Precalculus Examples

$5 x^{2} + 20 x + 5 y^{2} = 35$

Step 1

Divide both sides of the equation by $5$ .

$x^{2} + 4 x + y^{2} = 7$

Step 2

Complete the square for $x^{2} + 4 x$ .

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Step 2.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 4$

$c = 0$

Step 2.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 2.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 2.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{4}{2 \cdot 1}$

Step 2.3.2

Cancel the common factor of $4$ and $2$ .

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Step 2.3.2.1

Factor $2$ out of $4$ .

$d = \frac{2 \cdot 2}{2 \cdot 1}$

Step 2.3.2.2

Cancel the common factors.

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Step 2.3.2.2.1

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot 2}{2 (1)}$

Step 2.3.2.2.2

Cancel the common factor.

$d = \frac{2 \cdot 2}{2 \cdot 1}$

Step 2.3.2.2.3

Rewrite the expression.

$d = \frac{2}{1}$

Step 2.3.2.2.4

Divide $2$ by $1$ .

$d = 2$

Step 2.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 2.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{4^{2}}{4 \cdot 1}$

Step 2.4.2

Simplify the right side.

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Step 2.4.2.1

Simplify each term.

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Step 2.4.2.1.1

Cancel the common factor of $4^{2}$ and $4$ .

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Step 2.4.2.1.1.1

Factor $4$ out of $4^{2}$ .

$e = 0 - \frac{4 \cdot 4}{4 \cdot 1}$

Step 2.4.2.1.1.2

Cancel the common factors.

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Step 2.4.2.1.1.2.1

Factor $4$ out of $4 \cdot 1$ .

$e = 0 - \frac{4 \cdot 4}{4 (1)}$

Step 2.4.2.1.1.2.2

Cancel the common factor.

$e = 0 - \frac{4 \cdot 4}{4 \cdot 1}$

Step 2.4.2.1.1.2.3

Rewrite the expression.

$e = 0 - \frac{4}{1}$

Step 2.4.2.1.1.2.4

Divide $4$ by $1$ .

$e = 0 - 1 \cdot 4$

Step 2.4.2.1.2

Multiply $- 1$ by $4$ .

$e = 0 - 4$

Step 2.4.2.2

Subtract $4$ from $0$ .

$e = - 4$

Step 2.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + 2)}^{2} - 4$ .

${(x + 2)}^{2} - 4$

Step 3

Substitute ${(x + 2)}^{2} - 4$ for $x^{2} + 4 x$ in the equation $x^{2} + 4 x + y^{2} = 7$ .

${(x + 2)}^{2} - 4 + y^{2} = 7$

Step 4

Move $- 4$ to the right side of the equation by adding $4$ to both sides.

${(x + 2)}^{2} + y^{2} = 7 + 4$

Step 5

Add $7$ and $4$ .

${(x + 2)}^{2} + y^{2} = 11$