Trigonometry Examples

$\cos (\frac{17 π}{12})$

Step 1

First, split the angle into two angles where the values of the six trigonometric functions are known. In this case, $\frac{17 π}{12}$ can be split into $\frac{7 π}{6} + \frac{π}{4}$ .

$\cos (\frac{7 π}{6} + \frac{π}{4})$

Step 2

Use the sum formula for cosine to simplify the expression. The formula states that $\cos (A + B) = - (\cos (A) \cos (B) + \sin (A) \sin (B))$ .

$\cos (\frac{π}{4}) \cdot \cos (\frac{7 π}{6}) - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 3

Remove parentheses.

$\cos (\frac{π}{4}) \cdot \cos (\frac{7 π}{6}) - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 4

Simplify each term.

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Step 4.1

The exact value of $\cos (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{2}}{2} \cdot \cos (\frac{7 π}{6}) - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 4.2

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the third quadrant.

$\frac{\sqrt{2}}{2} \cdot (- \cos (\frac{π}{6})) - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 4.3

The exact value of $\cos (\frac{π}{6})$ is $\frac{\sqrt{3}}{2}$ .

$\frac{\sqrt{2}}{2} \cdot (- \frac{\sqrt{3}}{2}) - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 4.4

Multiply $\frac{\sqrt{2}}{2} (- \frac{\sqrt{3}}{2})$ .

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Step 4.4.1

Multiply $\frac{\sqrt{2}}{2}$ by $\frac{\sqrt{3}}{2}$ .

$- \frac{\sqrt{2} \sqrt{3}}{2 \cdot 2} - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 4.4.2

Combine using the product rule for radicals.

$- \frac{\sqrt{2 \cdot 3}}{2 \cdot 2} - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 4.4.3

Multiply $2$ by $3$ .

$- \frac{\sqrt{6}}{2 \cdot 2} - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 4.4.4

Multiply $2$ by $2$ .

$- \frac{\sqrt{6}}{4} - \sin (\frac{π}{4}) \cdot \sin (\frac{7 π}{6})$

Step 4.5

The exact value of $\sin (\frac{π}{4})$ is $\frac{\sqrt{2}}{2}$ .

$- \frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2} \cdot \sin (\frac{7 π}{6})$

Step 4.6

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the third quadrant.

$- \frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2} \cdot (- \sin (\frac{π}{6}))$

Step 4.7

The exact value of $\sin (\frac{π}{6})$ is $\frac{1}{2}$ .

$- \frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2} \cdot (- \frac{1}{2})$

Step 4.8

Multiply $- \frac{\sqrt{2}}{2} (- \frac{1}{2})$ .

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Step 4.8.1

Multiply $- 1$ by $- 1$ .

$- \frac{\sqrt{6}}{4} + 1 \frac{\sqrt{2}}{2} \frac{1}{2}$

Step 4.8.2

Multiply $\frac{\sqrt{2}}{2}$ by $1$ .

$- \frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$

Step 4.8.3

Multiply $\frac{\sqrt{2}}{2}$ by $\frac{1}{2}$ .

$- \frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{2 \cdot 2}$

Step 4.8.4

Multiply $2$ by $2$ .

$- \frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4}$

Step 5

Simplify.

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Step 5.1

Combine the numerators over the common denominator.

$\frac{- \sqrt{6} + \sqrt{2}}{4}$

Step 5.2

Factor $- 1$ out of $- \sqrt{6}$ .

$\frac{- (\sqrt{6}) + \sqrt{2}}{4}$

Step 5.3

Factor $- 1$ out of $\sqrt{2}$ .

$\frac{- (\sqrt{6}) - 1 (- \sqrt{2})}{4}$

Step 5.4

Factor $- 1$ out of $- (\sqrt{6}) - 1 (- \sqrt{2})$ .

$\frac{- (\sqrt{6} - \sqrt{2})}{4}$

Step 5.5

Simplify the expression.

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Step 5.5.1

Rewrite $- (\sqrt{6} - \sqrt{2})$ as $- 1 (\sqrt{6} - \sqrt{2})$ .

$\frac{- 1 (\sqrt{6} - \sqrt{2})}{4}$

Step 5.5.2

Move the negative in front of the fraction.

$- \frac{\sqrt{6} - \sqrt{2}}{4}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$- \frac{\sqrt{6} - \sqrt{2}}{4}$

Decimal Form:

$- 0.25881904 \dots$