Trigonometry Examples

Verify the Identity (sec(B)+tan(B))(1-sin(B))=cos(B)
(sec(B)+tan(B))(1-sin(B))=cos(B)
Step 1
Start on the left side.
(sec(B)+tan(B))(1-sin(B))
Step 2
Simplify the expression.
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Step 2.1
Simplify each term.
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Step 2.1.1
Rewrite sec(B) in terms of sines and cosines.
(1cos(B)+tan(B))(1-sin(B))
Step 2.1.2
Rewrite tan(B) in terms of sines and cosines.
(1cos(B)+sin(B)cos(B))(1-sin(B))
(1cos(B)+sin(B)cos(B))(1-sin(B))
Step 2.2
Expand (1cos(B)+sin(B)cos(B))(1-sin(B)) using the FOIL Method.
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Step 2.2.1
Apply the distributive property.
1cos(B)(1-sin(B))+sin(B)cos(B)(1-sin(B))
Step 2.2.2
Apply the distributive property.
1cos(B)1+1cos(B)(-sin(B))+sin(B)cos(B)(1-sin(B))
Step 2.2.3
Apply the distributive property.
1cos(B)1+1cos(B)(-sin(B))+sin(B)cos(B)1+sin(B)cos(B)(-sin(B))
1cos(B)1+1cos(B)(-sin(B))+sin(B)cos(B)1+sin(B)cos(B)(-sin(B))
Step 2.3
Simplify and combine like terms.
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Step 2.3.1
Simplify each term.
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Step 2.3.1.1
Multiply 1cos(B) by 1.
1cos(B)+1cos(B)(-sin(B))+sin(B)cos(B)1+sin(B)cos(B)(-sin(B))
Step 2.3.1.2
Rewrite using the commutative property of multiplication.
1cos(B)-1cos(B)sin(B)+sin(B)cos(B)1+sin(B)cos(B)(-sin(B))
Step 2.3.1.3
Combine sin(B) and 1cos(B).
1cos(B)-sin(B)cos(B)+sin(B)cos(B)1+sin(B)cos(B)(-sin(B))
Step 2.3.1.4
Multiply sin(B)cos(B) by 1.
1cos(B)-sin(B)cos(B)+sin(B)cos(B)+sin(B)cos(B)(-sin(B))
Step 2.3.1.5
Rewrite using the commutative property of multiplication.
1cos(B)-sin(B)cos(B)+sin(B)cos(B)-sin(B)cos(B)sin(B)
Step 2.3.1.6
Multiply -sin(B)cos(B)sin(B).
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Step 2.3.1.6.1
Combine sin(B) and sin(B)cos(B).
1cos(B)-sin(B)cos(B)+sin(B)cos(B)-sin(B)sin(B)cos(B)
Step 2.3.1.6.2
Raise sin(B) to the power of 1.
1cos(B)-sin(B)cos(B)+sin(B)cos(B)-sin1(B)sin(B)cos(B)
Step 2.3.1.6.3
Raise sin(B) to the power of 1.
1cos(B)-sin(B)cos(B)+sin(B)cos(B)-sin1(B)sin1(B)cos(B)
Step 2.3.1.6.4
Use the power rule aman=am+n to combine exponents.
1cos(B)-sin(B)cos(B)+sin(B)cos(B)-sin(B)1+1cos(B)
Step 2.3.1.6.5
Add 1 and 1.
1cos(B)-sin(B)cos(B)+sin(B)cos(B)-sin2(B)cos(B)
1cos(B)-sin(B)cos(B)+sin(B)cos(B)-sin2(B)cos(B)
1cos(B)-sin(B)cos(B)+sin(B)cos(B)-sin2(B)cos(B)
Step 2.3.2
Add -sin(B)cos(B) and sin(B)cos(B).
1cos(B)+0-sin2(B)cos(B)
Step 2.3.3
Add 1cos(B) and 0.
1cos(B)-sin2(B)cos(B)
1cos(B)-sin2(B)cos(B)
Step 2.4
Combine the numerators over the common denominator.
1-sin2(B)cos(B)
Step 2.5
Apply pythagorean identity.
cos2(B)cos(B)
Step 2.6
Cancel the common factor of cos2(B) and cos(B).
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Step 2.6.1
Factor cos(B) out of cos2(B).
cos(B)cos(B)cos(B)
Step 2.6.2
Cancel the common factors.
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Step 2.6.2.1
Multiply by 1.
cos(B)cos(B)cos(B)1
Step 2.6.2.2
Cancel the common factor.
cos(B)cos(B)cos(B)1
Step 2.6.2.3
Rewrite the expression.
cos(B)1
Step 2.6.2.4
Divide cos(B) by 1.
cos(B)
cos(B)
cos(B)
cos(B)
Step 3
Because the two sides have been shown to be equivalent, the equation is an identity.
(sec(B)+tan(B))(1-sin(B))=cos(B) is an identity
(sec(B)+tan(B))(1-sin(B))=cos(B)
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