Precalculus Examples

$\sin (θ) = - \frac{\sqrt{2}}{2}$

Step 1

Add $\frac{\sqrt{2}}{2}$ to both sides of the equation.

$\sin (θ) + \frac{\sqrt{2}}{2} = 0$

Step 2

The degree cannot be determined because $\sin (θ) + \frac{\sqrt{2}}{2}$ is not a polynomial.

Not a polynomial