Trigonometry Examples

$(\frac{\sqrt{3}}{2}, \frac{1}{2})$

Step 1

To find the $\sin (θ)$ between the x-axis and the line between the points $(0, 0)$ and $(\frac{\sqrt{3}}{2}, \frac{1}{2})$ , draw the triangle between the three points $(0, 0)$ , $(\frac{\sqrt{3}}{2}, 0)$ , and $(\frac{\sqrt{3}}{2}, \frac{1}{2})$ .

Opposite : $\frac{1}{2}$

Adjacent : $\frac{\sqrt{3}}{2}$

Step 2

Find the hypotenuse using Pythagorean theorem $c = \sqrt{a^{2} + b^{2}}$ .

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Step 2.1

Apply the product rule to $\frac{\sqrt{3}}{2}$ .

$\sqrt{\frac{{\sqrt{3}}^{2}}{2^{2}} + {(\frac{1}{2})}^{2}}$

Step 2.2

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

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Step 2.2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\sqrt{\frac{{(3^{\frac{1}{2}})}^{2}}{2^{2}} + {(\frac{1}{2})}^{2}}$

Step 2.2.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\sqrt{\frac{3^{\frac{1}{2} \cdot 2}}{2^{2}} + {(\frac{1}{2})}^{2}}$

Step 2.2.3

Combine $\frac{1}{2}$ and $2$ .

$\sqrt{\frac{3^{\frac{2}{2}}}{2^{2}} + {(\frac{1}{2})}^{2}}$

Step 2.2.4

Cancel the common factor of $2$ .

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Step 2.2.4.1

Cancel the common factor.

$\sqrt{\frac{3^{\frac{2}{2}}}{2^{2}} + {(\frac{1}{2})}^{2}}$

Step 2.2.4.2

Rewrite the expression.

$\sqrt{\frac{3^{1}}{2^{2}} + {(\frac{1}{2})}^{2}}$

Step 2.2.5

Evaluate the exponent.

$\sqrt{\frac{3}{2^{2}} + {(\frac{1}{2})}^{2}}$

Step 2.3

Simplify the expression.

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Step 2.3.1

Raise $2$ to the power of $2$ .

$\sqrt{\frac{3}{4} + {(\frac{1}{2})}^{2}}$

Step 2.3.2

Apply the product rule to $\frac{1}{2}$ .

$\sqrt{\frac{3}{4} + \frac{1^{2}}{2^{2}}}$

Step 2.3.3

One to any power is one.

$\sqrt{\frac{3}{4} + \frac{1}{2^{2}}}$

Step 2.3.4

Raise $2$ to the power of $2$ .

$\sqrt{\frac{3}{4} + \frac{1}{4}}$

Step 2.3.5

Combine the numerators over the common denominator.

$\sqrt{\frac{3 + 1}{4}}$

Step 2.3.6

Add $3$ and $1$ .

$\sqrt{\frac{4}{4}}$

Step 2.3.7

Divide $4$ by $4$ .

$\sqrt{1}$

Step 2.3.8

Any root of $1$ is $1$ .

$1$

Step 3

$\sin (θ) = \frac{Opposite}{Hypotenuse}$ therefore $\sin (θ) = \frac{\frac{1}{2}}{1}$ .

$\frac{\frac{1}{2}}{1}$

Step 4

Divide $\frac{1}{2}$ by $1$ .

$\sin (θ) = \frac{1}{2}$

Step 5

Approximate the result.

$\sin (θ) = \frac{1}{2} \approx 0.5$