Precalculus Examples

$- 12 {(y - 6)}^{2} = (x + 5)$

Step 1

Isolate $x$ to the left side of the equation.

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Step 1.1

Rewrite the equation as $x + 5 = - 12 {(y - 6)}^{2}$ .

$x + 5 = - 12 {(y - 6)}^{2}$

Step 1.2

Subtract $5$ from both sides of the equation.

$x = - 12 {(y - 6)}^{2} - 5$

Step 2

Use the vertex form, $x = a {(y - k)}^{2} + h$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 12$

$h = - 5$

$k = 6$

Step 3

Find the vertex $(h, k)$ .

$(- 5, 6)$

Step 4