Precalculus Examples

$\sin (B) = 53 \frac{\sin (29.2 °)}{27}$

Step 1

Multiply $53$ by $\frac{\sin (29.2 °)}{27}$ .

$\sin (B) = 53 (\frac{\sin (29.2 °)}{27})$

Step 2

Simplify $53 (\frac{\sin (29.2 °)}{27})$ .

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Step 2.1

Evaluate $\sin (29.2 °)$ .

$\sin (B) = 53 (\frac{0.48785965}{27})$

Step 2.2

Divide $0.48785965$ by $27$ .

$\sin (B) = 53 \cdot 0.01806887$

Step 2.3

Multiply $53$ by $0.01806887$ .

$\sin (B) = 0.95765044$

Step 3

Take the inverse sine of both sides of the equation to extract $B$ from inside the sine.

$B = \arcsin (0.95765044)$

Step 4

Simplify the right side.

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Step 4.1

Evaluate $\arcsin (0.95765044)$ .

$B = 73.26572916$

Step 5

The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from $180$ to find the solution in the second quadrant.

$B = 180 - 73.26572916$

Step 6

Subtract $73.26572916$ from $180$ .

$B = 106.73427083$

Step 7

Find the period of $\sin (B)$ .

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Step 7.1

The period of the function can be calculated using $\frac{360}{| b |}$ .

$\frac{360}{| b |}$

Step 7.2

Replace $b$ with $1$ in the formula for period.

$\frac{360}{| 1 |}$

Step 7.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{360}{1}$

Step 7.4

Divide $360$ by $1$ .

$360$

Step 8

The period of the $\sin (B)$ function is $360$ so values will repeat every $360$ degrees in both directions.

$B = 73.26572916 + 360 n, 106.73427083 + 360 n$ , for any integer $n$