Precalculus Examples

$x^{2} + y^{2} + 12 x - 4 y + 12 = 0$

Step 1

Subtract $12$ from both sides of the equation.

$x^{2} + y^{2} + 12 x - 4 y = - 12$

Step 2

Complete the square for $x^{2} + 12 x$ .

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Step 2.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 12$

$c = 0$

Step 2.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 2.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 2.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{12}{2 \cdot 1}$

Step 2.3.2

Cancel the common factor of $12$ and $2$ .

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Step 2.3.2.1

Factor $2$ out of $12$ .

$d = \frac{2 \cdot 6}{2 \cdot 1}$

Step 2.3.2.2

Cancel the common factors.

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Step 2.3.2.2.1

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot 6}{2 (1)}$

Step 2.3.2.2.2

Cancel the common factor.

$d = \frac{2 \cdot 6}{2 \cdot 1}$

Step 2.3.2.2.3

Rewrite the expression.

$d = \frac{6}{1}$

Step 2.3.2.2.4

Divide $6$ by $1$ .

$d = 6$

Step 2.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 2.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{12^{2}}{4 \cdot 1}$

Step 2.4.2

Simplify the right side.

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Step 2.4.2.1

Simplify each term.

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Step 2.4.2.1.1

Raise $12$ to the power of $2$ .

$e = 0 - \frac{144}{4 \cdot 1}$

Step 2.4.2.1.2

Multiply $4$ by $1$ .

$e = 0 - \frac{144}{4}$

Step 2.4.2.1.3

Divide $144$ by $4$ .

$e = 0 - 1 \cdot 36$

Step 2.4.2.1.4

Multiply $- 1$ by $36$ .

$e = 0 - 36$

Step 2.4.2.2

Subtract $36$ from $0$ .

$e = - 36$

Step 2.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + 6)}^{2} - 36$ .

${(x + 6)}^{2} - 36$

Step 3

Substitute ${(x + 6)}^{2} - 36$ for $x^{2} + 12 x$ in the equation $x^{2} + y^{2} + 12 x - 4 y = - 12$ .

${(x + 6)}^{2} - 36 + y^{2} - 4 y = - 12$

Step 4

Move $- 36$ to the right side of the equation by adding $36$ to both sides.

${(x + 6)}^{2} + y^{2} - 4 y = - 12 + 36$

Step 5

Complete the square for $y^{2} - 4 y$ .

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Step 5.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - 4$

$c = 0$

Step 5.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 5.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 5.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 4}{2 \cdot 1}$

Step 5.3.2

Cancel the common factor of $- 4$ and $2$ .

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Step 5.3.2.1

Factor $2$ out of $- 4$ .

$d = \frac{2 \cdot - 2}{2 \cdot 1}$

Step 5.3.2.2

Cancel the common factors.

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Step 5.3.2.2.1

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot - 2}{2 (1)}$

Step 5.3.2.2.2

Cancel the common factor.

$d = \frac{2 \cdot - 2}{2 \cdot 1}$

Step 5.3.2.2.3

Rewrite the expression.

$d = \frac{- 2}{1}$

Step 5.3.2.2.4

Divide $- 2$ by $1$ .

$d = - 2$

Step 5.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 5.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{{(- 4)}^{2}}{4 \cdot 1}$

Step 5.4.2

Simplify the right side.

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Step 5.4.2.1

Simplify each term.

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Step 5.4.2.1.1

Cancel the common factor of ${(- 4)}^{2}$ and $4$ .

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Step 5.4.2.1.1.1

Rewrite $- 4$ as $- 1 (4)$ .

$e = 0 - \frac{{(- 1 (4))}^{2}}{4 \cdot 1}$

Step 5.4.2.1.1.2

Apply the product rule to $- 1 (4)$ .

$e = 0 - \frac{{(- 1)}^{2} \cdot 4^{2}}{4 \cdot 1}$

Step 5.4.2.1.1.3

Raise $- 1$ to the power of $2$ .

$e = 0 - \frac{1 \cdot 4^{2}}{4 \cdot 1}$

Step 5.4.2.1.1.4

Multiply $4^{2}$ by $1$ .

$e = 0 - \frac{4^{2}}{4 \cdot 1}$

Step 5.4.2.1.1.5

Factor $4$ out of $4^{2}$ .

$e = 0 - \frac{4 \cdot 4}{4 \cdot 1}$

Step 5.4.2.1.1.6

Cancel the common factors.

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Step 5.4.2.1.1.6.1

Factor $4$ out of $4 \cdot 1$ .

$e = 0 - \frac{4 \cdot 4}{4 (1)}$

Step 5.4.2.1.1.6.2

Cancel the common factor.

$e = 0 - \frac{4 \cdot 4}{4 \cdot 1}$

Step 5.4.2.1.1.6.3

Rewrite the expression.

$e = 0 - \frac{4}{1}$

Step 5.4.2.1.1.6.4

Divide $4$ by $1$ .

$e = 0 - 1 \cdot 4$

Step 5.4.2.1.2

Multiply $- 1$ by $4$ .

$e = 0 - 4$

Step 5.4.2.2

Subtract $4$ from $0$ .

$e = - 4$

Step 5.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(y - 2)}^{2} - 4$ .

${(y - 2)}^{2} - 4$

Step 6

Substitute ${(y - 2)}^{2} - 4$ for $y^{2} - 4 y$ in the equation $x^{2} + y^{2} + 12 x - 4 y = - 12$ .

${(x + 6)}^{2} + {(y - 2)}^{2} - 4 = - 12 + 36$

Step 7

Move $- 4$ to the right side of the equation by adding $4$ to both sides.

${(x + 6)}^{2} + {(y - 2)}^{2} = - 12 + 36 + 4$

Step 8

Simplify $- 12 + 36 + 4$ .

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Step 8.1

Add $- 12$ and $36$ .

${(x + 6)}^{2} + {(y - 2)}^{2} = 24 + 4$

Step 8.2

Add $24$ and $4$ .

${(x + 6)}^{2} + {(y - 2)}^{2} = 28$

Step 9

This is the form of a circle. Use this form to determine the center and radius of the circle.

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$

Step 10

Match the values in this circle to those of the standard form. The variable $r$ represents the radius of the circle, $h$ represents the x-offset from the origin, and $k$ represents the y-offset from origin.

$r = 2 \sqrt{7}$

$h = - 6$

$k = 2$

Step 11

The center of the circle is found at $(h, k)$ .

Center: $(- 6, 2)$

Step 12

These values represent the important values for graphing and analyzing a circle.

Center: $(- 6, 2)$

Radius: $2 \sqrt{7}$

Step 13