Enter a problem...
Trigonometry Examples
cot(120)cot(120)
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cotangent is negative in the second quadrant.
-cot(60)−cot(60)
The exact value of cot(60)cot(60) is 1√31√3.
-1√3−1√3
Multiply 1√31√3 by √3√3√3√3.
-(1√3⋅√3√3)−(1√3⋅√3√3)
Multiply 1√31√3 by √3√3√3√3.
-√3√3√3−√3√3√3
Raise √3√3 to the power of 11.
-√3√31√3−√3√31√3
Raise √3√3 to the power of 11.
-√3√31√31−√3√31√31
Use the power rule aman=am+naman=am+n to combine exponents.
-√3√31+1−√3√31+1
Add 11 and 11.
-√3√32−√3√32
Rewrite √32√32 as 33.
Use n√ax=axnn√ax=axn to rewrite √3√3 as 312312.
-√3(312)2−√3(312)2
Apply the power rule and multiply exponents, (am)n=amn(am)n=amn.
-√3312⋅2−√3312⋅2
Combine 1212 and 22.
-√3322−√3322
Cancel the common factor of 22.
Cancel the common factor.
-√3322
Rewrite the expression.
-√331
-√331
Evaluate the exponent.
-√33
-√33
-√33
The result can be shown in multiple forms.
Exact Form:
-√33
Decimal Form:
-0.57735026…