Precalculus Examples

$\sqrt[3]{x + 3}$

Step 1

Interchange the variables.

$x = \sqrt[3]{y + 3}$

Step 2

Solve for $y$ .

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Step 2.1

Rewrite the equation as $\sqrt[3]{y + 3} = x$ .

$\sqrt[3]{y + 3} = x$

Step 2.2

To remove the radical on the left side of the equation, cube both sides of the equation.

${\sqrt[3]{y + 3}}^{3} = x^{3}$

Step 2.3

Simplify each side of the equation.

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Step 2.3.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{y + 3}$ as ${(y + 3)}^{\frac{1}{3}}$ .

${({(y + 3)}^{\frac{1}{3}})}^{3} = x^{3}$

Step 2.3.2

Simplify the left side.

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Step 2.3.2.1

Simplify ${({(y + 3)}^{\frac{1}{3}})}^{3}$ .

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Step 2.3.2.1.1

Multiply the exponents in ${({(y + 3)}^{\frac{1}{3}})}^{3}$ .

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Step 2.3.2.1.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(y + 3)}^{\frac{1}{3} \cdot 3} = x^{3}$

Step 2.3.2.1.1.2

Cancel the common factor of $3$ .

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Step 2.3.2.1.1.2.1

Cancel the common factor.

${(y + 3)}^{\frac{1}{3} \cdot 3} = x^{3}$

Step 2.3.2.1.1.2.2

Rewrite the expression.

${(y + 3)}^{1} = x^{3}$

Step 2.3.2.1.2

Simplify.

$y + 3 = x^{3}$

Step 2.4

Subtract $3$ from both sides of the equation.

$y = x^{3} - 3$

Step 3

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = x^{3} - 3$

Step 4

Verify if $f^{- 1} (x) = x^{3} - 3$ is the inverse of $f (x) = \sqrt[3]{x + 3}$ .

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Step 4.1

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Step 4.2

Evaluate $f^{- 1} (f (x))$ .

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Step 4.2.1

Set up the composite result function.

$f^{- 1} (f (x))$

Step 4.2.2

Evaluate $f^{- 1} (\sqrt[3]{x + 3})$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\sqrt[3]{x + 3}) = {(\sqrt[3]{x + 3})}^{3} - 3$

Step 4.2.3

Rewrite ${\sqrt[3]{x + 3}}^{3}$ as $x + 3$ .

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Step 4.2.3.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{x + 3}$ as ${(x + 3)}^{\frac{1}{3}}$ .

$f^{- 1} (\sqrt[3]{x + 3}) = {({(x + 3)}^{\frac{1}{3}})}^{3} - 3$

Step 4.2.3.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (\sqrt[3]{x + 3}) = {(x + 3)}^{\frac{1}{3} \cdot 3} - 3$

Step 4.2.3.3

Combine $\frac{1}{3}$ and $3$ .

$f^{- 1} (\sqrt[3]{x + 3}) = {(x + 3)}^{\frac{3}{3}} - 3$

Step 4.2.3.4

Cancel the common factor of $3$ .

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Step 4.2.3.4.1

Cancel the common factor.

$f^{- 1} (\sqrt[3]{x + 3}) = {(x + 3)}^{\frac{3}{3}} - 3$

Step 4.2.3.4.2

Rewrite the expression.

$f^{- 1} (\sqrt[3]{x + 3}) = (x + 3) - 3$

Step 4.2.3.5

Simplify.

$f^{- 1} (\sqrt[3]{x + 3}) = x + 3 - 3$

Step 4.2.4

Combine the opposite terms in $x + 3 - 3$ .

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Step 4.2.4.1

Subtract $3$ from $3$ .

$f^{- 1} (\sqrt[3]{x + 3}) = x + 0$

Step 4.2.4.2

Add $x$ and $0$ .

$f^{- 1} (\sqrt[3]{x + 3}) = x$

Step 4.3

Evaluate $f (f^{- 1} (x))$ .

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Step 4.3.1

Set up the composite result function.

$f (f^{- 1} (x))$

Step 4.3.2

Evaluate $f (x^{3} - 3)$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (x^{3} - 3) = \sqrt[3]{(x^{3} - 3) + 3}$

Step 4.3.3

Add $- 3$ and $3$ .

$f (x^{3} - 3) = \sqrt[3]{x^{3} + 0}$

Step 4.3.4

Add $x^{3}$ and $0$ .

$f (x^{3} - 3) = \sqrt[3]{x^{3}}$

Step 4.3.5

Pull terms out from under the radical, assuming real numbers.

$f (x^{3} - 3) = x$

Step 4.4

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = x^{3} - 3$ is the inverse of $f (x) = \sqrt[3]{x + 3}$ .

$f^{- 1} (x) = x^{3} - 3$