Precalculus Examples

$\frac{1}{4} (3 \ln (x + 2) - \ln (x + 4) - \ln (x^{2} + 2))$

Step 1

Simplify $3 \ln (x + 2)$ by moving $3$ inside the logarithm.

$\frac{1}{4} \cdot (\ln ({(x + 2)}^{3}) - \ln (x + 4) - \ln (x^{2} + 2))$

Step 2

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\frac{1}{4} \cdot (\ln (\frac{{(x + 2)}^{3}}{x + 4}) - \ln (x^{2} + 2))$

Step 3

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\frac{1}{4} \cdot \ln (\frac{\frac{{(x + 2)}^{3}}{x + 4}}{x^{2} + 2})$

Step 4

Multiply the numerator by the reciprocal of the denominator.

$\frac{1}{4} \cdot \ln (\frac{{(x + 2)}^{3}}{x + 4} \cdot \frac{1}{x^{2} + 2})$

Step 5

Multiply $\frac{{(x + 2)}^{3}}{x + 4}$ by $\frac{1}{x^{2} + 2}$ .

$\frac{1}{4} \cdot \ln (\frac{{(x + 2)}^{3}}{(x + 4) (x^{2} + 2)})$

Step 6

Simplify $\frac{1}{4} \ln (\frac{{(x + 2)}^{3}}{(x + 4) (x^{2} + 2)})$ by moving $\frac{1}{4}$ inside the logarithm.

$\ln ({(\frac{{(x + 2)}^{3}}{(x + 4) (x^{2} + 2)})}^{\frac{1}{4}})$

Step 7

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 7.1

Apply the product rule to $\frac{{(x + 2)}^{3}}{(x + 4) (x^{2} + 2)}$ .

$\ln (\frac{{({(x + 2)}^{3})}^{\frac{1}{4}}}{{((x + 4) (x^{2} + 2))}^{\frac{1}{4}}})$

Step 7.2

Apply the product rule to $(x + 4) (x^{2} + 2)$ .

$\ln (\frac{{({(x + 2)}^{3})}^{\frac{1}{4}}}{{(x + 4)}^{\frac{1}{4}} {(x^{2} + 2)}^{\frac{1}{4}}})$

Step 8

Multiply the exponents in ${({(x + 2)}^{3})}^{\frac{1}{4}}$ .

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Step 8.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\ln (\frac{{(x + 2)}^{3 (\frac{1}{4})}}{{(x + 4)}^{\frac{1}{4}} {(x^{2} + 2)}^{\frac{1}{4}}})$

Step 8.2

Combine $3$ and $\frac{1}{4}$ .

$\ln (\frac{{(x + 2)}^{\frac{3}{4}}}{{(x + 4)}^{\frac{1}{4}} {(x^{2} + 2)}^{\frac{1}{4}}})$