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Precalculus Examples
66 , 1212 , 2020 , 30 , 42 , 56
Step 1
Find the first level differences by finding the differences between consecutive terms.
6,8,10,12,14
Step 2
Find the second level difference by finding the differences between the first level differences. Because the second level difference is constant, the sequence is quadratic and given by an=an2+bn+c.
2
Step 3
Step 3.1
Set 2a equal to the constant second level difference 2.
2a=2
Step 3.2
Divide each term in 2a=2 by 2 and simplify.
Step 3.2.1
Divide each term in 2a=2 by 2.
2a2=22
Step 3.2.2
Simplify the left side.
Step 3.2.2.1
Cancel the common factor of 2.
Step 3.2.2.1.1
Cancel the common factor.
2a2=22
Step 3.2.2.1.2
Divide a by 1.
a=22
a=22
a=22
Step 3.2.3
Simplify the right side.
Step 3.2.3.1
Divide 2 by 2.
a=1
a=1
a=1
a=1
Step 4
Step 4.1
Set 3a+b equal to the first first level difference 6.
3a+b=6
Step 4.2
Substitute 1 for a.
3⋅1+b=6
Step 4.3
Multiply 3 by 1.
3+b=6
Step 4.4
Move all terms not containing b to the right side of the equation.
Step 4.4.1
Subtract 3 from both sides of the equation.
b=6-3
Step 4.4.2
Subtract 3 from 6.
b=3
b=3
b=3
Step 5
Step 5.1
Set a+b+c equal to the first term in the sequence 6.
a+b+c=6
Step 5.2
Substitute 1 for a and 3 for b.
1+3+c=6
Step 5.3
Add 1 and 3.
4+c=6
Step 5.4
Move all terms not containing c to the right side of the equation.
Step 5.4.1
Subtract 4 from both sides of the equation.
c=6-4
Step 5.4.2
Subtract 4 from 6.
c=2
c=2
c=2
Step 6
Substitute the values of a, b, and c into the quadratic sequence formula an=an2+bn+c.
an=1n2+3n+2
Step 7
Multiply n2 by 1.
an=n2+3n+2