Trigonometry Examples

$4 \sec (x) + 1 = 9$

Step 1

Move all terms not containing $\sec (x)$ to the right side of the equation.

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Step 1.1

Subtract $1$ from both sides of the equation.

$4 \sec (x) = 9 - 1$

Step 1.2

Subtract $1$ from $9$ .

$4 \sec (x) = 8$

Step 2

Divide each term in $4 \sec (x) = 8$ by $4$ and simplify.

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Step 2.1

Divide each term in $4 \sec (x) = 8$ by $4$ .

$\frac{4 \sec (x)}{4} = \frac{8}{4}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $4$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{4 \sec (x)}{4} = \frac{8}{4}$

Step 2.2.1.2

Divide $\sec (x)$ by $1$ .

$\sec (x) = \frac{8}{4}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Divide $8$ by $4$ .

$\sec (x) = 2$

Step 3

Take the inverse secant of both sides of the equation to extract $x$ from inside the secant.

$x = arcsec (2)$

Step 4

Simplify the right side.

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Step 4.1

The exact value of $arcsec (2)$ is $\frac{π}{3}$ .

$x = \frac{π}{3}$

Step 5

The secant function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the fourth quadrant.

$x = 2 π - \frac{π}{3}$

Step 6

Simplify $2 π - \frac{π}{3}$ .

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Step 6.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$x = 2 π \cdot \frac{3}{3} - \frac{π}{3}$

Step 6.2

Combine fractions.

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Step 6.2.1

Combine $2 π$ and $\frac{3}{3}$ .

$x = \frac{2 π \cdot 3}{3} - \frac{π}{3}$

Step 6.2.2

Combine the numerators over the common denominator.

$x = \frac{2 π \cdot 3 - π}{3}$

Step 6.3

Simplify the numerator.

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Step 6.3.1

Multiply $3$ by $2$ .

$x = \frac{6 π - π}{3}$

Step 6.3.2

Subtract $π$ from $6 π$ .

$x = \frac{5 π}{3}$

Step 7

Find the period of $\sec (x)$ .

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Step 7.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 7.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 7.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 7.4

Divide $2 π$ by $1$ .

$2 π$

Step 8

The period of the $\sec (x)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = \frac{π}{3} + 2 π n, \frac{5 π}{3} + 2 π n$ , for any integer $n$