Trigonometry Examples

\sin^{2} (θ) + \cos^{2} (θ) = 1

$\sin^{2} (θ) + \cos^{2} (θ) = 1$

Step 1

Subtract

1

$1$ from both sides of the equation.

\sin^{2} (θ) + \cos^{2} (θ) - 1 = 0

$\sin^{2} (θ) + \cos^{2} (θ) - 1 = 0$

Step 2

Simplify

\sin^{2} (θ) + \cos^{2} (θ) - 1

$\sin^{2} (θ) + \cos^{2} (θ) - 1$ .

Tap for more steps...

Step 2.1

Apply pythagorean identity.

1 - 1 = 0

$1 - 1 = 0$

Step 2.2

Subtract

1

$1$ from

1

$1$ .

0 = 0

$0 = 0$

0 = 0

$0 = 0$

Step 3

Since

0 = 0

$0 = 0$ , the equation will always be true.

Always true

Step 4

The result can be shown in multiple forms.

Always true

Interval Notation:

(- \infty, \infty)

$(- \infty, \infty)$

[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$