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Trigonometry Examples
cos(x)+√3=-cos(x)
Step 1
Step 1.1
Add cos(x) to both sides of the equation.
cos(x)+√3+cos(x)=0
Step 1.2
Add cos(x) and cos(x).
2cos(x)+√3=0
2cos(x)+√3=0
Step 2
Subtract √3 from both sides of the equation.
2cos(x)=-√3
Step 3
Step 3.1
Divide each term in 2cos(x)=-√3 by 2.
2cos(x)2=-√32
Step 3.2
Simplify the left side.
Step 3.2.1
Cancel the common factor of 2.
Step 3.2.1.1
Cancel the common factor.
2cos(x)2=-√32
Step 3.2.1.2
Divide cos(x) by 1.
cos(x)=-√32
cos(x)=-√32
cos(x)=-√32
Step 3.3
Simplify the right side.
Step 3.3.1
Move the negative in front of the fraction.
cos(x)=-√32
cos(x)=-√32
cos(x)=-√32
Step 4
Take the inverse cosine of both sides of the equation to extract x from inside the cosine.
x=arccos(-√32)
Step 5
Step 5.1
The exact value of arccos(-√32) is 150.
x=150
x=150
Step 6
The cosine function is negative in the second and third quadrants. To find the second solution, subtract the reference angle from 360 to find the solution in the third quadrant.
x=360-150
Step 7
Subtract 150 from 360.
x=210
Step 8
Step 8.1
The period of the function can be calculated using 360|b|.
360|b|
Step 8.2
Replace b with 1 in the formula for period.
360|1|
Step 8.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
3601
Step 8.4
Divide 360 by 1.
360
360
Step 9
The period of the cos(x) function is 360 so values will repeat every 360 degrees in both directions.
x=150+360n,210+360n, for any integer n