Trigonometry Examples

$(- 1, \sqrt{3})$

Step 1

To find the $\sec (θ)$ between the x-axis and the line between the points $(0, 0)$ and $(- 1, \sqrt{3})$ , draw the triangle between the three points $(0, 0)$ , $(- 1, 0)$ , and $(- 1, \sqrt{3})$ .

Opposite : $\sqrt{3}$

Adjacent : $- 1$

Step 2

Find the hypotenuse using Pythagorean theorem $c = \sqrt{a^{2} + b^{2}}$ .

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Step 2.1

Raise $- 1$ to the power of $2$ .

$\sqrt{1 + {(\sqrt{3})}^{2}}$

Step 2.2

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

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Step 2.2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\sqrt{1 + {(3^{\frac{1}{2}})}^{2}}$

Step 2.2.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\sqrt{1 + 3^{\frac{1}{2} \cdot 2}}$

Step 2.2.3

Combine $\frac{1}{2}$ and $2$ .

$\sqrt{1 + 3^{\frac{2}{2}}}$

Step 2.2.4

Cancel the common factor of $2$ .

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Step 2.2.4.1

Cancel the common factor.

$\sqrt{1 + 3^{\frac{2}{2}}}$

Step 2.2.4.2

Rewrite the expression.

$\sqrt{1 + 3^{1}}$

Step 2.2.5

Evaluate the exponent.

$\sqrt{1 + 3}$

Step 2.3

Simplify the expression.

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Step 2.3.1

Add $1$ and $3$ .

$\sqrt{4}$

Step 2.3.2

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2}}$

Step 2.4

Pull terms out from under the radical, assuming positive real numbers.

$2$

Step 3

$\sec (θ) = \frac{Hypotenuse}{Adjacent}$ therefore $\sec (θ) = \frac{2}{- 1}$ .

$\frac{2}{- 1}$

Step 4

Divide $2$ by $- 1$ .

$\sec (θ) = - 2$