Precalculus Examples

$\ln (0.693 \cdot 1.1 \cdot \sqrt[5]{36})$

Step 1

Multiply $0.693$ by $1.1$ .

$\ln (0.7623 \cdot \sqrt[5]{36})$

Step 2

Multiply $0.7623$ by $\sqrt[5]{36}$ .

$\ln (1.56094075)$

Step 3

The result can be shown in multiple forms.

Exact Form:

$\ln (1.56094075)$

Decimal Form:

$0.44528868 \dots$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$