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Statistics Examples
ClassFrequency360−3692370−3793380−3895390−3997400−4095410−4194420−4294430−4391
Step 1
Find the midpoint M for each class.
ClassFrequency(f)Midpoint(M)360−3692364.5370−3793374.5380−3895384.5390−3997394.5400−4095404.5410−4194414.5420−4294424.5430−4391434.5
Step 2
Multiply the frequency of each class by the class midpoint.
ClassFrequency(f)Midpoint(M)f⋅M360−3692364.52⋅364.5370−3793374.53⋅374.5380−3895384.55⋅384.5390−3997394.57⋅394.5400−4095404.55⋅404.5410−4194414.54⋅414.5420−4294424.54⋅424.5430−4391434.51⋅434.5
Step 3
Simplify the f⋅M column.
ClassFrequency(f)Midpoint(M)f⋅M360−3692364.5729370−3793374.51123.5380−3895384.51922.5390−3997394.52761.5400−4095404.52022.5410−4194414.51658420−4294424.51698430−4391434.5434.5
Step 4
Add the values in the f⋅M column.
729+1123.5+1922.5+2761.5+2022.5+1658+1698+434.5=12349.5
Step 5
Add the values in the frequency column.
n=2+3+5+7+5+4+4+1=31
Step 6
The mean (mu) is the sum of f⋅M divided by n, which is the sum of frequencies.
μ=∑f⋅M∑f
Step 7
The mean is the sum of the product of the midpoints and frequencies divided by the total of frequencies.
μ=12349.531
Step 8
Simplify the right side of μ=12349.531.
398.37096774