Enter a problem...
Trigonometry Examples
sec(x)=-52sec(x)=−52 , tan(x)<0tan(x)<0
Step 1
The tangent function is negative in the second and fourth quadrants. The secant function is negative in the second and third quadrants. The set of solutions for xx are limited to the second quadrant since that is the only quadrant found in both sets.
Solution is in the second quadrant.
Step 2
Use the definition of secant to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values.
sec(x)=hypotenuseadjacentsec(x)=hypotenuseadjacent
Step 3
Find the opposite side of the unit circle triangle. Since the adjacent side and hypotenuse are known, use the Pythagorean theorem to find the remaining side.
Opposite=√hypotenuse2-adjacent2Opposite=√hypotenuse2−adjacent2
Step 4
Replace the known values in the equation.
Opposite=√(5)2-(-2)2Opposite=√(5)2−(−2)2
Step 5
Step 5.1
Raise 55 to the power of 22.
Opposite =√25-(-2)2=√25−(−2)2
Step 5.2
Raise -2−2 to the power of 22.
Opposite =√25-1⋅4=√25−1⋅4
Step 5.3
Multiply -1−1 by 44.
Opposite =√25-4=√25−4
Step 5.4
Subtract 44 from 2525.
Opposite =√21=√21
Opposite =√21=√21
Step 6
Step 6.1
Use the definition of sine to find the value of sin(x)sin(x).
sin(x)=opphypsin(x)=opphyp
Step 6.2
Substitute in the known values.
sin(x)=√215sin(x)=√215
sin(x)=√215
Step 7
Step 7.1
Use the definition of cosine to find the value of cos(x).
cos(x)=adjhyp
Step 7.2
Substitute in the known values.
cos(x)=-25
Step 7.3
Move the negative in front of the fraction.
cos(x)=-25
cos(x)=-25
Step 8
Step 8.1
Use the definition of tangent to find the value of tan(x).
tan(x)=oppadj
Step 8.2
Substitute in the known values.
tan(x)=√21-2
Step 8.3
Move the negative in front of the fraction.
tan(x)=-√212
tan(x)=-√212
Step 9
Step 9.1
Use the definition of cotangent to find the value of cot(x).
cot(x)=adjopp
Step 9.2
Substitute in the known values.
cot(x)=-2√21
Step 9.3
Simplify the value of cot(x).
Step 9.3.1
Move the negative in front of the fraction.
cot(x)=-2√21
Step 9.3.2
Multiply 2√21 by √21√21.
cot(x)=-(2√21⋅√21√21)
Step 9.3.3
Combine and simplify the denominator.
Step 9.3.3.1
Multiply 2√21 by √21√21.
cot(x)=-2√21√21√21
Step 9.3.3.2
Raise √21 to the power of 1.
cot(x)=-2√21√21√21
Step 9.3.3.3
Raise √21 to the power of 1.
cot(x)=-2√21√21√21
Step 9.3.3.4
Use the power rule aman=am+n to combine exponents.
cot(x)=-2√21√211+1
Step 9.3.3.5
Add 1 and 1.
cot(x)=-2√21√212
Step 9.3.3.6
Rewrite √212 as 21.
Step 9.3.3.6.1
Use n√ax=axn to rewrite √21 as 2112.
cot(x)=-2√21(2112)2
Step 9.3.3.6.2
Apply the power rule and multiply exponents, (am)n=amn.
cot(x)=-2√212112⋅2
Step 9.3.3.6.3
Combine 12 and 2.
cot(x)=-2√212122
Step 9.3.3.6.4
Cancel the common factor of 2.
Step 9.3.3.6.4.1
Cancel the common factor.
cot(x)=-2√212122
Step 9.3.3.6.4.2
Rewrite the expression.
cot(x)=-2√2121
cot(x)=-2√2121
Step 9.3.3.6.5
Evaluate the exponent.
cot(x)=-2√2121
cot(x)=-2√2121
cot(x)=-2√2121
cot(x)=-2√2121
cot(x)=-2√2121
Step 10
Step 10.1
Use the definition of cosecant to find the value of csc(x).
csc(x)=hypopp
Step 10.2
Substitute in the known values.
csc(x)=5√21
Step 10.3
Simplify the value of csc(x).
Step 10.3.1
Multiply 5√21 by √21√21.
csc(x)=5√21⋅√21√21
Step 10.3.2
Combine and simplify the denominator.
Step 10.3.2.1
Multiply 5√21 by √21√21.
csc(x)=5√21√21√21
Step 10.3.2.2
Raise √21 to the power of 1.
csc(x)=5√21√21√21
Step 10.3.2.3
Raise √21 to the power of 1.
csc(x)=5√21√21√21
Step 10.3.2.4
Use the power rule aman=am+n to combine exponents.
csc(x)=5√21√211+1
Step 10.3.2.5
Add 1 and 1.
csc(x)=5√21√212
Step 10.3.2.6
Rewrite √212 as 21.
Step 10.3.2.6.1
Use n√ax=axn to rewrite √21 as 2112.
csc(x)=5√21(2112)2
Step 10.3.2.6.2
Apply the power rule and multiply exponents, (am)n=amn.
csc(x)=5√212112⋅2
Step 10.3.2.6.3
Combine 12 and 2.
csc(x)=5√212122
Step 10.3.2.6.4
Cancel the common factor of 2.
Step 10.3.2.6.4.1
Cancel the common factor.
csc(x)=5√212122
Step 10.3.2.6.4.2
Rewrite the expression.
csc(x)=5√2121
csc(x)=5√2121
Step 10.3.2.6.5
Evaluate the exponent.
csc(x)=5√2121
csc(x)=5√2121
csc(x)=5√2121
csc(x)=5√2121
csc(x)=5√2121
Step 11
This is the solution to each trig value.
sin(x)=√215
cos(x)=-25
tan(x)=-√212
cot(x)=-2√2121
sec(x)=-52
csc(x)=5√2121