inside the cosecant.

$x = arccsc (\sqrt{2})$

Step 5.2

Simplify the right side.

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Step 5.2.1

The exact value of

$arccsc (\sqrt{2})$ is

$\frac{π}{4}$ .

$x = \frac{π}{4}$

Step 5.3

The cosecant function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from

$π$ to find the solution in the second quadrant.

$x = π - \frac{π}{4}$

Step 5.4

Simplify

$π - \frac{π}{4}$ .

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Step 5.4.1

To write

$π$ as a fraction with a common denominator, multiply by

$\frac{4}{4}$ .

$x = π \cdot \frac{4}{4} - \frac{π}{4}$

Step 5.4.2

Combine fractions.

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Step 5.4.2.1

Combine

$π$ and

$\frac{4}{4}$ .

$x = \frac{π \cdot 4}{4} - \frac{π}{4}$

Step 5.4.2.2

Combine the numerators over the common denominator.

$x = \frac{π \cdot 4 - π}{4}$

Step 5.4.3

Simplify the numerator.

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Step 5.4.3.1

Move

$4$ to the left of

$π$ .

$x = \frac{4 \cdot π - π}{4}$

Step 5.4.3.2

Subtract

$π$ from

$4 π$ .

$x = \frac{3 π}{4}$

Step 5.5

Find the period of

$\csc (x)$ .

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Step 5.5.1

The period of the function can be calculated using

$\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 5.5.2

Replace

$b$ with

$1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 5.5.3

The absolute value is the distance between a number and zero. The distance between

$0$ and

$1$ is

$1$ .

$\frac{2 π}{1}$

Step 5.5.4

Divide

$2 π$ by

$1$ .

$2 π$

Step 5.6

The period of the

$\csc (x)$ function is

$2 π$ so values will repeat every

$2 π$ radians in both directions.

$x = \frac{π}{4} + 2 π n, \frac{3 π}{4} + 2 π n$ , for any integer

$n$

$x = \frac{π}{4} + 2 π n, \frac{3 π}{4} + 2 π n$ , for any integer

$n$

Step 6

Solve for

$x$ in

$\csc (x) = - \sqrt{2}$ .

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Step 6.1

Take the inverse cosecant of both sides of the equation to extract

$x$ from inside the cosecant.

$x = arccsc (- \sqrt{2})$

Step 6.2

Simplify the right side.

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Step 6.2.1

The exact value of

$arccsc (- \sqrt{2})$ is

$- \frac{π}{4}$ .

$x = - \frac{π}{4}$

Step 6.3

The cosecant function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from

$2 π$ , to find a reference angle. Next, add this reference angle to

$π$ to find the solution in the third quadrant.

$x = 2 π + \frac{π}{4} + π$

Step 6.4

Simplify the expression to find the second solution.

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Step 6.4.1

Subtract

$2 π$ from

$2 π + \frac{π}{4} + π$ .

$x = 2 π + \frac{π}{4} + π - 2 π$

Step 6.4.2

The resulting angle of

$\frac{5 π}{4}$ is positive, less than

$2 π$ , and coterminal with

$2 π + \frac{π}{4} + π$ .

$x = \frac{5 π}{4}$

Step 6.5

Find the period of

$\csc (x)$ .

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Step 6.5.1

The period of the function can be calculated using

$\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 6.5.2

Replace

$b$ with

$1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 6.5.3

The absolute value is the distance between a number and zero. The distance between

$0$ and

$1$ is

$1$ .

$\frac{2 π}{1}$

Step 6.5.4

Divide

$2 π$ by

$1$ .

$2 π$

Step 6.6

Add

$2 π$ to every negative angle to get positive angles.

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Step 6.6.1

Add

$2 π$ to

$- \frac{π}{4}$ to find the positive angle.

$- \frac{π}{4} + 2 π$

Step 6.6.2

To write

$2 π$ as a fraction with a common denominator, multiply by

$\frac{4}{4}$ .

$2 π \cdot \frac{4}{4} - \frac{π}{4}$

Step 6.6.3

Combine fractions.

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Step 6.6.3.1

Combine

$2 π$ and

$\frac{4}{4}$ .

$\frac{2 π \cdot 4}{4} - \frac{π}{4}$

Step 6.6.3.2

Combine the numerators over the common denominator.

$\frac{2 π \cdot 4 - π}{4}$

Step 6.6.4

Simplify the numerator.

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Step 6.6.4.1

Multiply

$4$ by

$2$ .

$\frac{8 π - π}{4}$

Step 6.6.4.2

Subtract

$π$ from

$8 π$ .

$\frac{7 π}{4}$

Step 6.6.5

List the new angles.

$x = \frac{7 π}{4}$

Step 6.7

The period of the

$\csc (x)$ function is

$2 π$ so values will repeat every

$2 π$ radians in both directions.

$x = \frac{5 π}{4} + 2 π n, \frac{7 π}{4} + 2 π n$ , for any integer

$n$

$x = \frac{5 π}{4} + 2 π n, \frac{7 π}{4} + 2 π n$ , for any integer

$n$

Step 7

List all of the solutions.

$x = \frac{π}{4} + 2 π n, \frac{3 π}{4} + 2 π n, \frac{5 π}{4} + 2 π n, \frac{7 π}{4} + 2 π n$ , for any integer

$n$

Step 8

Consolidate the answers.

$x = \frac{π}{4} + \frac{π n}{2}$ , for any integer

$n$