Statistics Examples

$\begin{array}{c} Class & Frequency \\ 360 - 369 & 2 \\ 370 - 379 & 3 \\ 380 - 389 & 5 \\ 390 - 399 & 7 \\ 400 - 409 & 5 \\ 410 - 419 & 4 \\ 420 - 429 & 4 \\ 430 - 439 & 1 \end{array}$

Step 1

Find the midpoint $M$ for each class.

$\begin{array}{c} Class & Frequency (f) & Midpoint (M) \\ 360 - 369 & 2 & 364.5 \\ 370 - 379 & 3 & 374.5 \\ 380 - 389 & 5 & 384.5 \\ 390 - 399 & 7 & 394.5 \\ 400 - 409 & 5 & 404.5 \\ 410 - 419 & 4 & 414.5 \\ 420 - 429 & 4 & 424.5 \\ 430 - 439 & 1 & 434.5 \end{array}$

Step 2

Multiply the frequency of each class by the class midpoint.

$\begin{array}{c} Class & Frequency (f) & Midpoint (M) & f \cdot M \\ 360 - 369 & 2 & 364.5 & 2 \cdot 364.5 \\ 370 - 379 & 3 & 374.5 & 3 \cdot 374.5 \\ 380 - 389 & 5 & 384.5 & 5 \cdot 384.5 \\ 390 - 399 & 7 & 394.5 & 7 \cdot 394.5 \\ 400 - 409 & 5 & 404.5 & 5 \cdot 404.5 \\ 410 - 419 & 4 & 414.5 & 4 \cdot 414.5 \\ 420 - 429 & 4 & 424.5 & 4 \cdot 424.5 \\ 430 - 439 & 1 & 434.5 & 1 \cdot 434.5 \end{array}$

Step 3

Simplify the $f \cdot M$ column.

$\begin{array}{c} Class & Frequency (f) & Midpoint (M) & f \cdot M \\ 360 - 369 & 2 & 364.5 & 729 \\ 370 - 379 & 3 & 374.5 & 1123.5 \\ 380 - 389 & 5 & 384.5 & 1922.5 \\ 390 - 399 & 7 & 394.5 & 2761.5 \\ 400 - 409 & 5 & 404.5 & 2022.5 \\ 410 - 419 & 4 & 414.5 & 1658 \\ 420 - 429 & 4 & 424.5 & 1698 \\ 430 - 439 & 1 & 434.5 & 434.5 \end{array}$

Step 4

Add the values in the $f \cdot M$ column.

$729 + 1123.5 + 1922.5 + 2761.5 + 2022.5 + 1658 + 1698 + 434.5 = 12349.5$

Step 5

Add the values in the frequency column.

$n = 2 + 3 + 5 + 7 + 5 + 4 + 4 + 1 = 31$

Step 6

The mean (mu) is the sum of $f \cdot M$ divided by $n$ , which is the sum of frequencies.

$μ = \frac{\sum_{}^{} f \cdot M}{\sum_{}^{} f}$

Step 7

The mean is the sum of the product of the midpoints and frequencies divided by the total of frequencies.

$μ = \frac{12349.5}{31}$

Step 8

Simplify the right side of $μ = \frac{12349.5}{31}$ .

$398.37096774$