Precalculus Examples

 $\begin{matrix} Side & Angle \\ \begin{matrix} b = \\ c = & 8 \\ a = \end{matrix} & \begin{matrix} A = \\ B = & 120 ° \\ C = & 45 ° \end{matrix} \end{matrix}$

Step 1

The law of sines is based on the proportionality of sides and angles in triangles. The law states that for the angles of a non-right triangle, each angle of the triangle has the same ratio of angle measure to sine value.

$\frac{\sin (A)}{a} = \frac{\sin (B)}{b} = \frac{\sin (C)}{c}$

Step 2

Substitute the known values into the law of sines to find $b$ .

$\frac{\sin (120 °)}{b} = \frac{\sin (45 °)}{8}$

Step 3

Solve the equation for $b$ .

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Step 3.1

Factor each term.

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Step 3.1.1

Simplify the numerator.

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Step 3.1.1.1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$\frac{\sin (60)}{b} = \frac{\sin (45 °)}{8}$

Step 3.1.1.2

The exact value of $\sin (60)$ is $\frac{\sqrt{3}}{2}$ .

$\frac{\frac{\sqrt{3}}{2}}{b} = \frac{\sin (45 °)}{8}$

Step 3.1.2

Multiply the numerator by the reciprocal of the denominator.

$\frac{\sqrt{3}}{2} \cdot \frac{1}{b} = \frac{\sin (45 °)}{8}$

Step 3.1.3

Multiply $\frac{\sqrt{3}}{2}$ by $\frac{1}{b}$ .

$\frac{\sqrt{3}}{2 b} = \frac{\sin (45 °)}{8}$

Step 3.1.4

The exact value of $\sin (45 °)$ is $\frac{\sqrt{2}}{2}$ .

$\frac{\sqrt{3}}{2 b} = \frac{\frac{\sqrt{2}}{2}}{8}$

Step 3.1.5

Multiply the numerator by the reciprocal of the denominator.

$\frac{\sqrt{3}}{2 b} = \frac{\sqrt{2}}{2} \cdot \frac{1}{8}$

Step 3.1.6

Multiply $\frac{\sqrt{2}}{2} \cdot \frac{1}{8}$ .

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Step 3.1.6.1

Multiply $\frac{\sqrt{2}}{2}$ by $\frac{1}{8}$ .

$\frac{\sqrt{3}}{2 b} = \frac{\sqrt{2}}{2 \cdot 8}$

Step 3.1.6.2

Multiply $2$ by $8$ .

$\frac{\sqrt{3}}{2 b} = \frac{\sqrt{2}}{16}$

Step 3.2

Find the LCD of the terms in the equation.

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Step 3.2.1

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$2 b, 16$

Step 3.2.2

Since $2 b, 16$ contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part $2, 16$ then find LCM for the variable part $b^{1}$ .

Step 3.2.3

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

Step 3.2.4

Since $2$ has no factors besides $1$ and $2$ .

$2$ is a prime number

Step 3.2.5

The prime factors for $16$ are $2 \cdot 2 \cdot 2 \cdot 2$ .

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Step 3.2.5.1

$16$ has factors of $2$ and $8$ .

$2 \cdot 8$

Step 3.2.5.2

$8$ has factors of $2$ and $4$ .

$2 \cdot 2 \cdot 4$

Step 3.2.5.3

$4$ has factors of $2$ and $2$ .

$2 \cdot 2 \cdot 2 \cdot 2$

Step 3.2.6

Multiply $2 \cdot 2 \cdot 2 \cdot 2$ .

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Step 3.2.6.1

Multiply $2$ by $2$ .

$4 \cdot 2 \cdot 2$

Step 3.2.6.2

Multiply $4$ by $2$ .

$8 \cdot 2$

Step 3.2.6.3

Multiply $8$ by $2$ .

$16$

Step 3.2.7

The factor for $b^{1}$ is $b$ itself.

$b^{1} = b$

$b$ occurs $1$ time.

Step 3.2.8

The LCM of $b^{1}$ is the result of multiplying all prime factors the greatest number of times they occur in either term.

$b$

Step 3.2.9

The LCM for $2 b, 16$ is the numeric part $16$ multiplied by the variable part.

$16 b$

Step 3.3

Multiply each term in $\frac{\sqrt{3}}{2 b} = \frac{\sqrt{2}}{16}$ by $16 b$ to eliminate the fractions.

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Step 3.3.1

Multiply each term in $\frac{\sqrt{3}}{2 b} = \frac{\sqrt{2}}{16}$ by $16 b$ .

$\frac{\sqrt{3}}{2 b} (16 b) = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.2

Simplify the left side.

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Step 3.3.2.1

Rewrite using the commutative property of multiplication.

$16 \frac{\sqrt{3}}{2 b} b = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.2.2

Cancel the common factor of $2$ .

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Step 3.3.2.2.1

Factor $2$ out of $16$ .

$2 (8) \frac{\sqrt{3}}{2 b} b = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.2.2.2

Factor $2$ out of $2 b$ .

$2 (8) \frac{\sqrt{3}}{2 (b)} b = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.2.2.3

Cancel the common factor.

$2 \cdot 8 \frac{\sqrt{3}}{2 b} b = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.2.2.4

Rewrite the expression.

$8 \frac{\sqrt{3}}{b} b = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.2.3

Combine $8$ and $\frac{\sqrt{3}}{b}$ .

$\frac{8 \sqrt{3}}{b} b = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.2.4

Cancel the common factor of $b$ .

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Step 3.3.2.4.1

Cancel the common factor.

$\frac{8 \sqrt{3}}{b} b = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.2.4.2

Rewrite the expression.

$8 \sqrt{3} = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.3

Simplify the right side.

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Step 3.3.3.1

Cancel the common factor of $16$ .

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Step 3.3.3.1.1

Factor $16$ out of $16 b$ .

$8 \sqrt{3} = \frac{\sqrt{2}}{16} (16 (b))$

Step 3.3.3.1.2

Cancel the common factor.

$8 \sqrt{3} = \frac{\sqrt{2}}{16} (16 b)$

Step 3.3.3.1.3

Rewrite the expression.

$8 \sqrt{3} = \sqrt{2} b$

Step 3.4

Solve the equation.

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Step 3.4.1

Rewrite the equation as $\sqrt{2} b = 8 \sqrt{3}$ .

$\sqrt{2} b = 8 \sqrt{3}$

Step 3.4.2

Divide each term in $\sqrt{2} b = 8 \sqrt{3}$ by $\sqrt{2}$ and simplify.

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Step 3.4.2.1

Divide each term in $\sqrt{2} b = 8 \sqrt{3}$ by $\sqrt{2}$ .

$\frac{\sqrt{2} b}{\sqrt{2}} = \frac{8 \sqrt{3}}{\sqrt{2}}$

Step 3.4.2.2

Simplify the left side.

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Step 3.4.2.2.1

Cancel the common factor of $\sqrt{2}$ .

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Step 3.4.2.2.1.1

Cancel the common factor.

$\frac{\sqrt{2} b}{\sqrt{2}} = \frac{8 \sqrt{3}}{\sqrt{2}}$

Step 3.4.2.2.1.2

Divide $b$ by $1$ .

$b = \frac{8 \sqrt{3}}{\sqrt{2}}$

Step 3.4.2.3

Simplify the right side.

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Step 3.4.2.3.1

Multiply $\frac{8 \sqrt{3}}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$b = \frac{8 \sqrt{3}}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$

Step 3.4.2.3.2

Combine and simplify the denominator.

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Step 3.4.2.3.2.1

Multiply $\frac{8 \sqrt{3}}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$b = \frac{8 \sqrt{3} \sqrt{2}}{\sqrt{2} \sqrt{2}}$

Step 3.4.2.3.2.2

Raise $\sqrt{2}$ to the power of $1$ .

$b = \frac{8 \sqrt{3} \sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}}$

Step 3.4.2.3.2.3

Raise $\sqrt{2}$ to the power of $1$ .

$b = \frac{8 \sqrt{3} \sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}}$

Step 3.4.2.3.2.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$b = \frac{8 \sqrt{3} \sqrt{2}}{{\sqrt{2}}^{1 + 1}}$

Step 3.4.2.3.2.5

Add $1$ and $1$ .

$b = \frac{8 \sqrt{3} \sqrt{2}}{{\sqrt{2}}^{2}}$

Step 3.4.2.3.2.6

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

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Step 3.4.2.3.2.6.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$b = \frac{8 \sqrt{3} \sqrt{2}}{{(2^{\frac{1}{2}})}^{2}}$

Step 3.4.2.3.2.6.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$b = \frac{8 \sqrt{3} \sqrt{2}}{2^{\frac{1}{2} \cdot 2}}$

Step 3.4.2.3.2.6.3

Combine $\frac{1}{2}$ and $2$ .

$b = \frac{8 \sqrt{3} \sqrt{2}}{2^{\frac{2}{2}}}$

Step 3.4.2.3.2.6.4

Cancel the common factor of $2$ .

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Step 3.4.2.3.2.6.4.1

Cancel the common factor.

$b = \frac{8 \sqrt{3} \sqrt{2}}{2^{\frac{2}{2}}}$

Step 3.4.2.3.2.6.4.2

Rewrite the expression.

$b = \frac{8 \sqrt{3} \sqrt{2}}{2^{1}}$

Step 3.4.2.3.2.6.5

Evaluate the exponent.

$b = \frac{8 \sqrt{3} \sqrt{2}}{2}$

Step 3.4.2.3.3

Cancel the common factor of $8$ and $2$ .

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Step 3.4.2.3.3.1

Factor $2$ out of $8 \sqrt{3} \sqrt{2}$ .

$b = \frac{2 (4 \sqrt{3} \sqrt{2})}{2}$

Step 3.4.2.3.3.2

Cancel the common factors.

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Step 3.4.2.3.3.2.1

Factor $2$ out of $2$ .

$b = \frac{2 (4 \sqrt{3} \sqrt{2})}{2 (1)}$

Step 3.4.2.3.3.2.2

Cancel the common factor.

$b = \frac{2 (4 \sqrt{3} \sqrt{2})}{2 \cdot 1}$

Step 3.4.2.3.3.2.3

Rewrite the expression.

$b = \frac{4 \sqrt{3} \sqrt{2}}{1}$

Step 3.4.2.3.3.2.4

Divide $4 \sqrt{3} \sqrt{2}$ by $1$ .

$b = 4 \sqrt{3} \sqrt{2}$

Step 3.4.2.3.4

Multiply $4 \sqrt{3} \sqrt{2}$ .

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Step 3.4.2.3.4.1

Combine using the product rule for radicals.

$b = 4 \sqrt{2 \cdot 3}$

Step 3.4.2.3.4.2

Multiply $2$ by $3$ .

$b = 4 \sqrt{6}$

Step 4

The sum of all the angles in a triangle is $180$ degrees.

$A + 45 ° + 120 ° = 180$

Step 5

Solve the equation for $A$ .

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Step 5.1

Add $45 °$ and $120 °$ .

$A + 165 = 180$

Step 5.2

Move all terms not containing $A$ to the right side of the equation.

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Step 5.2.1

Subtract $165$ from both sides of the equation.

$A = 180 - 165$

Step 5.2.2

Subtract $165$ from $180$ .

$A = 15$

Step 6

$\frac{\sin (A)}{a} = \frac{\sin (B)}{b} = \frac{\sin (C)}{c}$

Step 7

Substitute the known values into the law of sines to find $a$ .

$\frac{\sin (15)}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8

Solve the equation for $a$ .

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Step 8.1

Factor each term.

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Step 8.1.1

The exact value of $\sin (15)$ is $\frac{\sqrt{6} - \sqrt{2}}{4}$ .

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Step 8.1.1.1

Split $15$ into two angles where the values of the six trigonometric functions are known.

$\frac{\sin (45 - 30)}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.2

Separate negation.

$\frac{\sin (45 - (30))}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.3

Apply the difference of angles identity.

$\frac{\sin (45) \cos (30) - \cos (45) \sin (30)}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.4

The exact value of $\sin (45)$ is $\frac{\sqrt{2}}{2}$ .

$\frac{\frac{\sqrt{2}}{2} \cos (30) - \cos (45) \sin (30)}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.5

The exact value of $\cos (30)$ is $\frac{\sqrt{3}}{2}$ .

$\frac{\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \cos (45) \sin (30)}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.6

The exact value of $\cos (45)$ is $\frac{\sqrt{2}}{2}$ .

$\frac{\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \sin (30)}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.7

The exact value of $\sin (30)$ is $\frac{1}{2}$ .

$\frac{\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.8

Simplify $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Step 8.1.1.8.1

Simplify each term.

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Step 8.1.1.8.1.1

Multiply $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2}$ .

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Step 8.1.1.8.1.1.1

Multiply $\frac{\sqrt{2}}{2}$ by $\frac{\sqrt{3}}{2}$ .

$\frac{\frac{\sqrt{2} \sqrt{3}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.8.1.1.2

Combine using the product rule for radicals.

$\frac{\frac{\sqrt{2 \cdot 3}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.8.1.1.3

Multiply $2$ by $3$ .

$\frac{\frac{\sqrt{6}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.8.1.1.4

Multiply $2$ by $2$ .

$\frac{\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.8.1.2

Multiply $- \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Step 8.1.1.8.1.2.1

Multiply $\frac{1}{2}$ by $\frac{\sqrt{2}}{2}$ .

$\frac{\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2 \cdot 2}}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.8.1.2.2

Multiply $2$ by $2$ .

$\frac{\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4}}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.1.8.2

Combine the numerators over the common denominator.

$\frac{\frac{\sqrt{6} - \sqrt{2}}{4}}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.2

Multiply the numerator by the reciprocal of the denominator.

$\frac{\sqrt{6} - \sqrt{2}}{4} \cdot \frac{1}{a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.3

Multiply $\frac{\sqrt{6} - \sqrt{2}}{4}$ by $\frac{1}{a}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sin (120 °)}{4 \sqrt{6}}$

Step 8.1.4

Simplify the numerator.

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Step 8.1.4.1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sin (60)}{4 \sqrt{6}}$

Step 8.1.4.2

The exact value of $\sin (60)$ is $\frac{\sqrt{3}}{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\frac{\sqrt{3}}{2}}{4 \sqrt{6}}$

Step 8.1.5

Multiply the numerator by the reciprocal of the denominator.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{1}{4 \sqrt{6}}$

Step 8.1.6

Multiply $\frac{1}{4 \sqrt{6}}$ by $\frac{\sqrt{6}}{\sqrt{6}}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} (\frac{1}{4 \sqrt{6}} \cdot \frac{\sqrt{6}}{\sqrt{6}})$

Step 8.1.7

Combine and simplify the denominator.

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Step 8.1.7.1

Multiply $\frac{1}{4 \sqrt{6}}$ by $\frac{\sqrt{6}}{\sqrt{6}}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 \sqrt{6} \sqrt{6}}$

Step 8.1.7.2

Move $\sqrt{6}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 (\sqrt{6} \sqrt{6})}$

Step 8.1.7.3

Raise $\sqrt{6}$ to the power of $1$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 ({\sqrt{6}}^{1} \sqrt{6})}$

Step 8.1.7.4

Raise $\sqrt{6}$ to the power of $1$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 ({\sqrt{6}}^{1} {\sqrt{6}}^{1})}$

Step 8.1.7.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 {\sqrt{6}}^{1 + 1}}$

Step 8.1.7.6

Add $1$ and $1$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 {\sqrt{6}}^{2}}$

Step 8.1.7.7

Rewrite ${\sqrt{6}}^{2}$ as $6$ .

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Step 8.1.7.7.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{6}$ as $6^{\frac{1}{2}}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 {(6^{\frac{1}{2}})}^{2}}$

Step 8.1.7.7.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 \cdot 6^{\frac{1}{2} \cdot 2}}$

Step 8.1.7.7.3

Combine $\frac{1}{2}$ and $2$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 \cdot 6^{\frac{2}{2}}}$

Step 8.1.7.7.4

Cancel the common factor of $2$ .

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Step 8.1.7.7.4.1

Cancel the common factor.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 \cdot 6^{\frac{2}{2}}}$

Step 8.1.7.7.4.2

Rewrite the expression.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 \cdot 6^{1}}$

Step 8.1.7.7.5

Evaluate the exponent.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{4 \cdot 6}$

Step 8.1.8

Multiply $4$ by $6$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{24}$

Step 8.1.9

Multiply $\frac{\sqrt{3}}{2} \cdot \frac{\sqrt{6}}{24}$ .

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Step 8.1.9.1

Multiply $\frac{\sqrt{3}}{2}$ by $\frac{\sqrt{6}}{24}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3} \sqrt{6}}{2 \cdot 24}$

Step 8.1.9.2

Combine using the product rule for radicals.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3 \cdot 6}}{2 \cdot 24}$

Step 8.1.9.3

Multiply $3$ by $6$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{18}}{2 \cdot 24}$

Step 8.1.9.4

Multiply $2$ by $24$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{18}}{48}$

Step 8.1.10

Simplify the numerator.

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Step 8.1.10.1

Rewrite $18$ as $3^{2} \cdot 2$ .

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Step 8.1.10.1.1

Factor $9$ out of $18$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{9 (2)}}{48}$

Step 8.1.10.1.2

Rewrite $9$ as $3^{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{3^{2} \cdot 2}}{48}$

Step 8.1.10.2

Pull terms out from under the radical.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{3 \sqrt{2}}{48}$

Step 8.1.11

Cancel the common factor of $3$ and $48$ .

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Step 8.1.11.1

Factor $3$ out of $3 \sqrt{2}$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{3 (\sqrt{2})}{48}$

Step 8.1.11.2

Cancel the common factors.

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Step 8.1.11.2.1

Factor $3$ out of $48$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{3 \sqrt{2}}{3 \cdot 16}$

Step 8.1.11.2.2

Cancel the common factor.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{3 \sqrt{2}}{3 \cdot 16}$

Step 8.1.11.2.3

Rewrite the expression.

$\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{2}}{16}$

Step 8.2

Find the LCD of the terms in the equation.

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Step 8.2.1

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$4 a, 16$

Step 8.2.2

Since $4 a, 16$ contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part $4, 16$ then find LCM for the variable part $a^{1}$ .

Step 8.2.3

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

Step 8.2.4

$4$ has factors of $2$ and $2$ .

$2 \cdot 2$

Step 8.2.5

The prime factors for $16$ are $2 \cdot 2 \cdot 2 \cdot 2$ .

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Step 8.2.5.1

$16$ has factors of $2$ and $8$ .

$2 \cdot 8$

Step 8.2.5.2

$8$ has factors of $2$ and $4$ .

$2 \cdot 2 \cdot 4$

Step 8.2.5.3

$4$ has factors of $2$ and $2$ .

$2 \cdot 2 \cdot 2 \cdot 2$

Step 8.2.6

Multiply $2 \cdot 2 \cdot 2 \cdot 2$ .

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Step 8.2.6.1

Multiply $2$ by $2$ .

$4 \cdot 2 \cdot 2$

Step 8.2.6.2

Multiply $4$ by $2$ .

$8 \cdot 2$

Step 8.2.6.3

Multiply $8$ by $2$ .

$16$

Step 8.2.7

The factor for $a^{1}$ is $a$ itself.

$a^{1} = a$

$a$ occurs $1$ time.

Step 8.2.8

The LCM of $a^{1}$ is the result of multiplying all prime factors the greatest number of times they occur in either term.

$a$

Step 8.2.9

The LCM for $4 a, 16$ is the numeric part $16$ multiplied by the variable part.

$16 a$

Step 8.3

Multiply each term in $\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{2}}{16}$ by $16 a$ to eliminate the fractions.

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Step 8.3.1

Multiply each term in $\frac{\sqrt{6} - \sqrt{2}}{4 a} = \frac{\sqrt{2}}{16}$ by $16 a$ .

$\frac{\sqrt{6} - \sqrt{2}}{4 a} (16 a) = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2

Simplify the left side.

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Step 8.3.2.1

Rewrite using the commutative property of multiplication.

$16 \frac{\sqrt{6} - \sqrt{2}}{4 a} a = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.2

Cancel the common factor of $4$ .

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Step 8.3.2.2.1

Factor $4$ out of $16$ .

$4 (4) \frac{\sqrt{6} - \sqrt{2}}{4 a} a = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.2.2

Factor $4$ out of $4 a$ .

$4 (4) \frac{\sqrt{6} - \sqrt{2}}{4 (a)} a = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.2.3

Cancel the common factor.

$4 \cdot 4 \frac{\sqrt{6} - \sqrt{2}}{4 a} a = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.2.4

Rewrite the expression.

$4 \frac{\sqrt{6} - \sqrt{2}}{a} a = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.3

Combine $4$ and $\frac{\sqrt{6} - \sqrt{2}}{a}$ .

$\frac{4 (\sqrt{6} - \sqrt{2})}{a} a = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.4

Cancel the common factor of $a$ .

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Step 8.3.2.4.1

Cancel the common factor.

$\frac{4 (\sqrt{6} - \sqrt{2})}{a} a = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.4.2

Rewrite the expression.

$4 (\sqrt{6} - \sqrt{2}) = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.5

Apply the distributive property.

$4 \sqrt{6} + 4 (- \sqrt{2}) = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.2.6

Multiply $- 1$ by $4$ .

$4 \sqrt{6} - 4 \sqrt{2} = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.3

Simplify the right side.

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Step 8.3.3.1

Cancel the common factor of $16$ .

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Step 8.3.3.1.1

Factor $16$ out of $16 a$ .

$4 \sqrt{6} - 4 \sqrt{2} = \frac{\sqrt{2}}{16} (16 (a))$

Step 8.3.3.1.2

Cancel the common factor.

$4 \sqrt{6} - 4 \sqrt{2} = \frac{\sqrt{2}}{16} (16 a)$

Step 8.3.3.1.3

Rewrite the expression.

$4 \sqrt{6} - 4 \sqrt{2} = \sqrt{2} a$

Step 8.4

Solve the equation.

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Step 8.4.1

Rewrite the equation as $\sqrt{2} a = 4 \sqrt{6} - 4 \sqrt{2}$ .

$\sqrt{2} a = 4 \sqrt{6} - 4 \sqrt{2}$

Step 8.4.2

Divide each term in $\sqrt{2} a = 4 \sqrt{6} - 4 \sqrt{2}$ by $\sqrt{2}$ and simplify.

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Step 8.4.2.1

Divide each term in $\sqrt{2} a = 4 \sqrt{6} - 4 \sqrt{2}$ by $\sqrt{2}$ .

$\frac{\sqrt{2} a}{\sqrt{2}} = \frac{4 \sqrt{6}}{\sqrt{2}} + \frac{- 4 \sqrt{2}}{\sqrt{2}}$

Step 8.4.2.2

Simplify the left side.

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Step 8.4.2.2.1

Cancel the common factor of $\sqrt{2}$ .

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Step 8.4.2.2.1.1

Cancel the common factor.

$\frac{\sqrt{2} a}{\sqrt{2}} = \frac{4 \sqrt{6}}{\sqrt{2}} + \frac{- 4 \sqrt{2}}{\sqrt{2}}$

Step 8.4.2.2.1.2

Divide $a$ by $1$ .

$a = \frac{4 \sqrt{6}}{\sqrt{2}} + \frac{- 4 \sqrt{2}}{\sqrt{2}}$

Step 8.4.2.3

Simplify the right side.

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Step 8.4.2.3.1

Simplify each term.

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Step 8.4.2.3.1.1

Combine $\sqrt{6}$ and $\sqrt{2}$ into a single radical.

$a = 4 \sqrt{\frac{6}{2}} + \frac{- 4 \sqrt{2}}{\sqrt{2}}$

Step 8.4.2.3.1.2

Divide $6$ by $2$ .

$a = 4 \sqrt{3} + \frac{- 4 \sqrt{2}}{\sqrt{2}}$

Step 8.4.2.3.1.3

Cancel the common factor of $\sqrt{2}$ .

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Step 8.4.2.3.1.3.1

Cancel the common factor.

$a = 4 \sqrt{3} + \frac{- 4 \sqrt{2}}{\sqrt{2}}$

Step 8.4.2.3.1.3.2

Divide $- 4$ by $1$ .

$a = 4 \sqrt{3} - 4$

Step 9

These are the results for all angles and sides for the given triangle.

$A = 15$

$B = 120 °$

$C = 45 °$

$a = 4 \sqrt{3} - 4$

$b = 4 \sqrt{6}$

$c = 8$