Precalculus Examples

$y^{2} = - 15 x$

Step 1

Rewrite the equation in vertex form.

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Step 1.1

Isolate $x$ to the left side of the equation.

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Step 1.1.1

Rewrite the equation as $- 15 x = y^{2}$ .

$- 15 x = y^{2}$

Step 1.1.2

Divide each term in $- 15 x = y^{2}$ by $- 15$ and simplify.

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Step 1.1.2.1

Divide each term in $- 15 x = y^{2}$ by $- 15$ .

$\frac{- 15 x}{- 15} = \frac{y^{2}}{- 15}$

Step 1.1.2.2

Simplify the left side.

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Step 1.1.2.2.1

Cancel the common factor of $- 15$ .

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Step 1.1.2.2.1.1

Cancel the common factor.

$\frac{- 15 x}{- 15} = \frac{y^{2}}{- 15}$

Step 1.1.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{y^{2}}{- 15}$

Step 1.1.2.3

Simplify the right side.

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Step 1.1.2.3.1

Move the negative in front of the fraction.

$x = - \frac{y^{2}}{15}$

Step 1.2

Complete the square for $- \frac{y^{2}}{15}$ .

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Step 1.2.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - \frac{1}{15}$

$b = 0$

$c = 0$

Step 1.2.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 1.2.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 1.2.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{0}{2 (- \frac{1}{15})}$

Step 1.2.3.2

Simplify the right side.

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Step 1.2.3.2.1

Cancel the common factor of $0$ and $2$ .

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Step 1.2.3.2.1.1

Factor $2$ out of $0$ .

$d = \frac{2 (0)}{2 (- \frac{1}{15})}$

Step 1.2.3.2.1.2

Cancel the common factors.

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Step 1.2.3.2.1.2.1

Cancel the common factor.

$d = \frac{2 \cdot 0}{2 (- \frac{1}{15})}$

Step 1.2.3.2.1.2.2

Rewrite the expression.

$d = \frac{0}{- \frac{1}{15}}$

Step 1.2.3.2.2

Multiply the numerator by the reciprocal of the denominator.

$d = 0 (- 1 \cdot 15)$

Step 1.2.3.2.3

Multiply $0 (- 1 \cdot 15)$ .

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Step 1.2.3.2.3.1

Multiply $- 1$ by $15$ .

$d = 0 \cdot - 15$

Step 1.2.3.2.3.2

Multiply $0$ by $- 15$ .

$d = 0$

Step 1.2.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 1.2.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{0^{2}}{4 (- \frac{1}{15})}$

Step 1.2.4.2

Simplify the right side.

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Step 1.2.4.2.1

Simplify each term.

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Step 1.2.4.2.1.1

Raising $0$ to any positive power yields $0$ .

$e = 0 - \frac{0}{4 (- \frac{1}{15})}$

Step 1.2.4.2.1.2

Simplify the denominator.

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Step 1.2.4.2.1.2.1

Multiply $- 1$ by $4$ .

$e = 0 - \frac{0}{- 4 (\frac{1}{15})}$

Step 1.2.4.2.1.2.2

Combine $- 4$ and $\frac{1}{15}$ .

$e = 0 - \frac{0}{\frac{- 4}{15}}$

Step 1.2.4.2.1.3

Move the negative in front of the fraction.

$e = 0 - \frac{0}{- \frac{4}{15}}$

Step 1.2.4.2.1.4

Multiply the numerator by the reciprocal of the denominator.

$e = 0 - (0 (- \frac{15}{4}))$

Step 1.2.4.2.1.5

Multiply $0 (- \frac{15}{4})$ .

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Step 1.2.4.2.1.5.1

Multiply $- 1$ by $0$ .

$e = 0 - (0 (\frac{15}{4}))$

Step 1.2.4.2.1.5.2

Multiply $0$ by $\frac{15}{4}$ .

$e = 0 - 0$

Step 1.2.4.2.1.6

Multiply $- 1$ by $0$ .

$e = 0 + 0$

Step 1.2.4.2.2

Add $0$ and $0$ .

$e = 0$

Step 1.2.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- \frac{1}{15} y^{2}$ .

$- \frac{1}{15} y^{2}$

Step 1.3

Set $x$ equal to the new right side.

$x = - \frac{1}{15} y^{2}$

Step 2

Use the vertex form, $x = a {(y - k)}^{2} + h$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - \frac{1}{15}$

$h = 0$

$k = 0$

Step 3

Find the vertex $(h, k)$ .

$(0, 0)$

Step 4