Trigonometry Examples

Graph y=cos(7x)
y=cos(7x)
Step 1
Use the form acos(bx-c)+d to find the variables used to find the amplitude, period, phase shift, and vertical shift.
a=1
b=7
c=0
d=0
Step 2
Find the amplitude |a|.
Amplitude: 1
Step 3
Find the period of cos(7x).
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Step 3.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 3.2
Replace b with 7 in the formula for period.
2π|7|
Step 3.3
The absolute value is the distance between a number and zero. The distance between 0 and 7 is 7.
2π7
2π7
Step 4
Find the phase shift using the formula cb.
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Step 4.1
The phase shift of the function can be calculated from cb.
Phase Shift: cb
Step 4.2
Replace the values of c and b in the equation for phase shift.
Phase Shift: 07
Step 4.3
Divide 0 by 7.
Phase Shift: 0
Phase Shift: 0
Step 5
List the properties of the trigonometric function.
Amplitude: 1
Period: 2π7
Phase Shift: None
Vertical Shift: None
Step 6
Select a few points to graph.
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Step 6.1
Find the point at x=0.
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Step 6.1.1
Replace the variable x with 0 in the expression.
f(0)=cos(7(0))
Step 6.1.2
Simplify the result.
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Step 6.1.2.1
Multiply 7 by 0.
f(0)=cos(0)
Step 6.1.2.2
The exact value of cos(0) is 1.
f(0)=1
Step 6.1.2.3
The final answer is 1.
1
1
1
Step 6.2
Find the point at x=π14.
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Step 6.2.1
Replace the variable x with π14 in the expression.
f(π14)=cos(7(π14))
Step 6.2.2
Simplify the result.
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Step 6.2.2.1
Cancel the common factor of 7.
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Step 6.2.2.1.1
Factor 7 out of 14.
f(π14)=cos(7(π7(2)))
Step 6.2.2.1.2
Cancel the common factor.
f(π14)=cos(7(π72))
Step 6.2.2.1.3
Rewrite the expression.
f(π14)=cos(π2)
f(π14)=cos(π2)
Step 6.2.2.2
The exact value of cos(π2) is 0.
f(π14)=0
Step 6.2.2.3
The final answer is 0.
0
0
0
Step 6.3
Find the point at x=π7.
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Step 6.3.1
Replace the variable x with π7 in the expression.
f(π7)=cos(7(π7))
Step 6.3.2
Simplify the result.
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Step 6.3.2.1
Cancel the common factor of 7.
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Step 6.3.2.1.1
Cancel the common factor.
f(π7)=cos(7(π7))
Step 6.3.2.1.2
Rewrite the expression.
f(π7)=cos(π)
f(π7)=cos(π)
Step 6.3.2.2
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.
f(π7)=-cos(0)
Step 6.3.2.3
The exact value of cos(0) is 1.
f(π7)=-11
Step 6.3.2.4
Multiply -1 by 1.
f(π7)=-1
Step 6.3.2.5
The final answer is -1.
-1
-1
-1
Step 6.4
Find the point at x=3π14.
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Step 6.4.1
Replace the variable x with 3π14 in the expression.
f(3π14)=cos(7(3π14))
Step 6.4.2
Simplify the result.
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Step 6.4.2.1
Cancel the common factor of 7.
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Step 6.4.2.1.1
Factor 7 out of 14.
f(3π14)=cos(7(3π7(2)))
Step 6.4.2.1.2
Cancel the common factor.
f(3π14)=cos(7(3π72))
Step 6.4.2.1.3
Rewrite the expression.
f(3π14)=cos(3π2)
f(3π14)=cos(3π2)
Step 6.4.2.2
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.
f(3π14)=cos(π2)
Step 6.4.2.3
The exact value of cos(π2) is 0.
f(3π14)=0
Step 6.4.2.4
The final answer is 0.
0
0
0
Step 6.5
Find the point at x=2π7.
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Step 6.5.1
Replace the variable x with 2π7 in the expression.
f(2π7)=cos(7(2π7))
Step 6.5.2
Simplify the result.
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Step 6.5.2.1
Cancel the common factor of 7.
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Step 6.5.2.1.1
Cancel the common factor.
f(2π7)=cos(7(2π7))
Step 6.5.2.1.2
Rewrite the expression.
f(2π7)=cos(2π)
f(2π7)=cos(2π)
Step 6.5.2.2
Subtract full rotations of 2π until the angle is greater than or equal to 0 and less than 2π.
f(2π7)=cos(0)
Step 6.5.2.3
The exact value of cos(0) is 1.
f(2π7)=1
Step 6.5.2.4
The final answer is 1.
1
1
1
Step 6.6
List the points in a table.
xf(x)01π140π7-13π1402π71
xf(x)01π140π7-13π1402π71
Step 7
The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.
Amplitude: 1
Period: 2π7
Phase Shift: None
Vertical Shift: None
xf(x)01π140π7-13π1402π71
Step 8
image of graph
Enter a problem...
 [x2  12  π  xdx ]