Precalculus Examples

$y - 11 = - {(x - 5)}^{2}$

Step 1

Add $11$ to both sides of the equation.

$y = - {(x - 5)}^{2} + 11$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = 5$

$k = 11$

Step 3

Find the vertex $(h, k)$ .

$(5, 11)$

Step 4