Precalculus Examples

$\log (40) + \log (250)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log (40 \cdot 250)$

Step 2

Multiply $40$ by $250$ .

$\log (10000)$

Step 3

Logarithm base $10$ of $10000$ is $4$ .

$4$