Trigonometry Examples

$\frac{\tan (x)}{\sec (x)} + \frac{\cot (x)}{\csc (x)} = \sin (x) + \cos (x)$

Step 1

Start on the left side.

$\frac{\tan (x)}{\sec (x)} + \frac{\cot (x)}{\csc (x)}$

Step 2

Convert to sines and cosines.

Tap for more steps...

Step 2.1

Write $\tan (x)$ in sines and cosines using the quotient identity.

$\frac{\frac{\sin (x)}{\cos (x)}}{\sec (x)} + \frac{\cot (x)}{\csc (x)}$

Step 2.2

Apply the reciprocal identity to $\sec (x)$ .

$\frac{\frac{\sin (x)}{\cos (x)}}{\frac{1}{\cos (x)}} + \frac{\cot (x)}{\csc (x)}$

Step 2.3

Write $\cot (x)$ in sines and cosines using the quotient identity.

$\frac{\frac{\sin (x)}{\cos (x)}}{\frac{1}{\cos (x)}} + \frac{\frac{\cos (x)}{\sin (x)}}{\csc (x)}$

Step 2.4

Apply the reciprocal identity to $\csc (x)$ .

$\frac{\frac{\sin (x)}{\cos (x)}}{\frac{1}{\cos (x)}} + \frac{\frac{\cos (x)}{\sin (x)}}{\frac{1}{\sin (x)}}$

Step 3

Simplify each term.

$\sin (x) + \cos (x)$

Step 4

Because the two sides have been shown to be equivalent, the equation is an identity.

$\frac{\tan (x)}{\sec (x)} + \frac{\cot (x)}{\csc (x)} = \sin (x) + \cos (x)$ is an identity