Precalculus Examples

$x^{3} - 34 x > 0$

Step 1

Convert the inequality to an equation.

$x^{3} - 34 x = 0$

Step 2

Factor $x$ out of $x^{3} - 34 x$ .

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Step 2.1

Factor $x$ out of $x^{3}$ .

$x \cdot x^{2} - 34 x = 0$

Step 2.2

Factor $x$ out of $- 34 x$ .

$x \cdot x^{2} + x \cdot - 34 = 0$

Step 2.3

Factor $x$ out of $x \cdot x^{2} + x \cdot - 34$ .

$x (x^{2} - 34) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x^{2} - 34 = 0$

Step 4

Set $x$ equal to $0$ .

$x = 0$

Step 5

Set $x^{2} - 34$ equal to $0$ and solve for $x$ .

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Step 5.1

Set $x^{2} - 34$ equal to $0$ .

$x^{2} - 34 = 0$

Step 5.2

Solve $x^{2} - 34 = 0$ for $x$ .

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Step 5.2.1

Add $34$ to both sides of the equation.

$x^{2} = 34$

Step 5.2.2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{34}$

Step 5.2.3

The complete solution is the result of both the positive and negative portions of the solution.

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Step 5.2.3.1

First, use the positive value of the $\pm$ to find the first solution.

$x = \sqrt{34}$

Step 5.2.3.2

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \sqrt{34}$

Step 5.2.3.3

The complete solution is the result of both the positive and negative portions of the solution.

$x = \sqrt{34}, - \sqrt{34}$

Step 6

The final solution is all the values that make $x (x^{2} - 34) = 0$ true.

$x = 0, \sqrt{34}, - \sqrt{34}$

Step 7

Use each root to create test intervals.

$x < - \sqrt{34}$

$- \sqrt{34} < x < 0$

$0 < x < \sqrt{34}$

$x > \sqrt{34}$

Step 8

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

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Step 8.1

Test a value on the interval $x < - \sqrt{34}$ to see if it makes the inequality true.

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Step 8.1.1

Choose a value on the interval $x < - \sqrt{34}$ and see if this value makes the original inequality true.

$x = - 8$

Step 8.1.2

Replace $x$ with $- 8$ in the original inequality.

${(- 8)}^{3} - 34 \cdot - 8 > 0$

Step 8.1.3

The left side $- 240$ is not greater than the right side $0$ , which means that the given statement is false.

False

Step 8.2

Test a value on the interval $- \sqrt{34} < x < 0$ to see if it makes the inequality true.

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Step 8.2.1

Choose a value on the interval $- \sqrt{34} < x < 0$ and see if this value makes the original inequality true.

$x = - 3$

Step 8.2.2

Replace $x$ with $- 3$ in the original inequality.

${(- 3)}^{3} - 34 \cdot - 3 > 0$

Step 8.2.3

The left side $75$ is greater than the right side $0$ , which means that the given statement is always true.

True

Step 8.3

Test a value on the interval $0 < x < \sqrt{34}$ to see if it makes the inequality true.

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Step 8.3.1

Choose a value on the interval $0 < x < \sqrt{34}$ and see if this value makes the original inequality true.

$x = 3$

Step 8.3.2

Replace $x$ with $3$ in the original inequality.

${(3)}^{3} - 34 \cdot 3 > 0$

Step 8.3.3

The left side $- 75$ is not greater than the right side $0$ , which means that the given statement is false.

False

Step 8.4

Test a value on the interval $x > \sqrt{34}$ to see if it makes the inequality true.

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Step 8.4.1

Choose a value on the interval $x > \sqrt{34}$ and see if this value makes the original inequality true.

$x = 8$

Step 8.4.2

Replace $x$ with $8$ in the original inequality.

${(8)}^{3} - 34 \cdot 8 > 0$

Step 8.4.3

The left side $240$ is greater than the right side $0$ , which means that the given statement is always true.

True

Step 8.5

Compare the intervals to determine which ones satisfy the original inequality.

$x < - \sqrt{34}$ False

$- \sqrt{34} < x < 0$ True

$0 < x < \sqrt{34}$ False

$x > \sqrt{34}$ True

$x < - \sqrt{34}$ False

$- \sqrt{34} < x < 0$ True

$0 < x < \sqrt{34}$ False

$x > \sqrt{34}$ True

Step 9

The solution consists of all of the true intervals.

$- \sqrt{34} < x < 0$ or $x > \sqrt{34}$

Step 10

Convert the inequality to interval notation.

$(- \sqrt{34}, 0) \cup (\sqrt{34}, \infty)$

Step 11