Precalculus Examples

g (- 3) = \frac{x}{\sqrt{9 - x^{2}}}

$g (- 3) = \frac{x}{\sqrt{9 - x^{2}}}$

Step 1

Replace the variable

x

$x$ with

- 3

$- 3$ in the expression.

g (- 3) = \frac{- 3}{\sqrt{9 - {(- 3)}^{2}}}

$g (- 3) = \frac{- 3}{\sqrt{9 - {(- 3)}^{2}}}$

Step 2

Raise

- 3

$- 3$ to the power of

2

$2$ .

g (- 3) = \frac{- 3}{\sqrt{9 - 1 \cdot 9}}

$g (- 3) = \frac{- 3}{\sqrt{9 - 1 \cdot 9}}$

Step 3

Multiply

- 1

$- 1$ by

9

$9$ .

g (- 3) = \frac{- 3}{\sqrt{9 - 9}}

$g (- 3) = \frac{- 3}{\sqrt{9 - 9}}$

Step 4

Subtract

9

$9$ from

9

$9$ .

g (- 3) = \frac{- 3}{\sqrt{0}}

$g (- 3) = \frac{- 3}{\sqrt{0}}$

Step 5

Rewrite

0

$0$ as

0^{2}

$0^{2}$ .

g (- 3) = \frac{- 3}{\sqrt{0^{2}}}

$g (- 3) = \frac{- 3}{\sqrt{0^{2}}}$

Step 6

Pull terms out from under the radical, assuming positive real numbers.

g (- 3) = \frac{- 3}{0}

$g (- 3) = \frac{- 3}{0}$

Step 7

The expression contains a division by

0

$0$ . The expression is undefined.

Undefined