Trigonometry Examples

Solve for x in Degrees sin(x)+1=0
sin(x)+1=0
Step 1
Subtract 1 from both sides of the equation.
sin(x)=-1
Step 2
Take the inverse sine of both sides of the equation to extract x from inside the sine.
x=arcsin(-1)
Step 3
Simplify the right side.
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Step 3.1
The exact value of arcsin(-1) is -90.
x=-90
x=-90
Step 4
The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from 360, to find a reference angle. Next, add this reference angle to 180 to find the solution in the third quadrant.
x=360+90+180
Step 5
Simplify the expression to find the second solution.
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Step 5.1
Subtract 360° from 360+90+180°.
x=360+90+180°-360°
Step 5.2
The resulting angle of 270° is positive, less than 360°, and coterminal with 360+90+180.
x=270°
x=270°
Step 6
Find the period of sin(x).
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Step 6.1
The period of the function can be calculated using 360|b|.
360|b|
Step 6.2
Replace b with 1 in the formula for period.
360|1|
Step 6.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
3601
Step 6.4
Divide 360 by 1.
360
360
Step 7
Add 360 to every negative angle to get positive angles.
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Step 7.1
Add 360 to -90 to find the positive angle.
-90+360
Step 7.2
Subtract 90 from 360.
270
Step 7.3
List the new angles.
x=270
x=270
Step 8
The period of the sin(x) function is 360 so values will repeat every 360 degrees in both directions.
x=270+360n,270+360n, for any integer n
Step 9
Consolidate the answers.
x=270+360n, for any integer n
 [x2  12  π  xdx ]