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Trigonometry
Verify the Identity csc(theta)^2=1+cot(theta)^2
csc
2
(
θ
)
=
1
+
cot
2
(
θ
)
csc
2
(
θ
)
=
1
+
cot
2
(
θ
)
Step 1
Start on the right side.
1
+
cot
2
(
θ
)
1
+
cot
2
(
θ
)
Step 2
Apply pythagorean
identity
.
csc
2
(
θ
)
csc
2
(
θ
)
Step 3
Because the two sides have been shown to be
equivalent
, the
equation
is an
identity
.
csc
2
(
θ
)
=
1
+
cot
2
(
θ
)
csc
2
(
θ
)
=
1
+
cot
2
(
θ
)
is an
identity
⎡
⎢
⎣
x
2
1
2
√
π
∫
x
d
x
⎤
⎥
⎦
[
x
2
1
2
π
∫
x
d
x
]
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