Trigonometry Examples

$\sin (θ) = \frac{2 \sqrt{5}}{5}$

Step 1

Use the definition of sine to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values.

$\sin (θ) = \frac{opposite}{hypotenuse}$

Step 2

Find the adjacent side of the unit circle triangle. Since the hypotenuse and opposite sides are known, use the Pythagorean theorem to find the remaining side.

$Adjacent = - \sqrt{{hypotenuse}^{2} - {opposite}^{2}}$

Step 3

Replace the known values in the equation.

$Adjacent = - \sqrt{{(5)}^{2} - {(2 \sqrt{5})}^{2}}$

Step 4

Simplify inside the radical.

Tap for more steps...

Step 4.1

Negate $\sqrt{{(5)}^{2} - {(2 \sqrt{5})}^{2}}$ .

Adjacent $= - \sqrt{{(5)}^{2} - {(2 \sqrt{5})}^{2}}$

Step 4.2

Raise $5$ to the power of $2$ .

Adjacent $= - \sqrt{25 - {(2 \sqrt{5})}^{2}}$

Step 4.3

Apply the product rule to $2 \sqrt{5}$ .

Adjacent $= - \sqrt{25 - (2^{2} {\sqrt{5}}^{2})}$

Step 4.4

Raise $2$ to the power of $2$ .

Adjacent $= - \sqrt{25 - (4 {\sqrt{5}}^{2})}$

Step 4.5

Rewrite ${\sqrt{5}}^{2}$ as $5$ .

Tap for more steps...

Step 4.5.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{5}$ as $5^{\frac{1}{2}}$ .

Adjacent $= - \sqrt{25 - (4 {(5^{\frac{1}{2}})}^{2})}$

Step 4.5.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

Adjacent $= - \sqrt{25 - (4 \cdot 5^{\frac{1}{2} \cdot 2})}$

Step 4.5.3

Combine $\frac{1}{2}$ and $2$ .

Adjacent $= - \sqrt{25 - (4 \cdot 5^{\frac{2}{2}})}$

Step 4.5.4

Cancel the common factor of $2$ .

Tap for more steps...

Step 4.5.4.1

Cancel the common factor.

Adjacent $= - \sqrt{25 - (4 \cdot 5^{\frac{2}{2}})}$

Step 4.5.4.2

Rewrite the expression.

Adjacent $= - \sqrt{25 - (4 \cdot 5)}$

Step 4.5.5

Evaluate the exponent.

Adjacent $= - \sqrt{25 - (4 \cdot 5)}$

Step 4.6

Multiply $- (4 \cdot 5)$ .

Tap for more steps...

Step 4.6.1

Multiply $4$ by $5$ .

Adjacent $= - \sqrt{25 - 1 \cdot 20}$

Step 4.6.2

Multiply $- 1$ by $20$ .

Adjacent $= - \sqrt{25 - 20}$

Step 4.7

Subtract $20$ from $25$ .

Adjacent $= - \sqrt{5}$

Step 5

Find the value of cosine.

Tap for more steps...

Step 5.1

Use the definition of cosine to find the value of $\cos (θ)$ .

$\cos (θ) = \frac{adj}{hyp}$

Step 5.2

Substitute in the known values.

$\cos (θ) = \frac{- \sqrt{5}}{5}$

Step 5.3

Move the negative in front of the fraction.

$\cos (θ) = - \frac{\sqrt{5}}{5}$

Step 6

Find the value of tangent.

Tap for more steps...

Step 6.1

Use the definition of tangent to find the value of $\tan (θ)$ .

$\tan (θ) = \frac{opp}{adj}$

Step 6.2

Substitute in the known values.

$\tan (θ) = \frac{2 \sqrt{5}}{- \sqrt{5}}$

Step 6.3

Simplify the value of $\tan (θ)$ .

Tap for more steps...

Step 6.3.1

Cancel the common factor of $\sqrt{5}$ .

Tap for more steps...

Step 6.3.1.1

Cancel the common factor.

$\tan (θ) = \frac{2 \sqrt{5}}{- \sqrt{5}}$

Step 6.3.1.2

Rewrite the expression.

$\tan (θ) = \frac{2}{- 1}$

Step 6.3.1.3

Move the negative one from the denominator of $\frac{2}{- 1}$ .

$\tan (θ) = - 1 \cdot 2$

Step 6.3.2

Multiply $- 1$ by $2$ .

$\tan (θ) = - 2$

Step 7

Find the value of cotangent.

Tap for more steps...

Step 7.1

Use the definition of cotangent to find the value of $\cot (θ)$ .

$\cot (θ) = \frac{adj}{opp}$

Step 7.2

Substitute in the known values.

$\cot (θ) = \frac{- \sqrt{5}}{2 \sqrt{5}}$

Step 7.3

Simplify the value of $\cot (θ)$ .

Tap for more steps...

Step 7.3.1

Cancel the common factor of $\sqrt{5}$ .

Tap for more steps...

Step 7.3.1.1

Cancel the common factor.

$\cot (θ) = \frac{- \sqrt{5}}{2 \sqrt{5}}$

Step 7.3.1.2

Rewrite the expression.

$\cot (θ) = \frac{- 1}{2}$

Step 7.3.2

Move the negative in front of the fraction.

$\cot (θ) = - \frac{1}{2}$

Step 8

Find the value of secant.

Tap for more steps...

Step 8.1

Use the definition of secant to find the value of $\sec (θ)$ .

$\sec (θ) = \frac{hyp}{adj}$

Step 8.2

Substitute in the known values.

$\sec (θ) = \frac{5}{- \sqrt{5}}$

Step 8.3

Simplify the value of $\sec (θ)$ .

Tap for more steps...

Step 8.3.1

Move the negative in front of the fraction.

$\sec (θ) = - \frac{5}{\sqrt{5}}$

Step 8.3.2

Multiply $\frac{5}{\sqrt{5}}$ by $\frac{\sqrt{5}}{\sqrt{5}}$ .

$\sec (θ) = - (\frac{5}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}})$

Step 8.3.3

Combine and simplify the denominator.

Tap for more steps...

Step 8.3.3.1

Multiply $\frac{5}{\sqrt{5}}$ by $\frac{\sqrt{5}}{\sqrt{5}}$ .

$\sec (θ) = - \frac{5 \sqrt{5}}{\sqrt{5} \sqrt{5}}$

Step 8.3.3.2

Raise $\sqrt{5}$ to the power of $1$ .

$\sec (θ) = - \frac{5 \sqrt{5}}{\sqrt{5} \sqrt{5}}$

Step 8.3.3.3

Raise $\sqrt{5}$ to the power of $1$ .

$\sec (θ) = - \frac{5 \sqrt{5}}{\sqrt{5} \sqrt{5}}$

Step 8.3.3.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\sec (θ) = - \frac{5 \sqrt{5}}{{\sqrt{5}}^{1 + 1}}$

Step 8.3.3.5

Add $1$ and $1$ .

$\sec (θ) = - \frac{5 \sqrt{5}}{{\sqrt{5}}^{2}}$

Step 8.3.3.6

Rewrite ${\sqrt{5}}^{2}$ as $5$ .

Tap for more steps...

Step 8.3.3.6.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{5}$ as $5^{\frac{1}{2}}$ .

$\sec (θ) = - \frac{5 \sqrt{5}}{{(5^{\frac{1}{2}})}^{2}}$

Step 8.3.3.6.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\sec (θ) = - \frac{5 \sqrt{5}}{5^{\frac{1}{2} \cdot 2}}$

Step 8.3.3.6.3

Combine $\frac{1}{2}$ and $2$ .

$\sec (θ) = - \frac{5 \sqrt{5}}{5^{\frac{2}{2}}}$

Step 8.3.3.6.4

Cancel the common factor of $2$ .

Tap for more steps...

Step 8.3.3.6.4.1

Cancel the common factor.

$\sec (θ) = - \frac{5 \sqrt{5}}{5^{\frac{2}{2}}}$

Step 8.3.3.6.4.2

Rewrite the expression.

$\sec (θ) = - \frac{5 \sqrt{5}}{5}$

Step 8.3.3.6.5

Evaluate the exponent.

$\sec (θ) = - \frac{5 \sqrt{5}}{5}$

Step 8.3.4

Cancel the common factor of $5$ .

Tap for more steps...

Step 8.3.4.1

Cancel the common factor.

$\sec (θ) = - \frac{5 \sqrt{5}}{5}$

Step 8.3.4.2

Divide $\sqrt{5}$ by $1$ .

$\sec (θ) = - \sqrt{5}$

Step 9

Find the value of cosecant.

Tap for more steps...

Step 9.1

Use the definition of cosecant to find the value of $\csc (θ)$ .

$\csc (θ) = \frac{hyp}{opp}$

Step 9.2

Substitute in the known values.

$\csc (θ) = \frac{5}{2 \sqrt{5}}$

Step 9.3

Simplify the value of $\csc (θ)$ .

Tap for more steps...

Step 9.3.1

Multiply $\frac{5}{2 \sqrt{5}}$ by $\frac{\sqrt{5}}{\sqrt{5}}$ .

$\csc (θ) = \frac{5}{2 \sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}$

Step 9.3.2

Combine and simplify the denominator.

Tap for more steps...

Step 9.3.2.1

Multiply $\frac{5}{2 \sqrt{5}}$ by $\frac{\sqrt{5}}{\sqrt{5}}$ .

$\csc (θ) = \frac{5 \sqrt{5}}{2 \sqrt{5} \sqrt{5}}$

Step 9.3.2.2

Move $\sqrt{5}$ .

$\csc (θ) = \frac{5 \sqrt{5}}{2 (\sqrt{5} \sqrt{5})}$

Step 9.3.2.3

Raise $\sqrt{5}$ to the power of $1$ .

$\csc (θ) = \frac{5 \sqrt{5}}{2 (\sqrt{5} \sqrt{5})}$

Step 9.3.2.4

Raise $\sqrt{5}$ to the power of $1$ .

$\csc (θ) = \frac{5 \sqrt{5}}{2 (\sqrt{5} \sqrt{5})}$

Step 9.3.2.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\csc (θ) = \frac{5 \sqrt{5}}{2 {\sqrt{5}}^{1 + 1}}$

Step 9.3.2.6

Add $1$ and $1$ .

$\csc (θ) = \frac{5 \sqrt{5}}{2 {\sqrt{5}}^{2}}$

Step 9.3.2.7

Rewrite ${\sqrt{5}}^{2}$ as $5$ .

Tap for more steps...

Step 9.3.2.7.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{5}$ as $5^{\frac{1}{2}}$ .

$\csc (θ) = \frac{5 \sqrt{5}}{2 {(5^{\frac{1}{2}})}^{2}}$

Step 9.3.2.7.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\csc (θ) = \frac{5 \sqrt{5}}{2 \cdot 5^{\frac{1}{2} \cdot 2}}$

Step 9.3.2.7.3

Combine $\frac{1}{2}$ and $2$ .

$\csc (θ) = \frac{5 \sqrt{5}}{2 \cdot 5^{\frac{2}{2}}}$

Step 9.3.2.7.4

Cancel the common factor of $2$ .

Tap for more steps...

Step 9.3.2.7.4.1

Cancel the common factor.

$\csc (θ) = \frac{5 \sqrt{5}}{2 \cdot 5^{\frac{2}{2}}}$

Step 9.3.2.7.4.2

Rewrite the expression.

$\csc (θ) = \frac{5 \sqrt{5}}{2 \cdot 5}$

Step 9.3.2.7.5

Evaluate the exponent.

$\csc (θ) = \frac{5 \sqrt{5}}{2 \cdot 5}$

Step 9.3.3

Cancel the common factor of $5$ .

Tap for more steps...

Step 9.3.3.1

Cancel the common factor.

$\csc (θ) = \frac{5 \sqrt{5}}{2 \cdot 5}$

Step 9.3.3.2

Rewrite the expression.

$\csc (θ) = \frac{\sqrt{5}}{2}$

Step 10

This is the solution to each trig value.

$\sin (θ) = \frac{2 \sqrt{5}}{5}$

$\cos (θ) = - \frac{\sqrt{5}}{5}$

$\tan (θ) = - 2$

$\cot (θ) = - \frac{1}{2}$

$\sec (θ) = - \sqrt{5}$

$\csc (θ) = \frac{\sqrt{5}}{2}$