Precalculus Examples

$\frac{x - 1}{x^{2} {(x - 2)}^{3}}$

Step 1

Decompose the fraction and multiply through by the common denominator.

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Step 1.1

For each factor in the denominator, create a new fraction using the factor as the denominator, and an unknown value as the numerator. Since the factor in the denominator is linear, put a single variable in its place $C$ .

$\frac{A}{x^{2}} + \frac{B}{x} + \frac{C}{{(x - 2)}^{3}}$

Step 1.2

$\frac{A}{x^{2}} + \frac{B}{x} + \frac{C}{{(x - 2)}^{3}} + \frac{D}{{(x - 2)}^{2}}$

Step 1.3

$\frac{A}{x^{2}} + \frac{B}{x} + \frac{C}{{(x - 2)}^{3}} + \frac{D}{{(x - 2)}^{2}} + \frac{F}{x - 2}$

Step 1.4

Multiply each fraction in the equation by the denominator of the original expression. In this case, the denominator is $x^{2} {(x - 2)}^{3}$ .

$\frac{(x - 1) (x^{2} {(x - 2)}^{3})}{x^{2} {(x - 2)}^{3}} = \frac{A (x^{2} {(x - 2)}^{3})}{x^{2}} + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.5

Cancel the common factor of $x^{2}$ .

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Step 1.5.1

Cancel the common factor.

Step 1.5.2

Rewrite the expression.

$\frac{(x - 1) ({(x - 2)}^{3})}{{(x - 2)}^{3}} = \frac{A (x^{2} {(x - 2)}^{3})}{x^{2}} + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.6

Cancel the common factor of ${(x - 2)}^{3}$ .

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Step 1.6.1

Cancel the common factor.

$\frac{(x - 1) {(x - 2)}^{3}}{{(x - 2)}^{3}} = \frac{A (x^{2} {(x - 2)}^{3})}{x^{2}} + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.6.2

Divide $x - 1$ by $1$ .

$x - 1 = \frac{A (x^{2} {(x - 2)}^{3})}{x^{2}} + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7

Simplify each term.

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Step 1.7.1

Cancel the common factor of $x^{2}$ .

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Step 1.7.1.1

Cancel the common factor.

Step 1.7.1.2

Divide $A ({(x - 2)}^{3})$ by $1$ .

$x - 1 = A ({(x - 2)}^{3}) + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.2

Use the Binomial Theorem.

$x - 1 = A (x^{3} + 3 x^{2} \cdot - 2 + 3 x {(- 2)}^{2} + {(- 2)}^{3}) + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.3

Simplify each term.

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Step 1.7.3.1

Multiply $- 2$ by $3$ .

$x - 1 = A (x^{3} - 6 x^{2} + 3 x {(- 2)}^{2} + {(- 2)}^{3}) + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.3.2

Raise $- 2$ to the power of $2$ .

$x - 1 = A (x^{3} - 6 x^{2} + 3 x \cdot 4 + {(- 2)}^{3}) + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.3.3

Multiply $4$ by $3$ .

$x - 1 = A (x^{3} - 6 x^{2} + 12 x + {(- 2)}^{3}) + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.3.4

Raise $- 2$ to the power of $3$ .

$x - 1 = A (x^{3} - 6 x^{2} + 12 x - 8) + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.4

Apply the distributive property.

$x - 1 = A x^{3} + A (- 6 x^{2}) + A (12 x) + A \cdot - 8 + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.5

Simplify.

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Step 1.7.5.1

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + A (12 x) + A \cdot - 8 + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.5.2

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x + A \cdot - 8 + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.5.3

Move $- 8$ to the left of $A$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 \cdot A + \frac{B (x^{2} {(x - 2)}^{3})}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.6

Cancel the common factor of $x^{2}$ and $x$ .

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Step 1.7.6.1

Factor $x$ out of $B (x^{2} {(x - 2)}^{3})$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + \frac{x (B (x {(x - 2)}^{3}))}{x} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.6.2

Cancel the common factors.

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Step 1.7.6.2.1

Raise $x$ to the power of $1$ .

Step 1.7.6.2.2

Factor $x$ out of $x^{1}$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + \frac{x (B (x {(x - 2)}^{3}))}{x \cdot 1} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.6.2.3

Cancel the common factor.

Step 1.7.6.2.4

Rewrite the expression.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + \frac{B (x {(x - 2)}^{3})}{1} + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.6.2.5

Divide $B (x {(x - 2)}^{3})$ by $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x {(x - 2)}^{3}) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.7

Use the Binomial Theorem.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x (x^{3} + 3 x^{2} \cdot - 2 + 3 x {(- 2)}^{2} + {(- 2)}^{3})) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.8

Simplify each term.

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Step 1.7.8.1

Multiply $- 2$ by $3$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x (x^{3} - 6 x^{2} + 3 x {(- 2)}^{2} + {(- 2)}^{3})) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.8.2

Raise $- 2$ to the power of $2$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x (x^{3} - 6 x^{2} + 3 x \cdot 4 + {(- 2)}^{3})) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.8.3

Multiply $4$ by $3$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x (x^{3} - 6 x^{2} + 12 x + {(- 2)}^{3})) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.8.4

Raise $- 2$ to the power of $3$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x (x^{3} - 6 x^{2} + 12 x - 8)) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.9

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x \cdot x^{3} + x (- 6 x^{2}) + x (12 x) + x \cdot - 8) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.10

Simplify.

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Step 1.7.10.1

Multiply $x$ by $x^{3}$ by adding the exponents.

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Step 1.7.10.1.1

Multiply $x$ by $x^{3}$ .

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Step 1.7.10.1.1.1

Raise $x$ to the power of $1$ .

Step 1.7.10.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{1 + 3} + x (- 6 x^{2}) + x (12 x) + x \cdot - 8) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.10.1.2

Add $1$ and $3$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} + x (- 6 x^{2}) + x (12 x) + x \cdot - 8) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.10.2

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 x \cdot x^{2} + x (12 x) + x \cdot - 8) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.10.3

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 x \cdot x^{2} + 12 x \cdot x + x \cdot - 8) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.10.4

Move $- 8$ to the left of $x$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 x \cdot x^{2} + 12 x \cdot x - 8 \cdot x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.11

Simplify each term.

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Step 1.7.11.1

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 1.7.11.1.1

Move $x^{2}$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 (x^{2} x) + 12 x \cdot x - 8 \cdot x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.11.1.2

Multiply $x^{2}$ by $x$ .

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Step 1.7.11.1.2.1

Raise $x$ to the power of $1$ .

Step 1.7.11.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 x^{2 + 1} + 12 x \cdot x - 8 \cdot x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.11.1.3

Add $2$ and $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 x^{3} + 12 x \cdot x - 8 \cdot x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.11.2

Multiply $x$ by $x$ by adding the exponents.

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Step 1.7.11.2.1

Move $x$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 x^{3} + 12 (x \cdot x) - 8 \cdot x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.11.2.2

Multiply $x$ by $x$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 x^{3} + 12 x^{2} - 8 \cdot x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B (x^{4} - 6 x^{3} + 12 x^{2} - 8 x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.12

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} + B (- 6 x^{3}) + B (12 x^{2}) + B (- 8 x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.13

Simplify.

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Step 1.7.13.1

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + B (12 x^{2}) + B (- 8 x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.13.2

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} + B (- 8 x) + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.13.3

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + \frac{(C) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.14

Cancel the common factor of ${(x - 2)}^{3}$ .

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Step 1.7.14.1

Cancel the common factor.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + \frac{C (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{3}} + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.14.2

Divide $(C) (x^{2})$ by $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + (C) (x^{2}) + \frac{(D) (x^{2} {(x - 2)}^{3})}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.15

Cancel the common factor of ${(x - 2)}^{3}$ and ${(x - 2)}^{2}$ .

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Step 1.7.15.1

Factor ${(x - 2)}^{2}$ out of $(D) (x^{2} {(x - 2)}^{3})$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + \frac{{(x - 2)}^{2} (D (x^{2} (x - 2)))}{{(x - 2)}^{2}} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.15.2

Cancel the common factors.

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Step 1.7.15.2.1

Multiply by $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + \frac{{(x - 2)}^{2} (D (x^{2} (x - 2)))}{{(x - 2)}^{2} \cdot 1} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.15.2.2

Cancel the common factor.

Step 1.7.15.2.3

Rewrite the expression.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + \frac{D (x^{2} (x - 2))}{1} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.15.2.4

Divide $D (x^{2} (x - 2))$ by $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D (x^{2} (x - 2)) + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.16

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D (x^{2} x + x^{2} \cdot - 2) + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.17

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 1.7.17.1

Multiply $x^{2}$ by $x$ .

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Step 1.7.17.1.1

Raise $x$ to the power of $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D (x^{2} x + x^{2} \cdot - 2) + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.17.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D (x^{2 + 1} + x^{2} \cdot - 2) + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.17.2

Add $2$ and $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D (x^{3} + x^{2} \cdot - 2) + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.18

Move $- 2$ to the left of $x^{2}$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D (x^{3} - 2 \cdot x^{2}) + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.19

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} + D (- 2 x^{2}) + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.20

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + \frac{(F) (x^{2} {(x - 2)}^{3})}{x - 2}$

Step 1.7.21

Cancel the common factor of ${(x - 2)}^{3}$ and $x - 2$ .

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Step 1.7.21.1

Factor $x - 2$ out of $(F) (x^{2} {(x - 2)}^{3})$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + \frac{(x - 2) (F (x^{2} {(x - 2)}^{2}))}{x - 2}$

Step 1.7.21.2

Cancel the common factors.

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Step 1.7.21.2.1

Multiply by $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + \frac{(x - 2) (F (x^{2} {(x - 2)}^{2}))}{(x - 2) \cdot 1}$

Step 1.7.21.2.2

Cancel the common factor.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + \frac{(x - 2) (F (x^{2} {(x - 2)}^{2}))}{(x - 2) \cdot 1}$

Step 1.7.21.2.3

Rewrite the expression.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + \frac{F (x^{2} {(x - 2)}^{2})}{1}$

Step 1.7.21.2.4

Divide $F (x^{2} {(x - 2)}^{2})$ by $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} {(x - 2)}^{2})$

Step 1.7.22

Rewrite ${(x - 2)}^{2}$ as $(x - 2) (x - 2)$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} ((x - 2) (x - 2)))$

Step 1.7.23

Expand $(x - 2) (x - 2)$ using the FOIL Method.

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Step 1.7.23.1

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} (x (x - 2) - 2 (x - 2)))$

Step 1.7.23.2

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} (x \cdot x + x \cdot - 2 - 2 (x - 2)))$

Step 1.7.23.3

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} (x \cdot x + x \cdot - 2 - 2 x - 2 \cdot - 2))$

Step 1.7.24

Simplify and combine like terms.

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Step 1.7.24.1

Simplify each term.

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Step 1.7.24.1.1

Multiply $x$ by $x$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} (x^{2} + x \cdot - 2 - 2 x - 2 \cdot - 2))$

Step 1.7.24.1.2

Move $- 2$ to the left of $x$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} (x^{2} - 2 \cdot x - 2 x - 2 \cdot - 2))$

Step 1.7.24.1.3

Multiply $- 2$ by $- 2$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} (x^{2} - 2 x - 2 x + 4))$

Step 1.7.24.2

Subtract $2 x$ from $- 2 x$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} (x^{2} - 4 x + 4))$

Step 1.7.25

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2} x^{2} + x^{2} (- 4 x) + x^{2} \cdot 4)$

Step 1.7.26

Simplify.

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Step 1.7.26.1

Multiply $x^{2}$ by $x^{2}$ by adding the exponents.

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Step 1.7.26.1.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{2 + 2} + x^{2} (- 4 x) + x^{2} \cdot 4)$

Step 1.7.26.1.2

Add $2$ and $2$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{4} + x^{2} (- 4 x) + x^{2} \cdot 4)$

Step 1.7.26.2

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{4} - 4 x^{2} x + x^{2} \cdot 4)$

Step 1.7.26.3

Move $4$ to the left of $x^{2}$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{4} - 4 x^{2} x + 4 \cdot x^{2})$

Step 1.7.27

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 1.7.27.1

Move $x$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{4} - 4 (x \cdot x^{2}) + 4 \cdot x^{2})$

Step 1.7.27.2

Multiply $x$ by $x^{2}$ .

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Step 1.7.27.2.1

Raise $x$ to the power of $1$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{4} - 4 (x \cdot x^{2}) + 4 \cdot x^{2})$

Step 1.7.27.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{4} - 4 x^{1 + 2} + 4 \cdot x^{2})$

Step 1.7.27.3

Add $1$ and $2$ .

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{4} - 4 x^{3} + 4 \cdot x^{2})$

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F (x^{4} - 4 x^{3} + 4 x^{2})$

Step 1.7.28

Apply the distributive property.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} + F (- 4 x^{3}) + F (4 x^{2})$

Step 1.7.29

Simplify.

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Step 1.7.29.1

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + F (4 x^{2})$

Step 1.7.29.2

Rewrite using the commutative property of multiplication.

$x - 1 = A x^{3} - 6 A x^{2} + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + 4 F x^{2}$

Step 1.8

Simplify the expression.

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Step 1.8.1

Move $A$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 A x - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + 4 F x^{2}$

Step 1.8.2

Move $A$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + 4 F x^{2}$

Step 1.8.3

Reorder $B$ and $x^{4}$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A - 8 A + B x^{4} - 6 B x^{3} + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + 4 F x^{2}$

Step 1.8.4

Move $B$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A - 8 A + B x^{4} - 6 x^{3} B + 12 B x^{2} - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + 4 F x^{2}$

Step 1.8.5

Move $B$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A - 8 A + B x^{4} - 6 x^{3} B + 12 x^{2} B - 8 B x + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + 4 F x^{2}$

Step 1.8.6

Move $B$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A - 8 A + B x^{4} - 6 x^{3} B + 12 x^{2} B - 8 x B + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + 4 F x^{2}$

Step 1.8.7

Reorder $F$ and $x^{4}$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A - 8 A + B x^{4} - 6 x^{3} B + 12 x^{2} B - 8 x B + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 F x^{3} + 4 F x^{2}$

Step 1.8.8

Move $F$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A - 8 A + B x^{4} - 6 x^{3} B + 12 x^{2} B - 8 x B + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 x^{3} F + 4 F x^{2}$

Step 1.8.9

Move $F$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A - 8 A + B x^{4} - 6 x^{3} B + 12 x^{2} B - 8 x B + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 x^{3} F + 4 x^{2} F$

Step 1.8.10

Move $- 8 A$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A + B x^{4} - 6 x^{3} B + 12 x^{2} B - 8 x B + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 x^{3} F + 4 x^{2} F - 8 A$

Step 1.8.11

Move $- 8 x B$ .

$x - 1 = A x^{3} - 6 x^{2} A + 12 x A + B x^{4} - 6 x^{3} B + 12 x^{2} B + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 x^{3} F + 4 x^{2} F - 8 x B - 8 A$

Step 1.8.12

Move $12 x A$ .

$x - 1 = A x^{3} - 6 x^{2} A + B x^{4} - 6 x^{3} B + 12 x^{2} B + C x^{2} + D x^{3} - 2 D x^{2} + F x^{4} - 4 x^{3} F + 4 x^{2} F + 12 x A - 8 x B - 8 A$

Step 1.8.13

Move $- 2 D x^{2}$ .

$x - 1 = A x^{3} - 6 x^{2} A + B x^{4} - 6 x^{3} B + 12 x^{2} B + C x^{2} + D x^{3} + F x^{4} - 4 x^{3} F - 2 D x^{2} + 4 x^{2} F + 12 x A - 8 x B - 8 A$

Step 1.8.14

Move $C x^{2}$ .

$x - 1 = A x^{3} - 6 x^{2} A + B x^{4} - 6 x^{3} B + 12 x^{2} B + D x^{3} + F x^{4} - 4 x^{3} F + C x^{2} - 2 D x^{2} + 4 x^{2} F + 12 x A - 8 x B - 8 A$

Step 1.8.15

Move $12 x^{2} B$ .

$x - 1 = A x^{3} - 6 x^{2} A + B x^{4} - 6 x^{3} B + D x^{3} + F x^{4} - 4 x^{3} F + 12 x^{2} B + C x^{2} - 2 D x^{2} + 4 x^{2} F + 12 x A - 8 x B - 8 A$

Step 1.8.16

Move $- 6 x^{2} A$ .

$x - 1 = A x^{3} + B x^{4} - 6 x^{3} B + D x^{3} + F x^{4} - 4 x^{3} F - 6 x^{2} A + 12 x^{2} B + C x^{2} - 2 D x^{2} + 4 x^{2} F + 12 x A - 8 x B - 8 A$

Step 1.8.17

Move $D x^{3}$ .

$x - 1 = A x^{3} + B x^{4} - 6 x^{3} B + F x^{4} + D x^{3} - 4 x^{3} F - 6 x^{2} A + 12 x^{2} B + C x^{2} - 2 D x^{2} + 4 x^{2} F + 12 x A - 8 x B - 8 A$

Step 1.8.18

Move $- 6 x^{3} B$ .

$x - 1 = A x^{3} + B x^{4} + F x^{4} - 6 x^{3} B + D x^{3} - 4 x^{3} F - 6 x^{2} A + 12 x^{2} B + C x^{2} - 2 D x^{2} + 4 x^{2} F + 12 x A - 8 x B - 8 A$

Step 1.8.19

Move $A x^{3}$ .

$x - 1 = B x^{4} + F x^{4} + A x^{3} - 6 x^{3} B + D x^{3} - 4 x^{3} F - 6 x^{2} A + 12 x^{2} B + C x^{2} - 2 D x^{2} + 4 x^{2} F + 12 x A - 8 x B - 8 A$

Step 2

Create equations for the partial fraction variables and use them to set up a system of equations.

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Step 2.1

Create an equation for the partial fraction variables by equating the coefficients of $x^{4}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = B + F$

Step 2.2

Create an equation for the partial fraction variables by equating the coefficients of $x^{3}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = A - 6 B + D - 4 F$

Step 2.3

Create an equation for the partial fraction variables by equating the coefficients of $x^{2}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = - 6 A + 12 B + C - 2 D + 4 F$

Step 2.4

Create an equation for the partial fraction variables by equating the coefficients of $x$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$1 = 12 A - 8 B$

Step 2.5

Create an equation for the partial fraction variables by equating the coefficients of the terms not containing $x$ . For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$- 1 = - 8 A$

Step 2.6

Set up the system of equations to find the coefficients of the partial fractions.

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

$- 1 = - 8 A$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

$- 1 = - 8 A$

Step 3

Solve the system of equations.

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Step 3.1

Solve for $A$ in $- 1 = - 8 A$ .

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Step 3.1.1

Rewrite the equation as $- 8 A = - 1$ .

$- 8 A = - 1$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

Step 3.1.2

Divide each term in $- 8 A = - 1$ by $- 8$ and simplify.

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Step 3.1.2.1

Divide each term in $- 8 A = - 1$ by $- 8$ .

$\frac{- 8 A}{- 8} = \frac{- 1}{- 8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

Step 3.1.2.2

Simplify the left side.

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Step 3.1.2.2.1

Cancel the common factor of $- 8$ .

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Step 3.1.2.2.1.1

Cancel the common factor.

$\frac{- 8 A}{- 8} = \frac{- 1}{- 8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

Step 3.1.2.2.1.2

Divide $A$ by $1$ .

$A = \frac{- 1}{- 8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

$A = \frac{- 1}{- 8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

$A = \frac{- 1}{- 8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

Step 3.1.2.3

Simplify the right side.

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Step 3.1.2.3.1

Dividing two negative values results in a positive value.

$A = \frac{1}{8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

$A = \frac{1}{8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

$A = \frac{1}{8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

$A = \frac{1}{8}$

$0 = B + F$

$0 = A - 6 B + D - 4 F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

Step 3.2

Replace all occurrences of $A$ with $\frac{1}{8}$ in each equation.

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Step 3.2.1

Replace all occurrences of $A$ in $0 = A - 6 B + D - 4 F$ with $\frac{1}{8}$ .

$0 = (\frac{1}{8}) - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Remove parentheses.

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$0 = - 6 A + 12 B + C - 2 D + 4 F$

$1 = 12 A - 8 B$

Step 3.2.3

Replace all occurrences of $A$ in $0 = - 6 A + 12 B + C - 2 D + 4 F$ with $\frac{1}{8}$ .

$0 = - 6 (\frac{1}{8}) + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

Step 3.2.4

Simplify the right side.

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Step 3.2.4.1

Simplify each term.

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Step 3.2.4.1.1

Cancel the common factor of $2$ .

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Step 3.2.4.1.1.1

Factor $2$ out of $- 6$ .

$0 = 2 (- 3) (\frac{1}{8}) + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

Step 3.2.4.1.1.2

Factor $2$ out of $8$ .

$0 = 2 \cdot (- 3 \frac{1}{2 \cdot 4}) + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

Step 3.2.4.1.1.3

Cancel the common factor.

$0 = 2 \cdot (- 3 \frac{1}{2 \cdot 4}) + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

Step 3.2.4.1.1.4

Rewrite the expression.

$0 = - 3 (\frac{1}{4}) + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

$0 = - 3 (\frac{1}{4}) + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

Step 3.2.4.1.2

Combine $- 3$ and $\frac{1}{4}$ .

$0 = \frac{- 3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

Step 3.2.4.1.3

Move the negative in front of the fraction.

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 12 A - 8 B$

Step 3.2.5

Replace all occurrences of $A$ in $1 = 12 A - 8 B$ with $\frac{1}{8}$ .

$1 = 12 (\frac{1}{8}) - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.2.6

Simplify the right side.

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Step 3.2.6.1

Simplify each term.

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Step 3.2.6.1.1

Cancel the common factor of $4$ .

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Step 3.2.6.1.1.1

Factor $4$ out of $12$ .

$1 = 4 (3) (\frac{1}{8}) - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.2.6.1.1.2

Factor $4$ out of $8$ .

$1 = 4 \cdot (3 (\frac{1}{4 \cdot 2})) - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.2.6.1.1.3

Cancel the common factor.

$1 = 4 \cdot (3 (\frac{1}{4 \cdot 2})) - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.2.6.1.1.4

Rewrite the expression.

$1 = 3 (\frac{1}{2}) - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = 3 (\frac{1}{2}) - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.2.6.1.2

Combine $3$ and $\frac{1}{2}$ .

$1 = \frac{3}{2} - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = \frac{3}{2} - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = \frac{3}{2} - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$1 = \frac{3}{2} - 8 B$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3

Solve for $B$ in $1 = \frac{3}{2} - 8 B$ .

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Step 3.3.1

Rewrite the equation as $\frac{3}{2} - 8 B = 1$ .

$\frac{3}{2} - 8 B = 1$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.2

Move all terms not containing $B$ to the right side of the equation.

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Step 3.3.2.1

Subtract $\frac{3}{2}$ from both sides of the equation.

$- 8 B = 1 - \frac{3}{2}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.2.2

Write $1$ as a fraction with a common denominator.

$- 8 B = \frac{2}{2} - \frac{3}{2}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.2.3

Combine the numerators over the common denominator.

$- 8 B = \frac{2 - 3}{2}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.2.4

Subtract $3$ from $2$ .

$- 8 B = \frac{- 1}{2}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.2.5

Move the negative in front of the fraction.

$- 8 B = - \frac{1}{2}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$- 8 B = - \frac{1}{2}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3

Divide each term in $- 8 B = - \frac{1}{2}$ by $- 8$ and simplify.

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Step 3.3.3.1

Divide each term in $- 8 B = - \frac{1}{2}$ by $- 8$ .

$\frac{- 8 B}{- 8} = \frac{- \frac{1}{2}}{- 8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3.2

Simplify the left side.

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Step 3.3.3.2.1

Cancel the common factor of $- 8$ .

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Step 3.3.3.2.1.1

Cancel the common factor.

$\frac{- 8 B}{- 8} = \frac{- \frac{1}{2}}{- 8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3.2.1.2

Divide $B$ by $1$ .

$B = \frac{- \frac{1}{2}}{- 8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$B = \frac{- \frac{1}{2}}{- 8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$B = \frac{- \frac{1}{2}}{- 8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3.3

Simplify the right side.

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Step 3.3.3.3.1

Multiply the numerator by the reciprocal of the denominator.

$B = - \frac{1}{2} \cdot \frac{1}{- 8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3.3.2

Move the negative in front of the fraction.

$B = - \frac{1}{2} \cdot (- \frac{1}{8})$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3.3.3

Multiply $- \frac{1}{2} (- \frac{1}{8})$ .

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Step 3.3.3.3.3.1

Multiply $- 1$ by $- 1$ .

$B = 1 (\frac{1}{2}) \cdot \frac{1}{8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3.3.3.2

Multiply $\frac{1}{2}$ by $1$ .

$B = \frac{1}{2} \cdot \frac{1}{8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3.3.3.3

Multiply $\frac{1}{2}$ by $\frac{1}{8}$ .

$B = \frac{1}{2 \cdot 8}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.3.3.3.3.4

Multiply $2$ by $8$ .

$B = \frac{1}{16}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$B = \frac{1}{16}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$B = \frac{1}{16}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$B = \frac{1}{16}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$B = \frac{1}{16}$

$0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4

Replace all occurrences of $B$ with $\frac{1}{16}$ in each equation.

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Step 3.4.1

Replace all occurrences of $B$ in $0 = - \frac{3}{4} + 12 B + C - 2 D + 4 F$ with $\frac{1}{16}$ .

$0 = - \frac{3}{4} + 12 (\frac{1}{16}) + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.2

Simplify the right side.

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Step 3.4.2.1

Simplify $- \frac{3}{4} + 12 (\frac{1}{16}) + C - 2 D + 4 F$ .

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Step 3.4.2.1.1

Simplify each term.

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Step 3.4.2.1.1.1

Cancel the common factor of $4$ .

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Step 3.4.2.1.1.1.1

Factor $4$ out of $12$ .

$0 = - \frac{3}{4} + 4 (3) (\frac{1}{16}) + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.2.1.1.1.2

Factor $4$ out of $16$ .

$0 = - \frac{3}{4} + 4 \cdot (3 (\frac{1}{4 \cdot 4})) + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.2.1.1.1.3

Cancel the common factor.

$0 = - \frac{3}{4} + 4 \cdot (3 (\frac{1}{4 \cdot 4})) + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.2.1.1.1.4

Rewrite the expression.

$0 = - \frac{3}{4} + 3 (\frac{1}{4}) + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$0 = - \frac{3}{4} + 3 (\frac{1}{4}) + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.2.1.1.2

Combine $3$ and $\frac{1}{4}$ .

$0 = - \frac{3}{4} + \frac{3}{4} + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$0 = - \frac{3}{4} + \frac{3}{4} + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.2.1.2

Simplify by adding terms.

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Step 3.4.2.1.2.1

Add $- \frac{3}{4}$ and $\frac{3}{4}$ .

$0 = 0 + C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.2.1.2.2

Add $0$ and $C$ .

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$0 = \frac{1}{8} - 6 B + D - 4 F$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.3

Replace all occurrences of $B$ in $0 = \frac{1}{8} - 6 B + D - 4 F$ with $\frac{1}{16}$ .

$0 = \frac{1}{8} - 6 (\frac{1}{16}) + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4

Simplify the right side.

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Step 3.4.4.1

Simplify $\frac{1}{8} - 6 (\frac{1}{16}) + D - 4 F$ .

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Step 3.4.4.1.1

Simplify each term.

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Step 3.4.4.1.1.1

Cancel the common factor of $2$ .

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Step 3.4.4.1.1.1.1

Factor $2$ out of $- 6$ .

$0 = \frac{1}{8} + 2 (- 3) (\frac{1}{16}) + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.1.1.2

Factor $2$ out of $16$ .

$0 = \frac{1}{8} + 2 \cdot (- 3 \frac{1}{2 \cdot 8}) + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.1.1.3

Cancel the common factor.

$0 = \frac{1}{8} + 2 \cdot (- 3 \frac{1}{2 \cdot 8}) + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.1.1.4

Rewrite the expression.

$0 = \frac{1}{8} - 3 (\frac{1}{8}) + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

$0 = \frac{1}{8} - 3 (\frac{1}{8}) + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.1.2

Combine $- 3$ and $\frac{1}{8}$ .

$0 = \frac{1}{8} + \frac{- 3}{8} + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.1.3

Move the negative in front of the fraction.

$0 = \frac{1}{8} - \frac{3}{8} + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

$0 = \frac{1}{8} - \frac{3}{8} + D - 4 F$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.2

Combine fractions.

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Step 3.4.4.1.2.1

Combine the numerators over the common denominator.

$0 = D - 4 F + \frac{1 - 3}{8}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.2.2

Subtract $3$ from $1$ .

$0 = D - 4 F + \frac{- 2}{8}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

$0 = D - 4 F + \frac{- 2}{8}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.3

Simplify each term.

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Step 3.4.4.1.3.1

Cancel the common factor of $- 2$ and $8$ .

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Step 3.4.4.1.3.1.1

Factor $2$ out of $- 2$ .

$0 = D - 4 F + \frac{2 (- 1)}{8}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.3.1.2

Cancel the common factors.

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Step 3.4.4.1.3.1.2.1

Factor $2$ out of $8$ .

$0 = D - 4 F + \frac{2 \cdot - 1}{2 \cdot 4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.3.1.2.2

Cancel the common factor.

$0 = D - 4 F + \frac{2 \cdot - 1}{2 \cdot 4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.3.1.2.3

Rewrite the expression.

$0 = D - 4 F + \frac{- 1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

$0 = D - 4 F + \frac{- 1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

$0 = D - 4 F + \frac{- 1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.4.1.3.2

Move the negative in front of the fraction.

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = B + F$

Step 3.4.5

Replace all occurrences of $B$ in $0 = B + F$ with $\frac{1}{16}$ .

$0 = (\frac{1}{16}) + F$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.4.6

Simplify the right side.

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Step 3.4.6.1

Remove parentheses.

$0 = \frac{1}{16} + F$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = \frac{1}{16} + F$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = \frac{1}{16} + F$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.5

Solve for $F$ in $0 = \frac{1}{16} + F$ .

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Step 3.5.1

Rewrite the equation as $\frac{1}{16} + F = 0$ .

$\frac{1}{16} + F = 0$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.5.2

Subtract $\frac{1}{16}$ from both sides of the equation.

$F = - \frac{1}{16}$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$F = - \frac{1}{16}$

$0 = D - 4 F - \frac{1}{4}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6

Replace all occurrences of $F$ with $- \frac{1}{16}$ in each equation.

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Step 3.6.1

Replace all occurrences of $F$ in $0 = D - 4 F - \frac{1}{4}$ with $- \frac{1}{16}$ .

$0 = D - 4 (- \frac{1}{16}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2

Simplify the right side.

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Step 3.6.2.1

Simplify $D - 4 (- \frac{1}{16}) - \frac{1}{4}$ .

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Step 3.6.2.1.1

Simplify each term.

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Step 3.6.2.1.1.1

Cancel the common factor of $4$ .

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Step 3.6.2.1.1.1.1

Move the leading negative in $- \frac{1}{16}$ into the numerator.

$0 = D - 4 (\frac{- 1}{16}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.1.1.2

Factor $4$ out of $- 4$ .

$0 = D + 4 (- 1) (\frac{- 1}{16}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.1.1.3

Factor $4$ out of $16$ .

$0 = D + 4 \cdot (- 1 \frac{- 1}{4 \cdot 4}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.1.1.4

Cancel the common factor.

$0 = D + 4 \cdot (- 1 \frac{- 1}{4 \cdot 4}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.1.1.5

Rewrite the expression.

$0 = D - 1 (\frac{- 1}{4}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = D - 1 (\frac{- 1}{4}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.1.2

Move the negative in front of the fraction.

$0 = D - 1 (- \frac{1}{4}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.1.3

Multiply $- 1 (- \frac{1}{4})$ .

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Step 3.6.2.1.1.3.1

Multiply $- 1$ by $- 1$ .

$0 = D + 1 (\frac{1}{4}) - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.1.3.2

Multiply $\frac{1}{4}$ by $1$ .

$0 = D + \frac{1}{4} - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = D + \frac{1}{4} - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = D + \frac{1}{4} - \frac{1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.2

Combine the opposite terms in $D + \frac{1}{4} - \frac{1}{4}$ .

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Step 3.6.2.1.2.1

Combine the numerators over the common denominator.

$0 = D + \frac{1 - 1}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.2.2

Subtract $1$ from $1$ .

$0 = D + \frac{0}{4}$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.2.3

Divide $0$ by $4$ .

$0 = D + 0$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.2.1.2.4

Add $D$ and $0$ .

$0 = D$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = D$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = D$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = D$

$F = - \frac{1}{16}$

$0 = C - 2 D + 4 F$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.3

Replace all occurrences of $F$ in $0 = C - 2 D + 4 F$ with $- \frac{1}{16}$ .

$0 = C - 2 D + 4 (- \frac{1}{16})$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.4

Simplify the right side.

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Step 3.6.4.1

Simplify each term.

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Step 3.6.4.1.1

Cancel the common factor of $4$ .

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Step 3.6.4.1.1.1

Move the leading negative in $- \frac{1}{16}$ into the numerator.

$0 = C - 2 D + 4 (\frac{- 1}{16})$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.4.1.1.2

Factor $4$ out of $16$ .

$0 = C - 2 D + 4 (\frac{- 1}{4 (4)})$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.4.1.1.3

Cancel the common factor.

$0 = C - 2 D + 4 (\frac{- 1}{4 \cdot 4})$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.4.1.1.4

Rewrite the expression.

$0 = C - 2 D + \frac{- 1}{4}$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = C - 2 D + \frac{- 1}{4}$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.6.4.1.2

Move the negative in front of the fraction.

$0 = C - 2 D - \frac{1}{4}$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = C - 2 D - \frac{1}{4}$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = C - 2 D - \frac{1}{4}$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = C - 2 D - \frac{1}{4}$

$0 = D$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.7

Rewrite the equation as $D = 0$ .

$D = 0$

$0 = C - 2 D - \frac{1}{4}$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.8

Replace all occurrences of $D$ with $0$ in each equation.

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Step 3.8.1

Replace all occurrences of $D$ in $0 = C - 2 D - \frac{1}{4}$ with $0$ .

$0 = C - 2 \cdot 0 - \frac{1}{4}$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.8.2

Simplify the right side.

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Step 3.8.2.1

Simplify $C - 2 \cdot 0 - \frac{1}{4}$ .

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Step 3.8.2.1.1

Multiply $- 2$ by $0$ .

$0 = C + 0 - \frac{1}{4}$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.8.2.1.2

Add $C$ and $0$ .

$0 = C - \frac{1}{4}$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = C - \frac{1}{4}$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = C - \frac{1}{4}$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$0 = C - \frac{1}{4}$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.9

Solve for $C$ in $0 = C - \frac{1}{4}$ .

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Step 3.9.1

Rewrite the equation as $C - \frac{1}{4} = 0$ .

$C - \frac{1}{4} = 0$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.9.2

Add $\frac{1}{4}$ to both sides of the equation.

$C = \frac{1}{4}$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

$C = \frac{1}{4}$

$D = 0$

$F = - \frac{1}{16}$

$B = \frac{1}{16}$

$A = \frac{1}{8}$

Step 3.10

Solve the system of equations.

$C = \frac{1}{4} D = 0 F = - \frac{1}{16} B = \frac{1}{16} A = \frac{1}{8}$

Step 3.11

List all of the solutions.

$C = \frac{1}{4}, D = 0, F = - \frac{1}{16}, B = \frac{1}{16}, A = \frac{1}{8}$

Step 4

Replace each of the partial fraction coefficients in $\frac{A}{x^{2}} + \frac{B}{x} + \frac{C}{{(x - 2)}^{3}} + \frac{D}{{(x - 2)}^{2}} + \frac{F}{x - 2}$ with the values found for $A$ , $B$ , $C$ , $D$ , and $F$ .

$\frac{\frac{1}{8}}{x^{2}} + \frac{\frac{1}{16}}{x} + \frac{\frac{1}{4}}{{(x - 2)}^{3}} + \frac{0}{{(x - 2)}^{2}} + \frac{- \frac{1}{16}}{x - 2}$