Trigonometry Examples

\sin (270 °)

$\sin (270 °)$

Step 1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the third quadrant.

- \sin (90)

$- \sin (90)$

Step 2

The exact value of

\sin (90)

$\sin (90)$ is

1

$1$ .

- 1 \cdot 1

$- 1 \cdot 1$

Step 3

Multiply

- 1

$- 1$ by

1

$1$ .

- 1

$- 1$

[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$