Precalculus Examples

$\frac{5 x^{2}}{{(x - 2)}^{2} {(x + 2)}^{2}}$

Step 1

Decompose the fraction and multiply through by the common denominator.

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Step 1.1

For each factor in the denominator, create a new fraction using the factor as the denominator, and an unknown value as the numerator. Since the factor in the denominator is linear, put a single variable in its place $A$ .

$\frac{A}{{(x - 2)}^{2}}$

Step 1.2

$\frac{A}{{(x - 2)}^{2}} + \frac{B}{x - 2}$

Step 1.3

$\frac{A}{{(x - 2)}^{2}} + \frac{B}{x - 2} + \frac{C}{{(x + 2)}^{2}}$

Step 1.4

$\frac{A}{{(x - 2)}^{2}} + \frac{B}{x - 2} + \frac{C}{{(x + 2)}^{2}} + \frac{D}{x + 2}$

Step 1.5

Multiply each fraction in the equation by the denominator of the original expression. In this case, the denominator is ${(x - 2)}^{2} {(x + 2)}^{2}$ .

$\frac{5 x^{2} {(x - 2)}^{2} {(x + 2)}^{2}}{{(x - 2)}^{2} {(x + 2)}^{2}} = \frac{(A) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x - 2)}^{2}} + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.6

Cancel the common factor of ${(x - 2)}^{2}$ .

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Step 1.6.1

Cancel the common factor.

Step 1.6.2

Rewrite the expression.

$\frac{5 x^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} = \frac{(A) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x - 2)}^{2}} + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.7

Cancel the common factor of ${(x + 2)}^{2}$ .

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Step 1.7.1

Cancel the common factor.

Step 1.7.2

Divide $5 x^{2}$ by $1$ .

$5 x^{2} = \frac{(A) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x - 2)}^{2}} + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8

Simplify each term.

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Step 1.8.1

Cancel the common factor of ${(x - 2)}^{2}$ .

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Step 1.8.1.1

Cancel the common factor.

$5 x^{2} = \frac{A {(x - 2)}^{2} {(x + 2)}^{2}}{{(x - 2)}^{2}} + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.1.2

Divide $(A) {(x + 2)}^{2}$ by $1$ .

$5 x^{2} = (A) {(x + 2)}^{2} + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.2

Rewrite ${(x + 2)}^{2}$ as $(x + 2) (x + 2)$ .

$5 x^{2} = A ((x + 2) (x + 2)) + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.3

Expand $(x + 2) (x + 2)$ using the FOIL Method.

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Step 1.8.3.1

Apply the distributive property.

$5 x^{2} = A (x (x + 2) + 2 (x + 2)) + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.3.2

Apply the distributive property.

$5 x^{2} = A (x \cdot x + x \cdot 2 + 2 (x + 2)) + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.3.3

Apply the distributive property.

$5 x^{2} = A (x \cdot x + x \cdot 2 + 2 x + 2 \cdot 2) + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.4

Simplify and combine like terms.

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Step 1.8.4.1

Simplify each term.

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Step 1.8.4.1.1

Multiply $x$ by $x$ .

$5 x^{2} = A (x^{2} + x \cdot 2 + 2 x + 2 \cdot 2) + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.4.1.2

Move $2$ to the left of $x$ .

$5 x^{2} = A (x^{2} + 2 \cdot x + 2 x + 2 \cdot 2) + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.4.1.3

Multiply $2$ by $2$ .

$5 x^{2} = A (x^{2} + 2 x + 2 x + 4) + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.4.2

Add $2 x$ and $2 x$ .

$5 x^{2} = A (x^{2} + 4 x + 4) + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.5

Apply the distributive property.

$5 x^{2} = A x^{2} + A (4 x) + A \cdot 4 + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.6

Simplify.

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Step 1.8.6.1

Rewrite using the commutative property of multiplication.

$5 x^{2} = A x^{2} + 4 A x + A \cdot 4 + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.6.2

Move $4$ to the left of $A$ .

$5 x^{2} = A x^{2} + 4 A x + 4 \cdot A + \frac{(B) {(x - 2)}^{2} {(x + 2)}^{2}}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.7

Cancel the common factor of ${(x - 2)}^{2}$ and $x - 2$ .

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Step 1.8.7.1

Factor $x - 2$ out of $(B) {(x - 2)}^{2} {(x + 2)}^{2}$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + \frac{(x - 2) (B (x - 2) {(x + 2)}^{2})}{x - 2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.7.2

Cancel the common factors.

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Step 1.8.7.2.1

Multiply by $1$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + \frac{(x - 2) (B (x - 2) {(x + 2)}^{2})}{(x - 2) \cdot 1} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.7.2.2

Cancel the common factor.

$5 x^{2} = A x^{2} + 4 A x + 4 A + \frac{(x - 2) (B (x - 2) {(x + 2)}^{2})}{(x - 2) \cdot 1} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.7.2.3

Rewrite the expression.

$5 x^{2} = A x^{2} + 4 A x + 4 A + \frac{B (x - 2) {(x + 2)}^{2}}{1} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.7.2.4

Divide $B (x - 2) {(x + 2)}^{2}$ by $1$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B (x - 2) {(x + 2)}^{2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.8

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x + B \cdot - 2) {(x + 2)}^{2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.9

Move $- 2$ to the left of $B$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 \cdot B) {(x + 2)}^{2} + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.10

Rewrite ${(x + 2)}^{2}$ as $(x + 2) (x + 2)$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 B) ((x + 2) (x + 2)) + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.11

Expand $(x + 2) (x + 2)$ using the FOIL Method.

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Step 1.8.11.1

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 B) (x (x + 2) + 2 (x + 2)) + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.11.2

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 B) (x \cdot x + x \cdot 2 + 2 (x + 2)) + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.11.3

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 B) (x \cdot x + x \cdot 2 + 2 x + 2 \cdot 2) + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.12

Simplify and combine like terms.

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Step 1.8.12.1

Simplify each term.

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Step 1.8.12.1.1

Multiply $x$ by $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 B) (x^{2} + x \cdot 2 + 2 x + 2 \cdot 2) + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.12.1.2

Move $2$ to the left of $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 B) (x^{2} + 2 \cdot x + 2 x + 2 \cdot 2) + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.12.1.3

Multiply $2$ by $2$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 B) (x^{2} + 2 x + 2 x + 4) + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.12.2

Add $2 x$ and $2 x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + (B x - 2 B) (x^{2} + 4 x + 4) + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.13

Expand $(B x - 2 B) (x^{2} + 4 x + 4)$ by multiplying each term in the first expression by each term in the second expression.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x \cdot x^{2} + B x (4 x) + B x \cdot 4 - 2 B x^{2} - 2 B (4 x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14

Simplify each term.

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Step 1.8.14.1

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 1.8.14.1.1

Move $x^{2}$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B (x^{2} x) + B x (4 x) + B x \cdot 4 - 2 B x^{2} - 2 B (4 x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.1.2

Multiply $x^{2}$ by $x$ .

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Step 1.8.14.1.2.1

Raise $x$ to the power of $1$ .

Step 1.8.14.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{2 + 1} + B x (4 x) + B x \cdot 4 - 2 B x^{2} - 2 B (4 x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.1.3

Add $2$ and $1$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + B x (4 x) + B x \cdot 4 - 2 B x^{2} - 2 B (4 x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.2

Rewrite using the commutative property of multiplication.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 4 B x \cdot x + B x \cdot 4 - 2 B x^{2} - 2 B (4 x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.3

Multiply $x$ by $x$ by adding the exponents.

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Step 1.8.14.3.1

Move $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 4 B (x \cdot x) + B x \cdot 4 - 2 B x^{2} - 2 B (4 x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.3.2

Multiply $x$ by $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 4 B x^{2} + B x \cdot 4 - 2 B x^{2} - 2 B (4 x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.4

Move $4$ to the left of $B x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 4 B x^{2} + 4 \cdot (B x) - 2 B x^{2} - 2 B (4 x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.5

Rewrite using the commutative property of multiplication.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 4 B x^{2} + 4 B x - 2 B x^{2} - 2 \cdot (4 B x) - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.6

Multiply $- 2$ by $4$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 4 B x^{2} + 4 B x - 2 B x^{2} - 8 B x - 2 B \cdot 4 + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.14.7

Multiply $4$ by $- 2$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 4 B x^{2} + 4 B x - 2 B x^{2} - 8 B x - 8 B + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.15

Subtract $2 B x^{2}$ from $4 B x^{2}$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} + 4 B x - 8 B x - 8 B + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.16

Subtract $8 B x$ from $4 B x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.17

Cancel the common factor of ${(x + 2)}^{2}$ .

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Step 1.8.17.1

Cancel the common factor.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + \frac{(C) {(x - 2)}^{2} {(x + 2)}^{2}}{{(x + 2)}^{2}} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.17.2

Divide $(C) {(x - 2)}^{2}$ by $1$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + (C) {(x - 2)}^{2} + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.18

Rewrite ${(x - 2)}^{2}$ as $(x - 2) (x - 2)$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C ((x - 2) (x - 2)) + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.19

Expand $(x - 2) (x - 2)$ using the FOIL Method.

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Step 1.8.19.1

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C (x (x - 2) - 2 (x - 2)) + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.19.2

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C (x \cdot x + x \cdot - 2 - 2 (x - 2)) + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.19.3

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C (x \cdot x + x \cdot - 2 - 2 x - 2 \cdot - 2) + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.20

Simplify and combine like terms.

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Step 1.8.20.1

Simplify each term.

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Step 1.8.20.1.1

Multiply $x$ by $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C (x^{2} + x \cdot - 2 - 2 x - 2 \cdot - 2) + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.20.1.2

Move $- 2$ to the left of $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C (x^{2} - 2 \cdot x - 2 x - 2 \cdot - 2) + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.20.1.3

Multiply $- 2$ by $- 2$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C (x^{2} - 2 x - 2 x + 4) + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.20.2

Subtract $2 x$ from $- 2 x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C (x^{2} - 4 x + 4) + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.21

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} + C (- 4 x) + C \cdot 4 + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.22

Simplify.

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Step 1.8.22.1

Rewrite using the commutative property of multiplication.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + C \cdot 4 + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.22.2

Move $4$ to the left of $C$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 \cdot C + \frac{(D) {(x - 2)}^{2} {(x + 2)}^{2}}{x + 2}$

Step 1.8.23

Cancel the common factor of ${(x + 2)}^{2}$ and $x + 2$ .

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Step 1.8.23.1

Factor $x + 2$ out of $(D) {(x - 2)}^{2} {(x + 2)}^{2}$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + \frac{(x + 2) ((D) {(x - 2)}^{2} (x + 2))}{x + 2}$

Step 1.8.23.2

Cancel the common factors.

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Step 1.8.23.2.1

Multiply by $1$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + \frac{(x + 2) ((D) {(x - 2)}^{2} (x + 2))}{(x + 2) \cdot 1}$

Step 1.8.23.2.2

Cancel the common factor.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + \frac{(x + 2) ((D) {(x - 2)}^{2} (x + 2))}{(x + 2) \cdot 1}$

Step 1.8.23.2.3

Rewrite the expression.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + \frac{(D) {(x - 2)}^{2} (x + 2)}{1}$

Step 1.8.23.2.4

Divide $(D) {(x - 2)}^{2} (x + 2)$ by $1$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + (D) {(x - 2)}^{2} (x + 2)$

Step 1.8.24

Rewrite ${(x - 2)}^{2}$ as $(x - 2) (x - 2)$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D ((x - 2) (x - 2)) (x + 2)$

Step 1.8.25

Expand $(x - 2) (x - 2)$ using the FOIL Method.

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Step 1.8.25.1

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x (x - 2) - 2 (x - 2)) (x + 2)$

Step 1.8.25.2

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x \cdot x + x \cdot - 2 - 2 (x - 2)) (x + 2)$

Step 1.8.25.3

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x \cdot x + x \cdot - 2 - 2 x - 2 \cdot - 2) (x + 2)$

Step 1.8.26

Simplify and combine like terms.

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Step 1.8.26.1

Simplify each term.

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Step 1.8.26.1.1

Multiply $x$ by $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x^{2} + x \cdot - 2 - 2 x - 2 \cdot - 2) (x + 2)$

Step 1.8.26.1.2

Move $- 2$ to the left of $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x^{2} - 2 \cdot x - 2 x - 2 \cdot - 2) (x + 2)$

Step 1.8.26.1.3

Multiply $- 2$ by $- 2$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x^{2} - 2 x - 2 x + 4) (x + 2)$

Step 1.8.26.2

Subtract $2 x$ from $- 2 x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x^{2} - 4 x + 4) (x + 2)$

Step 1.8.27

Apply the distributive property.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + (D x^{2} + D (- 4 x) + D \cdot 4) (x + 2)$

Step 1.8.28

Simplify.

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Step 1.8.28.1

Rewrite using the commutative property of multiplication.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + (D x^{2} - 4 D x + D \cdot 4) (x + 2)$

Step 1.8.28.2

Move $4$ to the left of $D$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + (D x^{2} - 4 D x + 4 \cdot D) (x + 2)$

Step 1.8.29

Expand $(D x^{2} - 4 D x + 4 D) (x + 2)$ by multiplying each term in the first expression by each term in the second expression.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{2} x + D x^{2} \cdot 2 - 4 D x \cdot x - 4 D x \cdot 2 + 4 D x + 4 D \cdot 2$

Step 1.8.30

Simplify each term.

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Step 1.8.30.1

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 1.8.30.1.1

Move $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x \cdot x^{2}) + D x^{2} \cdot 2 - 4 D x \cdot x - 4 D x \cdot 2 + 4 D x + 4 D \cdot 2$

Step 1.8.30.1.2

Multiply $x$ by $x^{2}$ .

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Step 1.8.30.1.2.1

Raise $x$ to the power of $1$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D (x \cdot x^{2}) + D x^{2} \cdot 2 - 4 D x \cdot x - 4 D x \cdot 2 + 4 D x + 4 D \cdot 2$

Step 1.8.30.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{1 + 2} + D x^{2} \cdot 2 - 4 D x \cdot x - 4 D x \cdot 2 + 4 D x + 4 D \cdot 2$

Step 1.8.30.1.3

Add $1$ and $2$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} + D x^{2} \cdot 2 - 4 D x \cdot x - 4 D x \cdot 2 + 4 D x + 4 D \cdot 2$

Step 1.8.30.2

Move $2$ to the left of $D x^{2}$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} + 2 \cdot (D x^{2}) - 4 D x \cdot x - 4 D x \cdot 2 + 4 D x + 4 D \cdot 2$

Step 1.8.30.3

Multiply $x$ by $x$ by adding the exponents.

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Step 1.8.30.3.1

Move $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} + 2 D x^{2} - 4 D (x \cdot x) - 4 D x \cdot 2 + 4 D x + 4 D \cdot 2$

Step 1.8.30.3.2

Multiply $x$ by $x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} + 2 D x^{2} - 4 D x^{2} - 4 D x \cdot 2 + 4 D x + 4 D \cdot 2$

Step 1.8.30.4

Multiply $2$ by $- 4$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} + 2 D x^{2} - 4 D x^{2} - 8 D x + 4 D x + 4 D \cdot 2$

Step 1.8.30.5

Multiply $2$ by $4$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} + 2 D x^{2} - 4 D x^{2} - 8 D x + 4 D x + 8 D$

Step 1.8.31

Subtract $4 D x^{2}$ from $2 D x^{2}$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} - 2 D x^{2} - 8 D x + 4 D x + 8 D$

Step 1.8.32

Add $- 8 D x$ and $4 D x$ .

$5 x^{2} = A x^{2} + 4 A x + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} - 2 D x^{2} - 4 D x + 8 D$

Step 1.9

Simplify the expression.

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Step 1.9.1

Move $A$ .

$5 x^{2} = A x^{2} + 4 x A + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} - 2 D x^{2} - 4 D x + 8 D$

Step 1.9.2

Reorder $B$ and $x^{3}$ .

$5 x^{2} = A x^{2} + 4 x A + 4 A + B x^{3} + 2 B x^{2} - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} - 2 D x^{2} - 4 D x + 8 D$

Step 1.9.3

Move $B$ .

$5 x^{2} = A x^{2} + 4 x A + 4 A + B x^{3} + 2 x^{2} B - 4 B x - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} - 2 D x^{2} - 4 D x + 8 D$

Step 1.9.4

Move $B$ .

$5 x^{2} = A x^{2} + 4 x A + 4 A + B x^{3} + 2 x^{2} B - 4 x B - 8 B + C x^{2} - 4 C x + 4 C + D x^{3} - 2 D x^{2} - 4 D x + 8 D$

Step 1.9.5

Move $4 C$ .

$5 x^{2} = A x^{2} + 4 x A + 4 A + B x^{3} + 2 x^{2} B - 4 x B - 8 B + C x^{2} - 4 C x + D x^{3} - 2 D x^{2} - 4 D x + 4 C + 8 D$

Step 1.9.6

Move $- 8 B$ .

$5 x^{2} = A x^{2} + 4 x A + 4 A + B x^{3} + 2 x^{2} B - 4 x B + C x^{2} - 4 C x + D x^{3} - 2 D x^{2} - 4 D x - 8 B + 4 C + 8 D$

Step 1.9.7

Move $4 A$ .

$5 x^{2} = A x^{2} + 4 x A + B x^{3} + 2 x^{2} B - 4 x B + C x^{2} - 4 C x + D x^{3} - 2 D x^{2} - 4 D x + 4 A - 8 B + 4 C + 8 D$

Step 1.9.8

Move $- 4 C x$ .

$5 x^{2} = A x^{2} + 4 x A + B x^{3} + 2 x^{2} B - 4 x B + C x^{2} + D x^{3} - 2 D x^{2} - 4 C x - 4 D x + 4 A - 8 B + 4 C + 8 D$

Step 1.9.9

Move $- 4 x B$ .

$5 x^{2} = A x^{2} + 4 x A + B x^{3} + 2 x^{2} B + C x^{2} + D x^{3} - 2 D x^{2} - 4 x B - 4 C x - 4 D x + 4 A - 8 B + 4 C + 8 D$

Step 1.9.10

Move $4 x A$ .

$5 x^{2} = A x^{2} + B x^{3} + 2 x^{2} B + C x^{2} + D x^{3} - 2 D x^{2} + 4 x A - 4 x B - 4 C x - 4 D x + 4 A - 8 B + 4 C + 8 D$

Step 1.9.11

Move $C x^{2}$ .

$5 x^{2} = A x^{2} + B x^{3} + 2 x^{2} B + D x^{3} + C x^{2} - 2 D x^{2} + 4 x A - 4 x B - 4 C x - 4 D x + 4 A - 8 B + 4 C + 8 D$

Step 1.9.12

Move $2 x^{2} B$ .

$5 x^{2} = A x^{2} + B x^{3} + D x^{3} + 2 x^{2} B + C x^{2} - 2 D x^{2} + 4 x A - 4 x B - 4 C x - 4 D x + 4 A - 8 B + 4 C + 8 D$

Step 1.9.13

Move $A x^{2}$ .

$5 x^{2} = B x^{3} + D x^{3} + A x^{2} + 2 x^{2} B + C x^{2} - 2 D x^{2} + 4 x A - 4 x B - 4 C x - 4 D x + 4 A - 8 B + 4 C + 8 D$

Step 2

Create equations for the partial fraction variables and use them to set up a system of equations.

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Step 2.1

Create an equation for the partial fraction variables by equating the coefficients of $x^{3}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = B + D$

Step 2.2

Create an equation for the partial fraction variables by equating the coefficients of $x^{2}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$5 = A + 2 B + C - 2 D$

Step 2.3

Create an equation for the partial fraction variables by equating the coefficients of $x$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = 4 A - 4 B - 4 C - 4 D$

Step 2.4

Create an equation for the partial fraction variables by equating the coefficients of the terms not containing $x$ . For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = 4 A - 8 B + 4 C + 8 D$

Step 2.5

Set up the system of equations to find the coefficients of the partial fractions.

$0 = B + D$

$5 = A + 2 B + C - 2 D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

$0 = B + D$

$5 = A + 2 B + C - 2 D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3

Solve the system of equations.

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Step 3.1

Solve for $B$ in $0 = B + D$ .

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Step 3.1.1

Rewrite the equation as $B + D = 0$ .

$B + D = 0$

$5 = A + 2 B + C - 2 D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.1.2

Subtract $D$ from both sides of the equation.

$B = - D$

$5 = A + 2 B + C - 2 D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

$B = - D$

$5 = A + 2 B + C - 2 D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.2

Replace all occurrences of $B$ with $- D$ in each equation.

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Step 3.2.1

Replace all occurrences of $B$ in $5 = A + 2 B + C - 2 D$ with $- D$ .

$5 = A + 2 (- D) + C - 2 D$

$B = - D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Simplify $A + 2 (- D) + C - 2 D$ .

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Step 3.2.2.1.1

Multiply $- 1$ by $2$ .

$5 = A - 2 D + C - 2 D$

$B = - D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.2.2.1.2

Subtract $2 D$ from $- 2 D$ .

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 4 B - 4 C - 4 D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.2.3

Replace all occurrences of $B$ in $0 = 4 A - 4 B - 4 C - 4 D$ with $- D$ .

$0 = 4 A - 4 (- D) - 4 C - 4 D$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.2.4

Simplify the right side.

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Step 3.2.4.1

Simplify $4 A - 4 (- D) - 4 C - 4 D$ .

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Step 3.2.4.1.1

Multiply $- 1$ by $- 4$ .

$0 = 4 A + 4 D - 4 C - 4 D$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.2.4.1.2

Combine the opposite terms in $4 A + 4 D - 4 C - 4 D$ .

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Step 3.2.4.1.2.1

Subtract $4 D$ from $4 D$ .

$0 = 4 A - 4 C + 0$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.2.4.1.2.2

Add $4 A - 4 C$ and $0$ .

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 8 B + 4 C + 8 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 8 B + 4 C + 8 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 8 B + 4 C + 8 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A - 8 B + 4 C + 8 D$

Step 3.2.5

Replace all occurrences of $B$ in $0 = 4 A - 8 B + 4 C + 8 D$ with $- D$ .

$0 = 4 A - 8 (- D) + 4 C + 8 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

Step 3.2.6

Simplify the right side.

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Step 3.2.6.1

Simplify $4 A - 8 (- D) + 4 C + 8 D$ .

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Step 3.2.6.1.1

Multiply $- 1$ by $- 8$ .

$0 = 4 A + 8 D + 4 C + 8 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

Step 3.2.6.1.2

Add $8 D$ and $8 D$ .

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$5 = A + C - 4 D$

$B = - D$

Step 3.3

Solve for $A$ in $5 = A + C - 4 D$ .

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Step 3.3.1

Rewrite the equation as $A + C - 4 D = 5$ .

$A + C - 4 D = 5$

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.3.2

Move all terms not containing $A$ to the right side of the equation.

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Step 3.3.2.1

Subtract $C$ from both sides of the equation.

$A - 4 D = 5 - C$

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.3.2.2

Add $4 D$ to both sides of the equation.

$A = 5 - C + 4 D$

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$B = - D$

$A = 5 - C + 4 D$

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$B = - D$

$A = 5 - C + 4 D$

$0 = 4 A + 4 C + 16 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4

Replace all occurrences of $A$ with $5 - C + 4 D$ in each equation.

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Step 3.4.1

Replace all occurrences of $A$ in $0 = 4 A + 4 C + 16 D$ with $5 - C + 4 D$ .

$0 = 4 (5 - C + 4 D) + 4 C + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4.2

Simplify the right side.

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Step 3.4.2.1

Simplify $4 (5 - C + 4 D) + 4 C + 16 D$ .

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Step 3.4.2.1.1

Simplify each term.

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Step 3.4.2.1.1.1

Apply the distributive property.

$0 = 4 \cdot 5 + 4 (- C) + 4 (4 D) + 4 C + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4.2.1.1.2

Simplify.

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Step 3.4.2.1.1.2.1

Multiply $4$ by $5$ .

$0 = 20 + 4 (- C) + 4 (4 D) + 4 C + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4.2.1.1.2.2

Multiply $- 1$ by $4$ .

$0 = 20 - 4 C + 4 (4 D) + 4 C + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4.2.1.1.2.3

Multiply $4$ by $4$ .

$0 = 20 - 4 C + 16 D + 4 C + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

$0 = 20 - 4 C + 16 D + 4 C + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

$0 = 20 - 4 C + 16 D + 4 C + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4.2.1.2

Simplify by adding terms.

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Step 3.4.2.1.2.1

Combine the opposite terms in $20 - 4 C + 16 D + 4 C + 16 D$ .

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Step 3.4.2.1.2.1.1

Add $- 4 C$ and $4 C$ .

$0 = 20 + 16 D + 0 + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4.2.1.2.1.2

Add $20 + 16 D$ and $0$ .

$0 = 20 + 16 D + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

$0 = 20 + 16 D + 16 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4.2.1.2.2

Add $16 D$ and $16 D$ .

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$0 = 4 A - 4 C$

$B = - D$

Step 3.4.3

Replace all occurrences of $A$ in $0 = 4 A - 4 C$ with $5 - C + 4 D$ .

$0 = 4 (5 - C + 4 D) - 4 C$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.4.4

Simplify the right side.

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Step 3.4.4.1

Simplify $4 (5 - C + 4 D) - 4 C$ .

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Step 3.4.4.1.1

Simplify each term.

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Step 3.4.4.1.1.1

Apply the distributive property.

$0 = 4 \cdot 5 + 4 (- C) + 4 (4 D) - 4 C$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.4.4.1.1.2

Simplify.

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Step 3.4.4.1.1.2.1

Multiply $4$ by $5$ .

$0 = 20 + 4 (- C) + 4 (4 D) - 4 C$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.4.4.1.1.2.2

Multiply $- 1$ by $4$ .

$0 = 20 - 4 C + 4 (4 D) - 4 C$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.4.4.1.1.2.3

Multiply $4$ by $4$ .

$0 = 20 - 4 C + 16 D - 4 C$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

$0 = 20 - 4 C + 16 D - 4 C$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

$0 = 20 - 4 C + 16 D - 4 C$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.4.4.1.2

Subtract $4 C$ from $- 4 C$ .

$0 = 20 - 8 C + 16 D$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

$0 = 20 - 8 C + 16 D$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

$0 = 20 - 8 C + 16 D$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

$0 = 20 - 8 C + 16 D$

$0 = 20 + 32 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5

Solve for $D$ in $0 = 20 + 32 D$ .

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Step 3.5.1

Rewrite the equation as $20 + 32 D = 0$ .

$20 + 32 D = 0$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.2

Subtract $20$ from both sides of the equation.

$32 D = - 20$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.3

Divide each term in $32 D = - 20$ by $32$ and simplify.

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Step 3.5.3.1

Divide each term in $32 D = - 20$ by $32$ .

$\frac{32 D}{32} = \frac{- 20}{32}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.3.2

Simplify the left side.

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Step 3.5.3.2.1

Cancel the common factor of $32$ .

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Step 3.5.3.2.1.1

Cancel the common factor.

$\frac{32 D}{32} = \frac{- 20}{32}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.3.2.1.2

Divide $D$ by $1$ .

$D = \frac{- 20}{32}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

$D = \frac{- 20}{32}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

$D = \frac{- 20}{32}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.3.3

Simplify the right side.

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Step 3.5.3.3.1

Cancel the common factor of $- 20$ and $32$ .

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Step 3.5.3.3.1.1

Factor $4$ out of $- 20$ .

$D = \frac{4 (- 5)}{32}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.3.3.1.2

Cancel the common factors.

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Step 3.5.3.3.1.2.1

Factor $4$ out of $32$ .

$D = \frac{4 \cdot - 5}{4 \cdot 8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.3.3.1.2.2

Cancel the common factor.

$D = \frac{4 \cdot - 5}{4 \cdot 8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.3.3.1.2.3

Rewrite the expression.

$D = \frac{- 5}{8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

$D = \frac{- 5}{8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

$D = \frac{- 5}{8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.5.3.3.2

Move the negative in front of the fraction.

$D = - \frac{5}{8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

$D = - \frac{5}{8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

$D = - \frac{5}{8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

$D = - \frac{5}{8}$

$0 = 20 - 8 C + 16 D$

$A = 5 - C + 4 D$

$B = - D$

Step 3.6

Replace all occurrences of $D$ with $- \frac{5}{8}$ in each equation.

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Step 3.6.1

Replace all occurrences of $D$ in $0 = 20 - 8 C + 16 D$ with $- \frac{5}{8}$ .

$0 = 20 - 8 C + 16 (- \frac{5}{8})$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

Step 3.6.2

Simplify the right side.

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Step 3.6.2.1

Simplify $20 - 8 C + 16 (- \frac{5}{8})$ .

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Step 3.6.2.1.1

Simplify each term.

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Step 3.6.2.1.1.1

Cancel the common factor of $8$ .

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Step 3.6.2.1.1.1.1

Move the leading negative in $- \frac{5}{8}$ into the numerator.

$0 = 20 - 8 C + 16 (\frac{- 5}{8})$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

Step 3.6.2.1.1.1.2

Factor $8$ out of $16$ .

$0 = 20 - 8 C + 8 (2) (\frac{- 5}{8})$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

Step 3.6.2.1.1.1.3

Cancel the common factor.

$0 = 20 - 8 C + 8 \cdot (2 (\frac{- 5}{8}))$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

Step 3.6.2.1.1.1.4

Rewrite the expression.

$0 = 20 - 8 C + 2 \cdot - 5$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

$0 = 20 - 8 C + 2 \cdot - 5$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

Step 3.6.2.1.1.2

Multiply $2$ by $- 5$ .

$0 = 20 - 8 C - 10$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

$0 = 20 - 8 C - 10$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

Step 3.6.2.1.2

Subtract $10$ from $20$ .

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$A = 5 - C + 4 D$

$B = - D$

Step 3.6.3

Replace all occurrences of $D$ in $A = 5 - C + 4 D$ with $- \frac{5}{8}$ .

$A = 5 - C + 4 (- \frac{5}{8})$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4

Simplify the right side.

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Step 3.6.4.1

Simplify $5 - C + 4 (- \frac{5}{8})$ .

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Step 3.6.4.1.1

Simplify each term.

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Step 3.6.4.1.1.1

Cancel the common factor of $4$ .

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Step 3.6.4.1.1.1.1

Move the leading negative in $- \frac{5}{8}$ into the numerator.

$A = 5 - C + 4 (\frac{- 5}{8})$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.1.1.2

Factor $4$ out of $8$ .

$A = 5 - C + 4 (\frac{- 5}{4 (2)})$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.1.1.3

Cancel the common factor.

$A = 5 - C + 4 (\frac{- 5}{4 \cdot 2})$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.1.1.4

Rewrite the expression.

$A = 5 - C + \frac{- 5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

$A = 5 - C + \frac{- 5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.1.2

Move the negative in front of the fraction.

$A = 5 - C - \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

$A = 5 - C - \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.2

To write $5$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$A = - C + 5 \cdot \frac{2}{2} - \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.3

Combine $5$ and $\frac{2}{2}$ .

$A = - C + \frac{5 \cdot 2}{2} - \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.4

Combine the numerators over the common denominator.

$A = - C + \frac{5 \cdot 2 - 5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.5

Simplify the numerator.

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Step 3.6.4.1.5.1

Multiply $5$ by $2$ .

$A = - C + \frac{10 - 5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.4.1.5.2

Subtract $5$ from $10$ .

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = - D$

Step 3.6.5

Replace all occurrences of $D$ in $B = - D$ with $- \frac{5}{8}$ .

$B = - (- \frac{5}{8})$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

Step 3.6.6

Simplify the right side.

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Step 3.6.6.1

Multiply $- (- \frac{5}{8})$ .

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Step 3.6.6.1.1

Multiply $- 1$ by $- 1$ .

$B = 1 (\frac{5}{8})$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

Step 3.6.6.1.2

Multiply $\frac{5}{8}$ by $1$ .

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$0 = - 8 C + 10$

$D = - \frac{5}{8}$

Step 3.7

Solve for $C$ in $0 = - 8 C + 10$ .

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Step 3.7.1

Rewrite the equation as $- 8 C + 10 = 0$ .

$- 8 C + 10 = 0$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.7.2

Subtract $10$ from both sides of the equation.

$- 8 C = - 10$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.7.3

Divide each term in $- 8 C = - 10$ by $- 8$ and simplify.

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Step 3.7.3.1

Divide each term in $- 8 C = - 10$ by $- 8$ .

$\frac{- 8 C}{- 8} = \frac{- 10}{- 8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.7.3.2

Simplify the left side.

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Step 3.7.3.2.1

Cancel the common factor of $- 8$ .

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Step 3.7.3.2.1.1

Cancel the common factor.

$\frac{- 8 C}{- 8} = \frac{- 10}{- 8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.7.3.2.1.2

Divide $C$ by $1$ .

$C = \frac{- 10}{- 8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

$C = \frac{- 10}{- 8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

$C = \frac{- 10}{- 8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.7.3.3

Simplify the right side.

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Step 3.7.3.3.1

Cancel the common factor of $- 10$ and $- 8$ .

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Step 3.7.3.3.1.1

Factor $- 2$ out of $- 10$ .

$C = \frac{- 2 \cdot 5}{- 8}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.7.3.3.1.2

Cancel the common factors.

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Step 3.7.3.3.1.2.1

Factor $- 2$ out of $- 8$ .

$C = \frac{- 2 \cdot 5}{- 2 \cdot 4}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.7.3.3.1.2.2

Cancel the common factor.

$C = \frac{- 2 \cdot 5}{- 2 \cdot 4}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.7.3.3.1.2.3

Rewrite the expression.

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$A = - C + \frac{5}{2}$

$D = - \frac{5}{8}$

Step 3.8

Replace all occurrences of $C$ with $\frac{5}{4}$ in each equation.

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Step 3.8.1

Replace all occurrences of $C$ in $A = - C + \frac{5}{2}$ with $\frac{5}{4}$ .

$A = - (\frac{5}{4}) + \frac{5}{2}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

Step 3.8.2

Simplify the right side.

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Step 3.8.2.1

Simplify $- (\frac{5}{4}) + \frac{5}{2}$ .

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Step 3.8.2.1.1

To write $\frac{5}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$A = - \frac{5}{4} + \frac{5}{2} \cdot \frac{2}{2}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

Step 3.8.2.1.2

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.8.2.1.2.1

Multiply $\frac{5}{2}$ by $\frac{2}{2}$ .

$A = - \frac{5}{4} + \frac{5 \cdot 2}{2 \cdot 2}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

Step 3.8.2.1.2.2

Multiply $2$ by $2$ .

$A = - \frac{5}{4} + \frac{5 \cdot 2}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

$A = - \frac{5}{4} + \frac{5 \cdot 2}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

Step 3.8.2.1.3

Combine the numerators over the common denominator.

$A = \frac{- 5 + 5 \cdot 2}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

Step 3.8.2.1.4

Simplify the numerator.

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Step 3.8.2.1.4.1

Multiply $5$ by $2$ .

$A = \frac{- 5 + 10}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

Step 3.8.2.1.4.2

Add $- 5$ and $10$ .

$A = \frac{5}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

$A = \frac{5}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

$A = \frac{5}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

$A = \frac{5}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

$A = \frac{5}{4}$

$C = \frac{5}{4}$

$B = \frac{5}{8}$

$D = - \frac{5}{8}$

Step 3.9

List all of the solutions.

$A = \frac{5}{4}, C = \frac{5}{4}, B = \frac{5}{8}, D = - \frac{5}{8}$

Step 4

Replace each of the partial fraction coefficients in $\frac{A}{{(x - 2)}^{2}} + \frac{B}{x - 2} + \frac{C}{{(x + 2)}^{2}} + \frac{D}{x + 2}$ with the values found for $A$ , $B$ , $C$ , and $D$ .

$\frac{\frac{5}{4}}{{(x - 2)}^{2}} + \frac{\frac{5}{8}}{x - 2} + \frac{\frac{5}{4}}{{(x + 2)}^{2}} + \frac{- \frac{5}{8}}{x + 2}$