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Trigonometry Examples
cos(2x)=-1cos(2x)=−1
Step 1
Take the inverse cosine of both sides of the equation to extract xx from inside the cosine.
2x=arccos(-1)2x=arccos(−1)
Step 2
Step 2.1
The exact value of arccos(-1)arccos(−1) is ππ.
2x=π2x=π
2x=π2x=π
Step 3
Step 3.1
Divide each term in 2x=π2x=π by 22.
2x2=π22x2=π2
Step 3.2
Simplify the left side.
Step 3.2.1
Cancel the common factor of 22.
Step 3.2.1.1
Cancel the common factor.
2x2=π2
Step 3.2.1.2
Divide x by 1.
x=π2
x=π2
x=π2
x=π2
Step 4
The cosine function is negative in the second and third quadrants. To find the second solution, subtract the reference angle from 2π to find the solution in the third quadrant.
2x=2π-π
Step 5
Step 5.1
Subtract π from 2π.
2x=π
Step 5.2
Divide each term in 2x=π by 2 and simplify.
Step 5.2.1
Divide each term in 2x=π by 2.
2x2=π2
Step 5.2.2
Simplify the left side.
Step 5.2.2.1
Cancel the common factor of 2.
Step 5.2.2.1.1
Cancel the common factor.
2x2=π2
Step 5.2.2.1.2
Divide x by 1.
x=π2
x=π2
x=π2
x=π2
x=π2
Step 6
Step 6.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 6.2
Replace b with 2 in the formula for period.
2π|2|
Step 6.3
The absolute value is the distance between a number and zero. The distance between 0 and 2 is 2.
2π2
Step 6.4
Cancel the common factor of 2.
Step 6.4.1
Cancel the common factor.
2π2
Step 6.4.2
Divide π by 1.
π
π
π
Step 7
The period of the cos(2x) function is π so values will repeat every π radians in both directions.
x=π2+πn, for any integer n