Trigonometry Examples

Solve for x in Degrees cos(x)+ square root of 3=-cos(x)
cos(x)+3=-cos(x)
Step 1
Move all terms containing cos(x) to the left side of the equation.
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Step 1.1
Add cos(x) to both sides of the equation.
cos(x)+3+cos(x)=0
Step 1.2
Add cos(x) and cos(x).
2cos(x)+3=0
2cos(x)+3=0
Step 2
Subtract 3 from both sides of the equation.
2cos(x)=-3
Step 3
Divide each term in 2cos(x)=-3 by 2 and simplify.
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Step 3.1
Divide each term in 2cos(x)=-3 by 2.
2cos(x)2=-32
Step 3.2
Simplify the left side.
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Step 3.2.1
Cancel the common factor of 2.
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Step 3.2.1.1
Cancel the common factor.
2cos(x)2=-32
Step 3.2.1.2
Divide cos(x) by 1.
cos(x)=-32
cos(x)=-32
cos(x)=-32
Step 3.3
Simplify the right side.
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Step 3.3.1
Move the negative in front of the fraction.
cos(x)=-32
cos(x)=-32
cos(x)=-32
Step 4
Take the inverse cosine of both sides of the equation to extract x from inside the cosine.
x=arccos(-32)
Step 5
Simplify the right side.
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Step 5.1
The exact value of arccos(-32) is 150.
x=150
x=150
Step 6
The cosine function is negative in the second and third quadrants. To find the second solution, subtract the reference angle from 360 to find the solution in the third quadrant.
x=360-150
Step 7
Subtract 150 from 360.
x=210
Step 8
Find the period of cos(x).
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Step 8.1
The period of the function can be calculated using 360|b|.
360|b|
Step 8.2
Replace b with 1 in the formula for period.
360|1|
Step 8.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
3601
Step 8.4
Divide 360 by 1.
360
360
Step 9
The period of the cos(x) function is 360 so values will repeat every 360 degrees in both directions.
x=150+360n,210+360n, for any integer n
 [x2  12  π  xdx ]