Trigonometry Examples

Verify the Identity x^3+y^3=(x+y)(x^2-xy+y^2)
x3+y3=(x+y)(x2-xy+y2)
Step 1
Expand (x+y)(x2-xy+y2) by multiplying each term in the first expression by each term in the second expression.
x3+y3=xx2+x(-xy)+xy2+yx2+y(-xy)+yy2
Step 2
Simplify each term.
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Step 2.1
Multiply x by x2 by adding the exponents.
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Step 2.1.1
Multiply x by x2.
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Step 2.1.1.1
Raise x to the power of 1.
x3+y3=x1x2+x(-xy)+xy2+yx2+y(-xy)+yy2
Step 2.1.1.2
Use the power rule aman=am+n to combine exponents.
x3+y3=x1+2+x(-xy)+xy2+yx2+y(-xy)+yy2
x3+y3=x1+2+x(-xy)+xy2+yx2+y(-xy)+yy2
Step 2.1.2
Add 1 and 2.
x3+y3=x3+x(-xy)+xy2+yx2+y(-xy)+yy2
x3+y3=x3+x(-xy)+xy2+yx2+y(-xy)+yy2
Step 2.2
Rewrite using the commutative property of multiplication.
x3+y3=x3-x(xy)+xy2+yx2+y(-xy)+yy2
Step 2.3
Multiply x by x by adding the exponents.
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Step 2.3.1
Move x.
x3+y3=x3-(xx)y+xy2+yx2+y(-xy)+yy2
Step 2.3.2
Multiply x by x.
x3+y3=x3-x2y+xy2+yx2+y(-xy)+yy2
x3+y3=x3-x2y+xy2+yx2+y(-xy)+yy2
Step 2.4
Rewrite using the commutative property of multiplication.
x3+y3=x3-x2y+xy2+yx2-y(xy)+yy2
Step 2.5
Multiply y by y by adding the exponents.
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Step 2.5.1
Move y.
x3+y3=x3-x2y+xy2+yx2-(yy)x+yy2
Step 2.5.2
Multiply y by y.
x3+y3=x3-x2y+xy2+yx2-y2x+yy2
x3+y3=x3-x2y+xy2+yx2-y2x+yy2
Step 2.6
Multiply y by y2 by adding the exponents.
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Step 2.6.1
Multiply y by y2.
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Step 2.6.1.1
Raise y to the power of 1.
x3+y3=x3-x2y+xy2+yx2-y2x+y1y2
Step 2.6.1.2
Use the power rule aman=am+n to combine exponents.
x3+y3=x3-x2y+xy2+yx2-y2x+y1+2
x3+y3=x3-x2y+xy2+yx2-y2x+y1+2
Step 2.6.2
Add 1 and 2.
x3+y3=x3-x2y+xy2+yx2-y2x+y3
x3+y3=x3-x2y+xy2+yx2-y2x+y3
x3+y3=x3-x2y+xy2+yx2-y2x+y3
Step 3
Combine the opposite terms in x3-x2y+xy2+yx2-y2x+y3.
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Step 3.1
Reorder the factors in the terms -x2y and yx2.
x3+y3=x3-x2y+xy2+x2y-y2x+y3
Step 3.2
Add -x2y and x2y.
x3+y3=x3+xy2+0-y2x+y3
Step 3.3
Add x3+xy2 and 0.
x3+y3=x3+xy2-y2x+y3
Step 3.4
Reorder the factors in the terms xy2 and -y2x.
x3+y3=x3+y2x-y2x+y3
Step 3.5
Subtract y2x from y2x.
x3+y3=x3+0+y3
Step 3.6
Add x3 and 0.
x3+y3=x3+y3
x3+y3=x3+y3
Step 4
Since the two sides have been shown to be equivalent, the equation is an identity.
x3+y3=(x+y)(x2-xy+y2) is an identity.
 [x2  12  π  xdx ]