Trigonometry Examples

{cos}^{2} (x) = cos (x)

$\cos^{2} (x) = \cos (x)$

Step 1

Subtract

cos (x)

$\cos (x)$ from both sides of the equation.

$\cos^{2} (x) - \cos (x) = 0$

Step 2

Factor

$\cos (x)$ out of

$\cos^{2} (x) - \cos (x)$ .

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Step 2.1

Factor

$\cos (x)$ out of

$\cos^{2} (x)$ .

$\cos (x) \cos (x) - \cos (x) = 0$

Step 2.2

Factor

$\cos (x)$ out of

$- \cos (x)$ .

$\cos (x) \cos (x) + \cos (x) \cdot - 1 = 0$

Step 2.3

Factor

$\cos (x)$ out of

$\cos (x) \cos (x) + \cos (x) \cdot - 1$ .

$\cos (x) (\cos (x) - 1) = 0$

Step 3

If any individual factor on the left side of the equation is equal to

$0$ , the entire expression will be equal to

$0$ .

$\cos (x) = 0$

$\cos (x) - 1 = 0$

Step 4

Set

$\cos (x)$ equal to

$0$ and solve for

$x$ .

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Step 4.1

Set

$\cos (x)$ equal to

$0$ .

$\cos (x) = 0$

Step 4.2

Solve

$\cos (x) = 0$ for

$x$ .

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Step 4.2.1

Take the inverse cosine of both sides of the equation to extract

$x$ from inside the cosine.

$x = \arccos (0)$

Step 4.2.2

Simplify the right side.

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Step 4.2.2.1

The exact value of

$\arccos (0)$ is

$\frac{π}{2}$ .

$x = \frac{π}{2}$

Step 4.2.3

The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from

$2 π$ to find the solution in the fourth quadrant.

$x = 2 π - \frac{π}{2}$

Step 4.2.4

Simplify

$2 π - \frac{π}{2}$ .

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Step 4.2.4.1

To write

$2 π$ as a fraction with a common denominator, multiply by

$\frac{2}{2}$ .

$x = 2 π \cdot \frac{2}{2} - \frac{π}{2}$

Step 4.2.4.2

Combine fractions.

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Step 4.2.4.2.1

Combine

$2 π$ and

$\frac{2}{2}$ .

$x = \frac{2 π \cdot 2}{2} - \frac{π}{2}$

Step 4.2.4.2.2

Combine the numerators over the common denominator.

$x = \frac{2 π \cdot 2 - π}{2}$

Step 4.2.4.3

Simplify the numerator.

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Step 4.2.4.3.1

Multiply

$2$ by

$2$ .

$x = \frac{4 π - π}{2}$

Step 4.2.4.3.2

Subtract

$π$ from

$4 π$ .

$x = \frac{3 π}{2}$

Step 4.2.5

Find the period of

$\cos (x)$ .

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Step 4.2.5.1

The period of the function can be calculated using

$\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 4.2.5.2

Replace

$b$ with

$1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 4.2.5.3

The absolute value is the distance between a number and zero. The distance between

$0$ and

$1$ is

$1$ .

$\frac{2 π}{1}$

Step 4.2.5.4

Divide

$2 π$ by

$1$ .

$2 π$

Step 4.2.6

The period of the

$\cos (x)$ function is

$2 π$ so values will repeat every

$2 π$ radians in both directions.

$x = \frac{π}{2} + 2 π n, \frac{3 π}{2} + 2 π n$ , for any integer

$n$

$x = \frac{π}{2} + 2 π n, \frac{3 π}{2} + 2 π n$ , for any integer

$n$

$x = \frac{π}{2} + 2 π n, \frac{3 π}{2} + 2 π n$ , for any integer

$n$

Step 5

Set

$\cos (x) - 1$ equal to

$0$ and solve for

$x$ .

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Step 5.1

Set

$\cos (x) - 1$ equal to

$0$ .

$\cos (x) - 1 = 0$

Step 5.2

Solve

$\cos (x) - 1 = 0$ for

$x$ .

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Step 5.2.1

Add

$1$ to both sides of the equation.

$\cos (x) = 1$

Step 5.2.2

Take the inverse cosine of both sides of the equation to extract

$x$ from inside the cosine.

$x = \arccos (1)$

Step 5.2.3

Simplify the right side.

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Step 5.2.3.1

The exact value of

$\arccos (1)$ is

$0$ .

$x = 0$

Step 5.2.4

The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from

$2 π$ to find the solution in the fourth quadrant.

$x = 2 π - 0$

Step 5.2.5

Subtract

$0$ from

$2 π$ .

$x = 2 π$

Step 5.2.6

Find the period of

$\cos (x)$ .

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Step 5.2.6.1

The period of the function can be calculated using

$\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 5.2.6.2

Replace

$b$ with

$1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 5.2.6.3

The absolute value is the distance between a number and zero. The distance between

$0$ and

$1$ is

$1$ .

$\frac{2 π}{1}$

Step 5.2.6.4

Divide

$2 π$ by

$1$ .

$2 π$

Step 5.2.7

The period of the

$\cos (x)$ function is

$2 π$ so values will repeat every

$2 π$ radians in both directions.

$x = 2 π n, 2 π + 2 π n$ , for any integer

$n$

$x = 2 π n, 2 π + 2 π n$ , for any integer

$n$

$x = 2 π n, 2 π + 2 π n$ , for any integer

$n$

Step 6

The final solution is all the values that make

$\cos (x) (\cos (x) - 1) = 0$ true.

$x = \frac{π}{2} + 2 π n, \frac{3 π}{2} + 2 π n, 2 π n, 2 π + 2 π n$ , for any integer

$n$

Step 7

Consolidate the answers.

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Step 7.1

Consolidate

$\frac{π}{2} + 2 π n$ and

$\frac{3 π}{2} + 2 π n$ to

$\frac{π}{2} + π n$ .

$x = \frac{π}{2} + π n, 2 π n, 2 π + 2 π n$ , for any integer

$n$

Step 7.2

Consolidate

$2 π n$ and

$2 π + 2 π n$ to

$2 π n$ .

$x = \frac{π}{2} + π n, 2 π n$ , for any integer

$n$

$x = \frac{π}{2} + π n, 2 π n$ , for any integer

$n$