Trigonometry Examples

$\csc (B) - \sin (B) = \cot (B) \cos (B)$

Step 1

Start on the left side.

$\csc (B) - \sin (B)$

Step 2

Apply the reciprocal identity to $\csc (B)$ .

$\frac{1}{\sin (B)} - \sin (B)$

Step 3

Write $- \sin (B)$ as a fraction with denominator $1$ .

$\frac{1}{\sin (B)} + \frac{- \sin (B)}{1}$

Step 4

Add fractions.

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Step 4.1

To write $\frac{- \sin (B)}{1}$ as a fraction with a common denominator, multiply by $\frac{\sin (B)}{\sin (B)}$ .

$\frac{1}{\sin (B)} + \frac{- \sin (B)}{1} \cdot \frac{\sin (B)}{\sin (B)}$

Step 4.2

Multiply $\frac{- \sin (B)}{1}$ by $\frac{\sin (B)}{\sin (B)}$ .

$\frac{1}{\sin (B)} + \frac{- \sin (B) \sin (B)}{\sin (B)}$

Step 4.3

Combine the numerators over the common denominator.

$\frac{1 - \sin (B) \sin (B)}{\sin (B)}$

Step 5

Multiply $- \sin (B) \sin (B)$ .

$\frac{1 - \sin^{2} (B)}{\sin (B)}$

Step 6

Apply pythagorean identity.

$\frac{\cos^{2} (B)}{\sin (B)}$

Step 7

Rewrite $\frac{\cos^{2} (B)}{\sin (B)}$ as $\cot (B) \cos (B)$ .

$\cot (B) \cos (B)$

Step 8

Because the two sides have been shown to be equivalent, the equation is an identity.

$\csc (B) - \sin (B) = \cot (B) \cos (B)$ is an identity