Precalculus Examples

$\log (7.9) - \log (6.8)$

Step 1

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\log (\frac{7.9}{6.8})$

Step 2

Divide $7.9$ by $6.8$ .

$\log (1.1617647)$

Step 3

Log base $10$ of $1.1617647$ is approximately $0.06511817$ .

$0.06511817$