Trigonometry Examples

$(- 6, \frac{3 π}{2})$

Step 1

Use the conversion formulas to convert from polar coordinates to rectangular coordinates.

$x = r c o s θ$

$y = r s i n θ$

Step 2

Substitute in the known values of $r = - 6$ and $θ = \frac{3 π}{2}$ into the formulas.

$x = (- 6) \cos (\frac{3 π}{2})$

$y = (- 6) \sin (\frac{3 π}{2})$

Step 3

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$x = - 6 \cos (\frac{π}{2})$

$y = (- 6) \sin (\frac{3 π}{2})$

Step 4

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$x = - 6 \cdot 0$

$y = (- 6) \sin (\frac{3 π}{2})$

Step 5

Multiply $- 6$ by $0$ .

$x = 0$

$y = (- 6) \sin (\frac{3 π}{2})$

Step 6

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the fourth quadrant.

$x = 0$

$y = - 6 (- \sin (\frac{π}{2}))$

Step 7

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$x = 0$

$y = - 6 (- 1 \cdot 1)$

Step 8

Multiply $- 6 (- 1 \cdot 1)$ .

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Step 8.1

Multiply $- 1$ by $1$ .

$x = 0$

$y = - 6 \cdot - 1$

Step 8.2

Multiply $- 6$ by $- 1$ .

$x = 0$

$y = 6$

$x = 0$

$y = 6$

Step 9

The rectangular representation of the polar point $(- 6, \frac{3 π}{2})$ is $(0, 6)$ .

$(0, 6)$