Precalculus Examples

$p (t) = 115 + 25 \sin (160 π t)$

Step 1

Rewrite the expression as $25 \sin (160 π t) + 115$ .

$25 \sin (160 π t) + 115$

Step 2

Use the form $a \sin (b t - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = 25$

$b = 160 π$

$c = 0$

$d = 115$

Step 3

Find the amplitude $| a |$ .

Amplitude: $25$

Step 4

Find the period using the formula $\frac{2 π}{| b |}$ .

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Step 4.1

Find the period of $25 \sin (160 π t)$ .

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Step 4.1.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 4.1.2

Replace $b$ with $160 π$ in the formula for period.

$\frac{2 π}{| 160 π |}$

Step 4.1.3

$160 π$ is approximately $502.65482457$ which is positive so remove the absolute value

$\frac{2 π}{160 π}$

Step 4.1.4

Cancel the common factor of $2$ and $160$ .

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Step 4.1.4.1

Factor $2$ out of $2 π$ .

$\frac{2 (π)}{160 π}$

Step 4.1.4.2

Cancel the common factors.

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Step 4.1.4.2.1

Factor $2$ out of $160 π$ .

$\frac{2 (π)}{2 (80 π)}$

Step 4.1.4.2.2

Cancel the common factor.

$\frac{2 π}{2 (80 π)}$

Step 4.1.4.2.3

Rewrite the expression.

$\frac{π}{80 π}$

Step 4.1.5

Cancel the common factor of $π$ .

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Step 4.1.5.1

Cancel the common factor.

$\frac{π}{80 π}$

Step 4.1.5.2

Rewrite the expression.

$\frac{1}{80}$

Step 4.2

Find the period of $115$ .

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Step 4.2.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 4.2.2

Replace $b$ with $160 π$ in the formula for period.

$\frac{2 π}{| 160 π |}$

Step 4.2.3

$160 π$ is approximately $502.65482457$ which is positive so remove the absolute value

$\frac{2 π}{160 π}$

Step 4.2.4

Cancel the common factor of $2$ and $160$ .

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Step 4.2.4.1

Factor $2$ out of $2 π$ .

$\frac{2 (π)}{160 π}$

Step 4.2.4.2

Cancel the common factors.

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Step 4.2.4.2.1

Factor $2$ out of $160 π$ .

$\frac{2 (π)}{2 (80 π)}$

Step 4.2.4.2.2

Cancel the common factor.

$\frac{2 π}{2 (80 π)}$

Step 4.2.4.2.3

Rewrite the expression.

$\frac{π}{80 π}$

Step 4.2.5

Cancel the common factor of $π$ .

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Step 4.2.5.1

Cancel the common factor.

$\frac{π}{80 π}$

Step 4.2.5.2

Rewrite the expression.

$\frac{1}{80}$

Step 4.3

The period of addition/subtraction of trig functions is the maximum of the individual periods.

$\frac{1}{80}$

Step 5

Find the phase shift using the formula $\frac{c}{b}$ .

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Step 5.1

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Step 5.2

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{0}{160 π}$

Step 5.3

Cancel the common factor of $0$ and $160$ .

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Step 5.3.1

Factor $160$ out of $0$ .

Phase Shift: $\frac{160 (0)}{160 π}$

Step 5.3.2

Cancel the common factors.

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Step 5.3.2.1

Factor $160$ out of $160 π$ .

Phase Shift: $\frac{160 (0)}{160 (π)}$

Step 5.3.2.2

Cancel the common factor.

Phase Shift: $\frac{160 \cdot 0}{160 π}$

Step 5.3.2.3

Rewrite the expression.

Phase Shift: $\frac{0}{π}$

Step 5.4

Divide $0$ by $π$ .

Phase Shift: $0$

Step 6

List the properties of the trigonometric function.

Amplitude: $25$

Period: $\frac{1}{80}$

Phase Shift: None

Vertical Shift: $115$

Step 7