Precalculus Examples

$\ln (x - 4) (\ln (x y^{2}) + 3 \ln (x^{- 1})) + \ln (\frac{y^{6}}{x^{3}})$

Step 1

Simplify each term.

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Step 1.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\ln (x - 4) (\ln (x y^{2}) + 3 \ln (\frac{1}{x})) + \ln (\frac{y^{6}}{x^{3}})$

Step 1.2

Simplify $3 \ln (\frac{1}{x})$ by moving $3$ inside the logarithm.

$\ln (x - 4) (\ln (x y^{2}) + \ln ({(\frac{1}{x})}^{3})) + \ln (\frac{y^{6}}{x^{3}})$

Step 1.3

Apply the product rule to $\frac{1}{x}$ .

$\ln (x - 4) (\ln (x y^{2}) + \ln (\frac{1^{3}}{x^{3}})) + \ln (\frac{y^{6}}{x^{3}})$

Step 1.4

One to any power is one.

$\ln (x - 4) (\ln (x y^{2}) + \ln (\frac{1}{x^{3}})) + \ln (\frac{y^{6}}{x^{3}})$

Step 2

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\ln (x - 4) \ln (x y^{2} \frac{1}{x^{3}}) + \ln (\frac{y^{6}}{x^{3}})$

Step 3

Cancel the common factor of $x$ .

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Step 3.1

Factor $x$ out of $x y^{2}$ .

$\ln (x - 4) \ln (x (y^{2}) \frac{1}{x^{3}}) + \ln (\frac{y^{6}}{x^{3}})$

Step 3.2

Factor $x$ out of $x^{3}$ .

$\ln (x - 4) \ln (x (y^{2}) \frac{1}{x \cdot x^{2}}) + \ln (\frac{y^{6}}{x^{3}})$

Step 3.3

Cancel the common factor.

$\ln (x - 4) \ln (x y^{2} \frac{1}{x \cdot x^{2}}) + \ln (\frac{y^{6}}{x^{3}})$

Step 3.4

Rewrite the expression.

$\ln (x - 4) \ln (y^{2} \frac{1}{x^{2}}) + \ln (\frac{y^{6}}{x^{3}})$

Step 4

Combine $y^{2}$ and $\frac{1}{x^{2}}$ .

$\ln (x - 4) \ln (\frac{y^{2}}{x^{2}}) + \ln (\frac{y^{6}}{x^{3}})$